similar to: Kernel density estimate plot for 3-dimensional data

It is known that function bkde2D (package "KernSmooth") returns a matrix of density estimates over the mesh induced by x1 and x2. In Details it is written that "... heights of the kernel, scaled by the bandwidths, at each datapoint are summed. This sum, after a normalization, is the corresponding fhat value in the output". There are several questions: 1) How to calculate

I'm trying to make a set of contour plots of bivariate kernel density estimates, showing three such plots overlaid, similar to this plot http://euclid.psych.yorku.ca/SCS/Private/Test/ridge-boot2.pdf except that I would like to have the contours *filled* (using transparent colors). To make this reproducible, I've saved the results of KernSmooth::bkde2D() in the following file:

Dear R community, I'm having hard time to understand the kde function in "ks" package. Let me use a 3-dimensional kernel smooth example to explain my question using the elevation data in geoR. ### here is what I did ### library(ks) require(geoR) data(elevation) elev.df <- data.frame(x = elevation$coords[,"x"], y = elevation$coords[,"y"], z = elevation$data)

Hello there, I am presently using the locfit package in "R" and would appreciate some help here. Could anyone tell me tell me how I can obtain the various components (x and y values)of the density estimation after using the "R" command "locfit"? For example, with the command "fhat<-density(somename)" I can obtain the x and y values by simply calling

Hello!! At first thank you all for your suggestions and your help. But I would like to get another group of datas from the density estimation. I don't know if these information are provided by locfit or I should use an other function like plot(). Description: Each number between 1 and 100 (only integer) for example should have only one density value. But I also would like to have the density

Unsubscribe -----Original Message----- From: r-help-request at r-project.org Date: Wed, 05 May 2010 12:00:09 To: <r-help at r-project.org> Subject: R-help Digest, Vol 87, Issue 5 Send R-help mailing list submissions to r-help at r-project.org To subscribe or unsubscribe via the World Wide Web, visit https://stat.ethz.ch/mailman/listinfo/r-help or, via email, send a message with subject

Hi I hope this is going to the right place. I am trying to write a program which uses KernSmooth library to estimate mutual information between two time series at various different lags. At the moment it’s producing negative values, which is supposed to be impossible (something is fishy). I am summing across one row of the matrix to get p(value is in bin x) and summing across the columns to get

Need Help in Debugging below script:-------------------------------- dat <- get_majorlandmarks(dat,Dmin,Per) fit_xts <- xts(dat$fit,order.by = dat$Date,frequency = 365) close_xts <- xts(dat$Close, order.by = dat$Date, frequency = 365 ) majorlandmarks_xts <-xts(dat$Close[dat$majorlandmarks==TRUE], order.by = dat$Date[dat$majorlandmarks==TRUE], frequency = 365 ) minorlandmarks_xts

Dear all I want to display 4 dimensional space by some suitable way. I searched CRAN and found miscellaneous 3 dim graphics packages which I maybe can modify but anyway I am open to any hint how to efficiently display data like: longitude, latitude, height, value Thank you Petr Pikal petr.pikal at precheza.cz

Hi, I'm using the densCols function for a scatterplot and cannot figure out 1) how to extract the computed densities, and 2) how to create a legend based that represents the upper and lower ranges of the densities. For example: movers.den <- densCols(move$x, move$y) table(movers.den) #08306B #083775 #083B7C #083D7E #3989C1 #3F8FC4 28 22 101 25

Hi! I'm trying to implement in R in an easy way the negative reflection method described in Silverman (1986) on p.31, ie I have a non-negative dataset and would like to estimate the density by applying a reflection method where the reflected points have weight -1. I thought there should be a way to evaluate the wanted kernel at the required points, in other words to calculate formula (2.16):

I am trying to estimate home range size using the plug-in method with kernel density estimation in the kernel smoothing (ks) package. Unless there is another way I am not familiar with, in order to calculate spatial area under the space I need to convert my kde () object into a spatial object somehow in order to calculate its spatial area. Could someone demonstrate how this might be done? --

I have 2 linux boxes connected to a switch: box1: eth0 192.168.0.200/255.255.255.0 eth1 public address from ISP dhcp box2: eth0 192.168.0.35/255.255.255.0 box3: eth0 192.168.1.3/255.255.255.0 I want box1 to act as a gateway to the internet (it is doing this now for box2), but also want to communicate from box2 to box3 through box1, and that box3 can use the internet through box1. how can I do

At 19:28 29/06/00 +1000, you wrote: >a customer asked me about the difference between using Samba and NFS. AFAIK The answers are roughly the following: The difference between Samba and NFS is primarily that Samba uses the SMB (aka Lanmanager) protocol which is considered "standard" for PCs (Windows and OS/2 both have built in support for it, a free client is also available for

If I have a contourplot (in the lattice package) and I want to add straight lines to it, how do I do this? I see that there are llines() and lsegement() functions for lattice plots, but they don't seem to do anything in this case: library(lattice) library(KernSmooth) x=rnorm(10000) y=x+rnorm(x,0,.5) a=bkde2D(cbind(x,y),.7) z=as.vector(a$fhat) grid=expand.grid(x=a$x1,y=a$x2) grid$z=z

Como usas la función image puedes consultar la ayuda ?image o help(image) y encontrarás el siguiente ejemplo donde se usa un diferente color Palette (mencionada por pepeceb en su respuesta). x <- 10*(1:nrow(volcano)) y <- 10*(1:ncol(volcano)) image(x, y, volcano, col = terrain.colors(100), axes = FALSE) # O puedes usar directamente el número para indicar el color image(x, y, volcano, col =

I'm a bit confused how scp works... could someone please explain the local/remote external calls that happen when scp is started... in particular how it relates to ssh on the remote site? To be more specific... I use Kerberos for authentication and I've been working on an ssh wrapper script that checks my Kerberos credentials before running the ssh command. If the credentials are

Hi, I am having an issue when creating a postscript file from RGL window. It seems to cut off some of the axis labels. Here is the code I am using. I created a 3D plot using RGL_0.71 with R 2.5 on Windows XP. z1<-c(5,4,1,4.5,2,3,2,1,1) z2<-c(6,8,7,7.5,5,3.5,4,1,1) z3<-c(3,2,4,7,3,4.5,6,2,3) x1<-seq(1,9) x2<-seq(1,9) x3<-seq(10,18) y1<-seq(8,0) y2<--1*y1

Hal Finkel <hfinkel at anl.gov> wrote on 16.03.2015 17:56:20: > If you want to do it at a clang level, the right thing to do is to > fixup the ABI lowerings for pointers to keep them pointers in this case. > So this is an artifact of the way that we pass structures, and > constructing a general solution at the ABI level might be tricky. > I've cc'd Uli, who did most

Dear expeRts, I am a new user of rgl, below is my first trial to plot a simple function in 3d. I managed to put the axes in the right locations, but: (1) The xlab, ylab, and zlab arguments are ignored; how can I put in axes labels? (2) Since I removed the axes in persp3d() the viewport is too small; is it possible to keep the size of the viewport? (3) The box is not correctly drawn, there