similar to: Retrieve regular expression groups

Is there anything like cumsum and cumprod but which allows you to apply an arbitrary function instead of sum and product? In other words, I want a function cumfunc(x, f) that returns a vector, so that for all n up to the length of x cumapply(x,f)[n] = f(x[1:n]) This would give cumsum and cumprod as special cases when f=sum or f=prod. I could write such a function, but I can't see

I've been using Tinn-R with RGui on Windows for quite some time now, but it's very irritating how the Windows RGui allows only very rudimentary line-editing. I can't even use shift-arrow key to select text! I searched through the archives and found what seemed to be a few people asking about this, but I couldn't find a clear answer. I saw some references in the docs to

I've been using the ave function to compute some statistics on a data frame. After a while I noticed that, for some reason, it was returning numerical statistics as strings instead of numbers. I delved into the code of the functions and traced the problem to the following fact: ave uses split<- to do its work. Specifically, it does "split(x, g) <- lapply(split(x, g),

Full_Name: Brendan Barnwell Version: 2.9.0 OS: Windows XP Pro Submission from: (NULL) (71.102.131.29) The ave() function returns an incorrect datatype. Specifically, ave(x, g, f) always returns a vector with the same mode as x, rather than using the mode of the vector returned by f. Observe: > x [1] "A" "B" "C" "A" "B" "C"

Actually it worked, but only after I defaulted all the settings on the phone and let it pick the config up fresh. Anyone know if there is any headset config options to default to headset/speaker? Thanks Lee -----Original Message----- From: asterisk-users-bounces@lists.digium.com [mailto:asterisk-users-bounces@lists.digium.com] On Behalf Of Lee Archer Sent: 03 January 2006 14:49 To:

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hey all, First of all, hello again! Been a while since I've posted to the list, but I've been here lurking and watching ;-) Anyway, I wanted to pose a general question to the list to see if it turns up new suggestions for everyone/me. What is your preferred editor when coding in the dialplan? This is mainly aimed at those of you who write

Hi, i need to recognize itemization structures in strings which follow the format: "digit-digit-dot" like e.g. 1. 2. 19. 211. Given the string " This happened in the 21. century." (the dot behind 21 is used in German instead of 21st) I want know where the dots are but I do not want the 21.-dot to be returned as well. I am not good at regular expressions. How

hello friends, You are right, changed the user to root, and icmpping and icmppingsec are working now!!! Thank you!!!! On 10/26/05, Fortin, Benoit <benoit.fortin@cgi.com> wrote: > > > Hi, > > The setuid of fping was already set, as you can see : > > zabbix@wirelessKTM:~/fping-2.4b2_to$ ls -l fping > -rwsr-xr-x 1 zabbix zabbix 69258 2005-10-26 17:59 fping >

How can I make it more readable? Name/username 601/601 123456789/123456789 voipbuster/abcd 601 = hotline 123456789 = Peter Pan only voipbuster/abcd is easy read/understandable! bye Ronald Wiplinger

We are gradually migrating our users away from Sun Solstice NFS client over to using Samba on the Solaris servers. The PCs that the users use run Windows NT. We've hit a snag. Some of the directories that we are sharing out need to have the drive letters mapped to sub-directories of the share. This seems to be possible with Windows 2000 and Windows XP, but NT doesn't seem to be able to do

Imagine that I have a large number of points (given by coordinates x and y) that vary in density per space. For the purpose of demonstration it could be generated like this: s <- data.frame(x=runif(10000,0,900),y=runif(10000,0,900)); plot(s) I want to create polygons around the points where point density is greater than a selected threshold (for example, by using krieging or equivalent

Hi, I need to select a substring from the filename of a file in a list. I can find all the filenames in a directory by list.files(fn_dir) Each filename has the format (the following is an example because field lengths are variable) XXX184_YYY_ZZZ.dat XXX: 2 or 3 alphabetic characters 184: 3 numeric characters ... I'd like to select the substring XXX which has variable length (from each

Dear R-List, I have a great many files in a directory and I would like to replace in every file the character " by the character ' and in the same time, I have to change ' by '' (i.e. the character ' twice and not the unique character ") when the character ' is embodied in "....." So, "....." becomes '.....' and

Hi, this should be an easy one, but I can't figure it out. I have a vector of tests, with their units between brackets (if they have units). eg tests <- c("pH", "Assay (%)", "Impurity A(%)", "content (mg/ml)") Now I would like to hava a function where I use a test as input, and which returns the units like: f <- function (x) sub("\\)",

Hello; I am a R newbie and would like to know correct and efficient method for doing string replacement. I have a large data set, where I want to replace character "M", "b", and "K" (currency in Million, Billion and K) to millions. That is 209.7B with (209.7 * 10e6) and 100.00K with (100.00 *1/100) and etc.. d <- c("120.0M", "11.01m",

Hi, Is there a way in R to get the string which matches the expression, where the expression is a substring of the parent string. Lets say, I have $i <- "transcript:ENST0000112334 pid:ENSP000012345" What I need is the string "pid:ENSP000012345" from $i using the query "ENSP". Appreciate your comments. Praveen Surendran School of Medicine and

Un texte encapsul? et encod? dans un jeu de caract?res inconnu a ?t? nettoy?... Nom : non disponible URL : <https://stat.ethz.ch/pipermail/r-help/attachments/20100208/52a6d080/attachment.pl>

Hi there I have a string like this i want to extract 9831019 from this string i used a regular expresion \d+ by which i can only make it to see 7 and returns. This type of number(9831019) appears in any part of the string and is definitely more than 5 digits all the time and i want to give that as a condition UV7C11-F9-E1 MCS#9831019 MCS Lot #9512516" how do i go abt it Ramya -- View

can someone show me how to use a regular expression to break the string at the bottom up into its three components : (-0.791,-0.263] (-38,-1.24] (0.96,2.43] I tried to use strplit because of my regexpitis ( it's not curable. i've been to many doctors all over NYC. they tell me there's no cure ) but it doesn't work because there also dots inside the brackets. Thanks.

What is the simplest way to extract a matched subexpression? Eg. in perl you can do "hello world" =~ m/hello (.*)/ which would return 1(true) and set $1 to the matched subexpression "world". -- View this message in context: http://n4.nabble.com/regular-expression-submatch-tp1459146p1459146.html Sent from the R help mailing list archive at Nabble.com.