similar to: regexpr help (match.length=0)

Each of the following calls crash ("core dumps") R (R --vanilla) on various versions and OSes: regexpr("a{2-}", "") sub("a{2-}", "") gsub("a{2-}", "") EXAMPLES: > sessionInfo() R version 2.11.1 Patched (2010-09-16 r52949) Platform: i386-pc-mingw32 (32-bit) ... > regexpr("a{2-}", "") Assertion

Each of the following calls crash ("core dumps") R (R --vanilla) on various versions and OSes: regexpr("a{2-}", "") sub("a{2-}", "") gsub("a{2-}", "") EXAMPLES: > sessionInfo() R version 2.11.1 Patched (2010-09-16 r52949) Platform: i386-pc-mingw32 (32-bit) ... > regexpr("a{2-}", "") Assertion

Dear R Helpers, I am running R 2.6.2 on a Windows XP machine. I am trying to use regexpr to locate full stops in strings, but, without success. Here an example:- f="a,b.c at d:" #define an arbitrary test string regexpr(',',f) #find the occurrences of ',' in f - should be one at location 2 # and this is what regexpr finds #[1] 2

Given a text like I want to be able to extract a matched regular expression from a piece of text. this apparently works, but is pretty ugly # some html test<-"</tr><tr><th>88958</th><th>Abcdsef</th><th>67.8S</th><th>68.9\nW</th><th>26m</th>" # a pattern to extract 5 digits > pattern<-"[0-9]{5}" #

Help-Rs,   I'm doing some string manipulation in a file where I converted a string date in mm/dd/yyyy format and returned the date yyyy.   I've used regexpr (hat tip to Gabor G for a very nice earlier post on this function) in steps (I've un-nested the code and provided it and an example of what I did below.  My question is: is there a more efficient way to do this.  Specifically is

Hi, I'm trying to parse lines of the form: dan001.hin (0): fingerprint={256, 411, 426, 947, 973, 976} What I need is the sequence of number between {}. I'm using grep as match <- grep("{([0-9,\s]*)}",s,perl=T,value=T) where s is a character vector. But all I get is the whole string s. I tried using regexpr in an attempt to get just the sequence I wanted: match <-

Hi, I 'd like to match each member of a list to a target string, e.g. ------------------------------ mylist=c("MN","NY","FL") g=regexpr(mylist[1], "Those from MN:") if (g>0) { "On list" } ------------------------------ My question is: How to add an end-of-string symbol '$' to the to-match string? so that 'M' won't

Dear all-- I am still forging my first arms with R and I am fighting with regexpr() as well as portability between unix and windoz. I need to extract barcodes from filenames (which are located between a double and single underscore) as well as the directory where the filename is residing. Here is the solution I came to: aFileName <-

Hello, I have build a syntax to find out if a given substring is included in a larger string that works like this: d1$V1[regexpr("some text = 9",d1$V2)>0] <- 9 and this works all right till "some text" contains standard ASCII set. However, it does not work when accents are included as the following: d1$V1[regexpr("some t?xt = 9",d1$V2)>0] <- 9 I have

I'm trying to use the regexpr function to locate the decimal in a character string. Regardless of the position of the decimal, the function returns 1. For example, > regexpr(".", "Female.Alabama") [1] 1 attr(,"match.length") [1] 1 In trying to figure out what was going on here, I tried the below command: > gsub(".", ",",

Dear all I encountered strange problem with regexpr replacement I made this character object str <- "02.06.10 12:40 " > str(str) chr "02.06.10 12:40 " I read in an object which seems to be quite similar > str(as.character(becva$V1)[1]) chr "02.06.10 12:40 " However I can not remove trailing spaces from it > sub(' +$',

Dear R users, I have the following two problems, related to the function sub, grep, regexpr and similia. The header of the file(s) I have to import is like this. c("y (m)", "BD (g/cm3)", "PR (Mpa)", "Ks (m/s)", "SP g./g.", "P (m3/m3)", "theta1 (g/g)", "theta2 (g/g)", "AWC (g/g)") To get rid of spaces and

Greetings R list, I am stuck on a simple syntax problem. I want to list all files in a directory, excluding files of a certain type. I have tried pattern matching as follows: a <- list.files(data, full.name = TRUE, pattern != ".xml") # exclude all .xml files The warning returns that my syntax is incorrect. I have read the regexpr help files and search old posts to no

Hi! I want to index html files, but w/o the tags, so I was thinking either I remove them before I index it (expensive), or put up an RegExpAnalyzer. BTW, when using an analyzer, does that mean that everything which it declines (i.e. the RegExpAnalyzer doesn''t match) won''t be put into the index files (i.e. blows it up)? I came up with a simple test, which didn''t

I finally got around to upgrading from 0.8.2 (!!). I had a spec which looked like specify "should render abc123" do controller.should_render :text => "abc123" get :key end With 1.0.0, the new spec is it "should render abc123" do get :key response.should render_text("abc123") end However it doesn''t work, giving me the error: undefined

Hi, I need to setup a load of user accounts on a series of machines, for testing purposes. I'm using a script to do this, but the only problem I have so far: I have to activate them all manually by doing passwd user1, passwd user2, passwd user3, etcetera. The useradd man page mentions a -p option to define a password, but I can't seem to get this to work. Here's what I'd like

We have a new customer with a lot of old phones like the 9133i. They won't register, and we see some very strange behavior with them. If the SIP peer exists, they simply fail silently, with no error in the CLI or the messages log. Nothing works, but no errors. If the peer does not exist, it's clear that it's registering improperly: [2013-04-28 13:34:31] NOTICE[3058] chan_sip.c:

I''m writing an acts_as_* plugin and am trying to BDD it. Ideally my specs would look like: describe ActsAsCloneable, " basic cloning" do load_example_classes School.class_eval do acts_as_cloneable end before(:each) do @old_school = School.create! :name => "Baylake Pines", :city => "Virginia Beach", :guid => "abc123"

Hi, Here's my problem... I have a data frame with three columns containing strings. The first columns is a simple character. I want to get the index of that character in the second column and use it to extract the item from the third column. I can do this using a scalar method. But I'm not finding a vector method. An example is below. col1 col2 col3 'L'

Hi, i'm running CentOS 6.0 on my server and installed mrtg from the rpm-package mrtg-2.16.2 . I also installed the depending packages perl-IO-Socket-INET6 perl-Socket6 .... mrtg works fine with IPV4-Addresses. When i specify a Target by IPV6-Address (or hostname resolving to a V6-address) mrtg fails. Here i have a small sample-config for V4 which is working: LogDir: /tmp ThreshDir: /tmp