similar to: more dates and data frames

Dear R People: In the DASL library, there is a story about hot dogs. Here are the data: Beef 186 495 Beef 181 477 Beef 176 425 Beef 149 322 Beef 184 482 Beef 190 587 Beef 158 370 Beef 139 322 Beef 175 479 Beef 148 375 Beef 152 330 Beef 111 300 Beef 141 386 Beef 153 401 Beef 190 645 Beef 157 440 Beef 131 317 Beef 149 319 Beef 135 298 Beef 132 253 Meat 173 458 Meat 191 506 Meat 182 473 Meat 190

good evening all, i upgraded my last samba 2.2.7a (dog2) this afternoon and have run into problems. first, the setup: windows 2000 clients three sites on three seperate subnets connected by t1 through routers. each site has a samba server that authenticates the users on its subnet. the workgroup name for each server is dognet. /etc/passwd, /etc/group, and smbpasswd are synced up manually.

Dear R People: I am trying to split a character vector into a set of individual letters: Ideal: x3 <- c("dog") "d" "o" "g" I tried the following: > strsplit(x3) Error in strsplit(x3) : argument "split" is missing, with no default > strsplit(x3,1) [[1]] [1] "dog" I know that this is incredibly simple, but what am I doing

Dear R People: I'm still struggling with sending methods and classes as part of creating a new package. Where does the .onLoad function go? Within R itself or in a file in one of the new package directories? Here are my latest efforts: Here's the last part of the woof1-Ex.Rout > library('woof1') Error in loadNamespace(package, c(which.lib.loc, lib.loc), keep.source =

Dear R People: I have the following data frame: > str(dog.df) 'data.frame': 7 obs. of 2 variables: $ V1: Factor w/ 3 levels "1/1/2000","1/2/2000",..: 1 1 1 2 2 3 3 $ V2: Factor w/ 3 levels "cat","dog","tree": 2 1 3 1 3 2 3 > dog.df V1 V2 1 1/1/2000 dog 2 1/1/2000 cat 3 1/1/2000 tree 4 1/2/2000 cat 5 1/2/2000 tree 6

Hi R People: I have a question about setClass please. I'm working thru "R Programming for Bioinformatics". Actually, I was wondering if there is such a thing as an updateClass, in order to change a "contains" option, please? that is, if I had setClass("dog", representation(name="character",paws="numeric",tail="character")) Fair

Dear R People: I want to use the "grep" command in UNIX/Linux to check some words from the dictionary. Let's say I use: grep dog /usr/share/dict/words and I get back bulldog dog dogged and so on. How could I just get back "dog" with the grep command please? Thanks, Sincerely Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University

Dear R People: I have dates as factors in the following: > poudel.df$DATE [1] 1/2/2011 1/4/2011 1/4/2011 1/4/2011 1/6/2011 1/7/2011 1/8/2011 [8] 1/9/2011 1/10/2011 Levels: 1/10/2011 1/2/2011 1/4/2011 1/6/2011 1/7/2011 1/8/2011 1/9/2011 > I want them to be "regular" dates which can be sorted, etc. But when I did this: > as.character(poudel.df$DATE) [1]

Dear R People: I have a zoo object with its date index as a factor. > xAle1.zoo$index Error in xAle1.zoo$index : $ operator is invalid for atomic vectors > str(xAle1.zoo) Class 'zoo' atomic [1:32] 1253 1316 1038 1157 1710 1489 1159 1142 945 1245 ... ..- attr(*, "index")= Factor w/ 32 levels "04/16/09","04/17/09",..: 1 2 3 4 5 6 7 8 9 10 ... >

Hello again: Here is a solution to the dates without leading zeros: pou1 <- function(x) { #Note: x is a data frame #Assume that Column 1 has the date #Column 2 has station #Column 3 has min #Column 4 has max library(stringr) w <- character(length=nrow(x)) z <- str_split(x[,1],"/") for(i in 1:nrow(x)) { u <-

Dear R People: I have a data frame with the two following date columns: > a.df[1:10,c(1,6)] DATE DEATH 1207 2009-04-16 2009-05-06 1514 2009-04-16 2009-05-06 2548 2009-04-16 2009-05-08 3430 2009-04-16 2009-05-09 3851 2009-04-16 2009-05-09 3945 2009-04-16 2009-05-09 7274 2009-04-16 2009-05-12 7532 2009-04-16 2009-05-12 7651 2009-04-16 2009-05-12 8495 2009-04-16 2009-05-13 >

Dear R People: I have a data frame, xm1, which has 12 rows and 4 columns. If I put is xm1[,-4], I get all rows, and columns 1 - 3, which is as it should be. Now, is there a way to use the names of the columns to omit them, please? Thanks so much in advance! Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown

Hi again. I'm putting together a little project with R, python, and a website. So I have an HTML file, a py file, an R file. Here is the HTML file: <form action="/cgi-bin/radio4.py" method="post" target="_blank"> <input type="radio" name="subject" value="Integrate" /> Integrate <input type="radio"

Everything is ok on Firefox, IE, and iPad. Thanks, Erin On Tue, Jan 8, 2013 at 7:58 PM, Erin Hodgess <erinm.hodgess at gmail.com> wrote: > Dear R People: > > Has anyone used R2HTML in web files that were on the Blackboard LMS, please? > > I'm starting to do these but wanted to know if there were any > potential pitfalls. > > Thanks, > Erin > > > --

Dear R People: Here is a goofy question: I want to extract the zip code from an address and here is my work so far: > add1 results.formatted_address "200 W Rosamond St, Houston, TX 77076, USA" > add1[1][32:36] <NA> <NA> <NA> <NA> <NA> NA NA NA NA NA > str(add1) Named chr "200 W Rosamond St, Houston, TX 77076,

Dear R People: Here is a toy example: > x <- c("2E","5W","12H") > substr(x,2,2) [1] "E" "W" "2" > Sometimes x has 3 elements, sometimes 2. I want to extract the last element, and then extract the other 1 or 2 elements. How can I do this, please? TIA, Sincerely, Erin -- Erin Hodgess Associate Professor Department of

Hello I would like to build R from source and use the PGI compiler, rather than the GCC compiler. I saw the instructions for the Intel compiler in the R Installation Manual, but I didn't see the PGI. I tried a few times without instructions, but without success. Any suggestions would be most welcome. Also, I hope this is the right group for the question. Sincerely, Erin -- Erin

Dear R People: I have generated the following table: > table(zza$DEATH,zza$GENDER) F M 2009-04-21 0 1 2009-04-22 4 2 2009-04-24 6 0 2009-04-25 1 3 2009-04-26 2 0 2009-04-28 3 0 2009-04-29 2 2 However, instead of total counts in the F and M columns, I would like percents. How would I do this, please? thanks, Erin -- Erin

Dear R People: When I want to produce a small sample confidence interval using t.test, I get the following: > t.test(buzz$var1, conf.level=.98)$conf.int [1] 2.239337 4.260663 attr(,"conf.level") [1] 0.98 How do I keep the attr statement from printing, please? I'm sure it's something really simple. Thanks, Sincerely, Erin -- Erin Hodgess Associate Professor Department

Dear R People: Here is something that I am sure is very simple. I'm just trying to re-create the C convolution example in the Extensions manual. Here is the subroutine: void convolve(double *a, int *na, double *b, int *nb, double *ab) { R_len_t i, j, nab = *na + *nb - 1; for(i = 0; i < nab; i++) ab[i] = 0.0; for(i = 0; i < *na; i++) for(j = 0; j < *nb; j++) ab[i + j] += a[i] *