similar to: building time series/zoo/its from a data frame

Dear R People: I have the following data set with the columns DATE, GENDER, and Co. Co has 8 possible options. > a.df[1:10,] DATE GENDER Co 1 2009-04-16 F Rash 2 2009-04-16 F Other 3 2009-04-16 M Botulinic 4 2009-04-16 M Other 5 2009-04-16 M Constitutional 6 2009-04-16 F Other 7 2009-04-16

Dear R People: I have two data frames, a.df and b.df as seen here: > a.df[1:10,] DATE GENDER PATIENT_ID AGE SYNDROME 1 4/16/2009 F 23686 45 RASH ON BODY 2 4/16/2009 F 13840 35 CANT URINATE 3 4/16/2009 M 12895 30 BLURRED VISION 4 4/16/2009 M 18375 33 UNABLE TO VOID 5 4/16/2009 M 2237 44

Hello, I'm new using R and developing tables. I have a problem in developing a table. In a questionaire I made I ask this question "Please tell me the first three sympthoms caused by Respiratory tract infection you've caught this year", then the people answer three sympthoms, the first mention (Top of mind) is saved in a variable called "P2_A", the second mention in

Dear R People: The aggregate function works very well on regular time series. Is there a version for zoo or its that would take daily data and convert it to monthly, please? Thanks in advance, Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com

Dear R People: I have a zoo object with its date index as a factor. > xAle1.zoo$index Error in xAle1.zoo$index : $ operator is invalid for atomic vectors > str(xAle1.zoo) Class 'zoo' atomic [1:32] 1253 1316 1038 1157 1710 1489 1159 1142 945 1245 ... ..- attr(*, "index")= Factor w/ 32 levels "04/16/09","04/17/09",..: 1 2 3 4 5 6 7 8 9 10 ... >

Dear R users - I have a list of patient identifiers and diagnoses from inpatient admissions. I would like to reorganize the list, presently in a long format to a wide format in reshape, but in the absence of a "time" element, I am uncertain how to do this - any help greatly appreciated. ID Dx A nausea A diabetes A kidney failure A heart attack A fever B fever B

Dear R People: I have the following code that I use to convert a monthly zoo object to a data.frame, and it works perfectly: library(tseries) z <- get.hist.quote(instrument=inst1, start=start1,end=end1, quote=quot1,comp = "m") y <- as.ts(aggregate(z, as.yearmon, tail, 1)) y.df <- data.frame(y=y,time=time(y)) y.df$x <- ts(y.df[,1]) tsp(y.df$x) <-

Dear R Community: I am working on a public health early warning system, and I see that the qcc package allows for CUSUM and other statistical quality tests but I am not sure if my project is a good match for qcc functions as written. Any advice you may have is very much appreciated. I have four years worth of daily counts of emergency room admissions for different conditions (e.g. respiratory,

Dear R People: I'm trying to convert a daily zoo object to a weekly zoo object: xdate <- seq(as.Date("2002-01-01"),as.Date("2010-07-10"),by="day") library(zoo) length(xdate) xt <- zoo(rnorm(3113),order=xdate) xdat2 <- seq(index(xt)[1],index(xt)[3113],by="week") xt.w <- aggregate(xt,by=xdat2,mean) Error: length(time(x)) ==

Dear R People: I would like to combine a zoo object with some observations at the end. Here is the set up: > xgh 2010-06-15 2010-06-16 2010-06-17 2010-06-18 2010-06-19 2010-06-20 2010-06-21 5 6 1 5 0 0 13 2010-06-22 2010-06-23 2010-06-24 2010-06-25 2010-06-26 2010-06-27 2010-06-28 9 6 4 6

Estimado José Betancourt Dos sugerencias: Debes responder a toda la lista, no solo a quien envía un correo. Es un conjunto de datos y esas son probabilidades. Entiendo que puedes utilizar el método de cálculo que le resulte adecuado. Flu2009 {EpiEstim} R Documentation Data on the 2009 H1N1 influenza pandemic in a school in Pennsylvania Description This data set gives 1/ the daily

Dear R People: I have the following data frame: > str(dog.df) 'data.frame': 7 obs. of 2 variables: $ V1: Factor w/ 3 levels "1/1/2000","1/2/2000",..: 1 1 1 2 2 3 3 $ V2: Factor w/ 3 levels "cat","dog","tree": 2 1 3 1 3 2 3 > dog.df V1 V2 1 1/1/2000 dog 2 1/1/2000 cat 3 1/1/2000 tree 4 1/2/2000 cat 5 1/2/2000 tree 6

I am working on a simple pilot project comparing the capability of SQL, SAS and R to perform a rolling mean per the following instructions. I have completed the SQL and SAS analysis, so now it's R's turn. Calculate mean values of x (x=count) for each date in the dataset where mean = the average count of days [t-9] through day [t-3] for each date/illness combination. Dataset aggpilot

Dear listers, Let use say that I want to display the Pixel dataset (in the NLME library) xyplot(pixel~day|Dog, groups=Side, data=Pixel, panel=panel.superpose, panel.groups=panel.xyplot, type="b", pch=16) (I know, there are better examples, ...) Now, how could I change the colours of the symbols accordingly to another factor changing within subject and side form time to time? (let us

Dear R People: I have a data frame, xm1, which has 12 rows and 4 columns. If I put is xm1[,-4], I get all rows, and columns 1 - 3, which is as it should be. Now, is there a way to use the names of the columns to omit them, please? Thanks so much in advance! Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown

Hi again. I'm putting together a little project with R, python, and a website. So I have an HTML file, a py file, an R file. Here is the HTML file: <form action="/cgi-bin/radio4.py" method="post" target="_blank"> <input type="radio" name="subject" value="Integrate" /> Integrate <input type="radio"

Everything is ok on Firefox, IE, and iPad. Thanks, Erin On Tue, Jan 8, 2013 at 7:58 PM, Erin Hodgess <erinm.hodgess at gmail.com> wrote: > Dear R People: > > Has anyone used R2HTML in web files that were on the Blackboard LMS, please? > > I'm starting to do these but wanted to know if there were any > potential pitfalls. > > Thanks, > Erin > > > --

Dear R People: Here is a goofy question: I want to extract the zip code from an address and here is my work so far: > add1 results.formatted_address "200 W Rosamond St, Houston, TX 77076, USA" > add1[1][32:36] <NA> <NA> <NA> <NA> <NA> NA NA NA NA NA > str(add1) Named chr "200 W Rosamond St, Houston, TX 77076,

Dear R People: Here is a toy example: > x <- c("2E","5W","12H") > substr(x,2,2) [1] "E" "W" "2" > Sometimes x has 3 elements, sometimes 2. I want to extract the last element, and then extract the other 1 or 2 elements. How can I do this, please? TIA, Sincerely, Erin -- Erin Hodgess Associate Professor Department of

Dear R People: I have generated the following table: > table(zza$DEATH,zza$GENDER) F M 2009-04-21 0 1 2009-04-22 4 2 2009-04-24 6 0 2009-04-25 1 3 2009-04-26 2 0 2009-04-28 3 0 2009-04-29 2 2 However, instead of total counts in the F and M columns, I would like percents. How would I do this, please? thanks, Erin -- Erin