similar to: reformat time from hhmm

Hello, I am having trouble with the conversion specifications as described in the strptime help page. > head(dat) Date Time Open High Low Close Up Down Volume 1 11/19/2012 935 137.89 138.06 137.82 138.05 3202541 3013215 0 2 11/19/2012 940 138.04 138.40 138.02 138.38 2549660 2107595 4657255 3 11/19/2012 945 138.38 138.40 138.18 138.19 1627379 1856318 3483697 4

Hi, I have a dataframe Wash2005, which has daily weather data. I am doing a regression by month as follows: # FM10 Regression by Month # Plot 12 Month of OFM10, FFM10 for(i in 1:12) { Temp <- subset (Wash2005, MM == i) assign( paste('Wash2005FM10', strtrim(month.name[i],3), sep=""),lm(Temp$FM10.1 ~ Temp$FM10)) } Wash2005FM10Jan, Wash2005FM10Feb, etc holds the

hi ,I am writing a soft package based on R. But when I try to read a configure file showed as below. How can I read the parameter in this text file. How can I read the parameter into each variable in this file ? configinfo<-scan(file(configfile),ok=TRUE,n=-1) scan seems need every line have same column ? configinfo <- readLines(configfile,ok=TRUE,n=-1) methodnum <-

Hola a tod@s, Me han mandado una base de datos y al abrirla me he encontrado con la fecha y la hora en el siguiente formato: FECHA HORA 20121007 1206 20110622 1854 20110623 054 He conseguido que la Fecha me quedara en el formato dd/mm/aaaa mediante el script db[, "FECHA"] <- as.Date(as.character(db[,

I feel like an idiot posting this because every language I've ever seen has a string function that trims blanks off strings (off the front or back or both). Ideally, it would process whole data frames/matrices etc but I don't even see one that processes a single string. But I've searched and I don't even see that. There's a strtrim function but it does something completely

Hello R Community, I've been run the following codes. However, I've been getting an unusual segfault that I'm unable to trace its origin. Please give me a light to decipher the "caught segfault" Thanks for you attention. Bernardo. > options(STERM='iESS', editor='emacsclient') > rm(list = ls()) > > source("fgenIGLD.R") #RNG

Hola de nuevo, acabo de encontrar la solución. He creado una variable ficticia con los días 1 de cada mes en la secuencia temporal que quería y después he actuado de la siguiente manera attach(Libro1) plot (xbar~as.Date(fecha,"%d/%m/%y"), type="b", pch=19,cex=2,xaxt="n") xlabels<-strptime(ofeje, format = "%d/%m/%y") axis.Date(1,

Date-Time-Stamp input method to correctly interpret user-specific formats:coding is 90% there - based on exmple at http://tolstoy.newcastle.edu.au/R/help/05/02/12003.html ...anyone got the last 10% please? CONTEXT: Data is received where one of the columns is a datetimestamp. At midnight, the value represented as text in this column consists of just the date part, e.g.

Help-Rs,   I'm doing some string manipulation in a file where I converted a string date in mm/dd/yyyy format and returned the date yyyy.   I've used regexpr (hat tip to Gabor G for a very nice earlier post on this function) in steps (I've un-nested the code and provided it and an example of what I did below.  My question is: is there a more efficient way to do this.  Specifically is

I have a numerical vector which contains a (poorly) formatted time column, which, in theory, should be HHMM, but was distributed as an integer, so, for 12:15 am, it is saved as "15" (e.g. HHMM = 0015 with the zeroes stripped). I'm trying to use this in conjunction with strptime, but I'm thinking because each time is an integer ranging from 1 to 4 digits, I probably need to

Hola lista, tengo una base de datos muy grande de un datalogger. Consiste en un vector con 0's y 1's, y tengo que ver cuando hay 600 o más unos seguidos. Se me ocurrió hacerlo con un loop for. Pero tarda demasiado. También intente usar which para que seleccione solo los 1 para empezar a sumar pero no hay gran diferencia. A alguien se le ocurre alguna solución para hacerlo más rápido? Acá

I am having a problem with a gantt chart since moving to R2.4.0. from 2.3.1 I made some adaptations to the code from http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=74 and successful produced a simple gantt chart. However when I upgraded to 2.4.0 it no longer works as desired. See http://ca.geocities.com/jrkrideau/R/gantproblem.pdf for the two charts. The charts were produced

Dear R user, I am running R under Windows 2000. I am looking for a routine for importing - shape files (ESRI) into R - dbase files (FOXPRO) into R and I am looking for time-space models for description and prediction of Bernoulli-, Binomial- and Poissonvaraibles. Thank's a lot for a reply. Sincerely yours, Ekkehardt Altpeter Swiss Federal Office of Public

hi everyone . Here I have a text where there are some integer and string variables.But I can not read them by readLines and scan the text is : weight ;30;130 food:2;1;12 color:white;black the first column is the names of the variables and others are the value of them. the column in different line are different. Can anyone help me ? -- TANG Jie Email: totangjie@gmail.com Tel: 0086-2154896104

This is definitely obscure but we had a unit test that called .Internal(strptime, "1942/01/01", %Y/%m/%d") with timezone (TZ) set to CET. In R-3.1.3 that returned "1942-01-01 CEST" which, paradoxically, is correct as they evidently did strange things in Germany during the war period. Java also returns the same. However, R-3.2.4 returns "1942-01-01 CET".

On 3/12/16 12:33 AM, peter dalgaard wrote: >> On 12 Mar 2016, at 00:05 , Mick Jordan <mick.jordan at oracle.com> wrote: >> >> This is definitely obscure but we had a unit test that called .Internal(strptime, "1942/01/01", %Y/%m/%d") with timezone (TZ) set to CET. > Umm, that doesn't even parse. And fixing the typo, it doesn't run: > >>

>>>>> Richard O'Keefe >>>>> on Mon, 6 Nov 2023 18:37:34 +1300 writes: > Thanks to all who replied. On Mon, 6 Nov 2023 at 18:37, > Richard O'Keefe <raoknz at gmail.com> wrote: >> OK, so the consensus is (1) One cannot make strptime >> accept ISO8601-compliant zone designators (2) The >> lubridate package

>>>>> peter dalgaard <pdalgd at gmail.com> >>>>> on Sat, 12 Mar 2016 19:11:40 +0100 writes: > OK, .Internal is not necessary to reproduce oddity in this area. I also see things like (notice 1980) >> strptime(paste0(sample(1900:1999,80,replace=TRUE),"/01/01"), "%Y/%m/%d", tz="CET") ............... >

Today I built R from source on a 32-bit Ubuntu 10.04.3 LTS box, and saw that the "make check" tests/reg-tests-1b.R failed. From the output at the end of my "tests/reg-tests-1b.Rout.fail" file, the problem is appearing in the "identical(z, x %*% t(y))" test code below. I then tried the stock R provided by the Ubuntu r-base-core binary package, and to my surprise, it

Dear R Helpers, I am having difficulty with strptime. I wish to find the differences between two vectors of times. I have apparently no difficulty to convert the vectors to the appropriate format using strptime. But, then difftime does not calculate all the differences. Here is the code and output:- dob=strptime(as.character(datx$BDT),'%d-%b-%y'); dob$year=dob$year-100