similar to: converting a zoo or an xts to a data frame

Hi, I was trying to get a graph in lattice with the following data frame (7 rows, 5 cols): chr start1 end1 meth positive 1 1 10 20 1.5 y 2 2 12 18 -0.7 n 3 3 22 34 2.0 y 4 1 35 70 3.0 y 5 1 120 140 -1.3 n 6 1 180 190 0.2 y 7 2 220 300 0.4 y I wanted the panels to be organized by 'chr' -

> Suppose you have four lifetime operations on the same address in memory, > with loads and stores all around them: > > start1--end1 .. start2--end2 > > If you remove start1 then you have a bare pointer, the memory came from > somewhere and you lose the optimization that loads before start1 become > undef, but you don't miscompile. This is assuming no looping after

On 12/27/2012 12:35 PM, Rafael Espíndola wrote: >>> Oh, I was reading "precedes/following" as having static (dominance) >>> meaning. That is, in the above example you could not delete the store >>> since it is not true that >>> llvm.lifetime.end dominates it. >>> >>> Nick, is this what you had in mind? If not, then we must delete a

Dear all, I am a biologist. I have two sets of distance P(start1, end1) and Q(start2, end2). The distance will be like this. P ------------------------ Q ---------------------------------------- I want to know whether P falls closely to the right end or left end of Q. P and Q are of different lengths for each data point. There are more than 10000 pairs of P and Q. Is there any test or

I've been using the following code to plot using Sweave in version 1.9.1 library(RODBC) library(lattice) channel <-odbcConnectExcel("h:/water.xls") data <- sqlQuery(channel,"select * from `Sheet1$` where Test = 'TOC' and (Valve='5010-05' or Valve='8030-V26' or Valve='1180-08' or Valve='5040-08')") odbcClose(channel) srt <-

>> Oh, I was reading "precedes/following" as having static (dominance) >> meaning. That is, in the above example you could not delete the store >> since it is not true that >> llvm.lifetime.end dominates it. >> >> Nick, is this what you had in mind? If not, then we must delete a >> matching llvm.lifetime.end, but it is not clear how we define

Dear R People: I have a monthly time series which runs from January 1998 to December 2010. When I use tsp I get the following: > tsp(ibm$ts) [1] 1998.000 2010.917 12.000 Is there an easy way to convert this to a seq.Date object, please? I would like to have something to the effect of 1998/01/01 .... 2010/12/01 Thanks, Erin -- Erin Hodgess Associate Professor Department of Computer

Dear R People: I have a zoo object with its date index as a factor. > xAle1.zoo$index Error in xAle1.zoo$index : $ operator is invalid for atomic vectors > str(xAle1.zoo) Class 'zoo' atomic [1:32] 1253 1316 1038 1157 1710 1489 1159 1142 945 1245 ... ..- attr(*, "index")= Factor w/ 32 levels "04/16/09","04/17/09",..: 1 2 3 4 5 6 7 8 9 10 ... >

Dear R-ers, In my question there are no statistics involved - it's all about data manipulation in R. I am trying to write a code that should replace what's currently being done in SAS and SPSS. Or, at least, I am trying to show to my colleagues R is not much worse than SAS/SPSS for the task at hand. I've written a code that works but it's too slow. Probably because it's

Dear R People: The aggregate function works very well on regular time series. Is there a version for zoo or its that would take daily data and convert it to monthly, please? Thanks in advance, Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com

Dear R People: This is probably is very simple question. I have a monthly time series, ibm$ts , that I would like to convert to a quarterly series. I know that I could use "aggregate", but I am interested in the to.quarterly conversion, please. Here is my example: > str(ibm$ts) Time-Series [1:144] from 1998 to 2010: 43.7 46.3 46 51.4 52.2 ... > tsp(ibm$ts) [1] 1998.000 2009.917

Dear R People: I have the following data frame: > x.df date cond freq 1 04/01/09 Fever 12 2 04/02/09 Fever 11 3 04/03/09 Fever 10 4 04/04/09 Fever 13 5 04/05/09 Fever 6 6 04/01/09 Rash 6 7 04/02/09 Rash 10 8 04/03/09 Rash 9 9 04/04/09 Rash 10 10 04/05/09 Rash 8 11 04/01/09

Dear R People: I'm trying to convert a daily zoo object to a weekly zoo object: xdate <- seq(as.Date("2002-01-01"),as.Date("2010-07-10"),by="day") library(zoo) length(xdate) xt <- zoo(rnorm(3113),order=xdate) xdat2 <- seq(index(xt)[1],index(xt)[3113],by="week") xt.w <- aggregate(xt,by=xdat2,mean) Error: length(time(x)) ==

Dear useRs, Thanks for any advices # I do not know where are the examples how to mark groups # based on signal occurence in the additional variable: cf. variable c2, # How to calculate different calculations for groups defined by (split by occurence of c2 characteristic data) #First example of simple data #mexample 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17

Dear R People: I would like to combine a zoo object with some observations at the end. Here is the set up: > xgh 2010-06-15 2010-06-16 2010-06-17 2010-06-18 2010-06-19 2010-06-20 2010-06-21 5 6 1 5 0 0 13 2010-06-22 2010-06-23 2010-06-24 2010-06-25 2010-06-26 2010-06-27 2010-06-28 9 6 4 6

If you are writing a new package I don't see why you should restrict yourself to S3 or S4 classes. Your "new package" can certainly build on other packages. (Why not?) As I wrote in my previous email, if you are dealing with time series you might want to consider appropriate classes already defined in other packages, such as those obtained via library(fpp3) In my work, I deal with

Dear R People: I have the following time series and plot: > x <- ts(rnorm(50),start=2005,freq=12) > plot(x) > which works fine. I would like to plot a subset of that time series, which I did with: > plot(window(x,2005,2006.83)) Is there a better way to do this, please? Thanks, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences

Hello everyone! I have an opinion question please. If I?m writing a new package, would you recommend using S3 or S4 structure, please? I know I will get lots of opinions, but that?s fine. Thanks, Erin Erin Hodgess, PhD mailto: erinm.hodgess at gmail.com [[alternative HTML version deleted]]

Dear R People: Hello again! I found something unusual in the behavior of the "endpoints" function from the xts package: > x1 <- ts(1:24,start=2008,freq=12) > dat <- seq(as.Date("2008/01/01"),length=24,by="months") > library(zoo);library(xts) > x2 <- zoo(1:24,order=dat) > #Here is the surprise: > endpoints(as.xts(x1),'quarters')

We can have different frequencies of data, including Business day data and daily data as our outputs. Both of those will start on Monday. Erin Hodgess, PhD mailto: erinm.hodgess at gmail.com On Mon, Apr 7, 2025 at 4:57?PM CALUM POLWART <polc1410 at gmail.com> wrote: > Clearly something has gone terribly wrong. Everyone is saying use S3. This > is an online discussion... So someone