similar to: the bar width of barchart plot in lattice package

Hi R users, suppose I have two vectors, > x=c(1,2,3,4,5) > y=c('a','b','c','a','c') How can I get a data.frame like this? > xy count a 5 b 2 c 8 I know a few ways to fulfill the task. However, I have a huge number of this kind calculations, so I'd like an efficient solution. Thanks -- Best, Zhenjiang

Hi, For example, the data.frame like: origdata.long <- read.table(header=T, con <- textConnection(' subject sex condition measurement 1 M control 7.9 1 M first 12.3 1 M second 10.7 2 F control 6.3 2 F first 10.6 2 F second 11.1 3 F control 9.5 3

Hi R users, I have a list: > x $A [1] "a" "b" "c" $B [1] "b" "c" $C [1] "c" I want to convert it to a lowercase-to-uppercase list like this: > y $a [1] "A" $b [1] "A" "B" $c [1] "A" "B" "C" In a word, I want to reverse the list names and the elements under each

Hi, I have a file like this: 1 2 0.1 2 3 0.2 3 1 0.3 And I want to read it to create a matrix like this: [,1] [,2] [,3] [1,] 0 0.1 0 [2,] 0 0 0.2 [3,] 0.3 0 0 How can I do it efficiently? Thanks. -- Best, Zhenjiang [[alternative HTML version deleted]]

Hi, I have a for loop to make 2 types of plots and I'd like to save one type of plots to a pdf file and the other to another pdf file. How can I control which plot will be saved to which pdf? Thanks -- Best, Zhenjiang

here's my question: suppose I have a matrix: mt<-matrix(1:12,ncol=6) now I have a vector vt<-c(1,2,2,2,1,2) which means I want to get: the 1st row for column1; the 2nd row for column2; the 2nd row for column3; the 2nd row for column4; ... that what I want is this vector: 1,4,6,8,9,12 Does anyone know how to do this fast? I know I can use for-loop to travel all columns,but

Hi all, Suppose I have 2 data.frame , a and b, how can I add them together to get c? Thanks > a A a 1 b 2 c 3 > b A a 6 c 1 > c A a 7 b 2 c 4 -- Best, Zhenjiang [[alternative HTML version deleted]]

Hi R users, Suppose I have two lists and the names of list 'm' are a subset of those of 'n', how can I sum the two lists with corresponding elements added together to get list 'o'? > n = list("a"=1,"b"=3,"c"=5) > m = list('b'=4) > o $a [1] 1 $b [1] 7 $c [1] 5 Thanks -- Best, Zhenjiang [[alternative HTML version

Hi all, When running R interactively, I have the problem as following: > library(ggplot2) Loading required package: reshape Loading required package: plyr Attaching package: 'reshape' The following object(s) are masked from 'package:plyr': round_any Loading required package: grid Loading required package: proto > data(VADeaths) > pg <- ggplot(melt(VADeaths),

Hi R users, I was using read.table to read a file. The data.fame looked alright, but I found not all rows are read by the read.table. What's wrong with it? It didn't give me any warning or error messages. Why the data are truncated? Thanks. $ wc -l all/isoform_exp.diff 42847 all/isoform_exp.diff > a=read.table('all/isoform_exp.diff', header=T, sep='\t') > nrow(a)

Hi all, I have a list x: ?> x=list(a=c('1','2'),b=c('2','3'),c=c('1','2'),d=c('2','3')) I can get the unique elements with unique(), but how can I get the number of duplicates for each unique elements? > unique(x) [[1]] [1] "1" "2" [[2]] [1] "2" "3" Thanks -- Best, Zhenjiang

Hi R users, where can I find the equations used by acf function to calculate autocorrelation? I think I misunderstand acf. Doesn't acf use following equation to calculate autocorrelation? [image: R(\tau) = \frac{\operatorname{E}[(X_t - \mu)(X_{t+\tau} - \mu)]}{\sigma^2}\, ,] If it does, then the autocorrelation of a sine function should give a cosine; however, the following code gives a

R experts, Is there anyway to reorder inside each group? In the following example, the bar of year 1932 is always plotted before the bar of year 1931, may I change the order inside each groups of bars? library(lattice) barchart(yield ~ variety | site,data=barley, groups = year, layout = c(1,6),auto.key = list(points = FALSE, rectangles = TRUE, space = "right"),ylab = "Barley Yield

-----Original Message----- From: Robert Gentleman [mailto:rgentlem@fhcrc.org] Sent: Wed 10/12/2008 18:47 To: Legaie, Roxane Subject: Re: Kegg.db with GOstats Hi Roxanne, Can you redirect your question to the mailing list. And, you can find the answer in the mailing list archives... best wishes Robert Legaie, Roxane wrote: > Dear Robert Gentleman, > I am currently working on

Hi all, I've read the emails of Dan, Deepayan and Sundar about adding error bars to the lattice plots ( https://stat.ethz.ch/pipermail/r-help/2006-October/114883.html), but I still have the problem when I want to adding error bars to barchart. I tried both the solution of Deepayan and Sundar but without luck. Here is my code (I changed prepanel.ci and panel.ci a little to plot bars

I have installed openssh-3.7.1p2(and its Run-time dependencies), from Software Porting And Archive Centre for HP-UX, on an HP rx2600 OS-version 11.23. When I now try to use ssh to this server it works but the DISPLAY environment variable is not set. I get this line in syslog.log on the server Jan 16 10:24:25 sabina sshd[8979]: Accepted publickey for s66103 from 136.163.6.9 port 53117 ssh2 Jan

Hello, I'd like to remove the individual pairs of square brackets along with their content - plus the space directly behind it - from address strings such as this: [Swidsinski, Alexander; Loening-Baucke, Vera; Lochs, Herbert] Charite Humboldt Univ, Innere Klin, D-10098 Berlin, Germany; [Hale, Laura P.] Duke Univ, Med Ctr, Dept Pathol, Durham, NC 27710 USA I'd like get the

Hola gente!! Estoy empezando a trabajar con R, y no puedo resolver lo siguiente: Quiero crear una nueva variable (datmatriz) que toma el valor de 1 si: -la variable sp es igual a L.lucidum -alguna de las variables pap11, pap06, pap01, pap96 es igual a muerto. El script que utilicé es : guaran$datmatriz<-ifelse (guaran$sp=="L.lucidum"|guaran$pap11 ==