similar to: comparing attitudes of 2 groups / likert scales?

Help with survey data: Hello R colleagues, I hope this is an appropriate place to direct this question. It relates specifically to the comparability of a 5-point likert to a 4- point likert scale. One question in my dataset asks "How much should be done to reduce the gap between rich and poor" Much more, somewhat more, about the same, somewhat less and much less. The second

Hi everyone, I'm stuck on my dissertation which is due next week. I'm a business major student and my project is a comparative research on corporate social responsibility (CSR) between Chinese and German firms. According to my literature review, it's quite obvious that German firms have much better CSR initiatives and strategies than the Chinese ones and I wanted to test whether it was

R- Help Forum Working with the "likert" package and I can't figure out why my "bar" graphs are backwards (see attached). The percentages are place correctly but the bars are backwards. #Sample code # libraries library(likert) # create data band <- c("Band 3","Band 3","Band 3","Band 3","Band 3","Band

I'm creating a stacked bar chart using the likert command in the HH package. My data are in a data frame, with two numeric variables and a categorical variable, I can't get likert to use the column containing the categorical variable as a my y axis label. Here is a quick example: library(HH) #my data are:

Dear R members Could someone tell me how to simulate Likert-type data using the rnorm function. Let's say, 200*15 random numbers in a variable that goes from 1 to 4 in steps of 1 (i.e., 1, 2, 3, 4) belonging to a normal distribution? random.data <— matrix(rnorm(200 * 15), nrow = 200, ncol = 15) random.data The result cannot be reached. could one help me revise the syntax?

R- Help Forum Working with the "likert" package and find that my "bar" graphs are backwards (see attached) > summary(results) Item low neutral high mean sd 4 Q4 5 15 80 2.75 0.5501196 5 Q5 20 40 40 2.20 0.7677719 1 Q1 65 30 5 1.40 0.5982430 3 Q3 5 90 5 2.00 0.3244428 2 Q2 90 10 0 1.10 0.3077935

Hello, Before I start to construct something inferior myself I would like to know if such a plot function is already out there. I have count data of a small survey with a few questions which use a scale from "Strongly disagree" to "Strongly agree" and similar things. What I would like to have for a slide is a plot which shows for each question a line over this scale and the

Dear colleagues, I would like to run a cluster analysis on a number of variables. They are Likert Scale (0 to 10), but they also have a "Don't know' option at the end of the scale. Apparently, with the 'Don't Know' option in place, they cannot be considered to be linear or ordinal. How can these variables be analysed using R? One option would be to use poLC and treat

Hi! I am using R to process some community survey data. Several item responses are recorded via a 7-point Likert-Scale. As I have coded the responses, 1 represents high agreement, and 7 high disagreement. This of course impacts the coefficients in a linear regression (of example agreement to self-perception measures on housing satisfaction). For some purposes, in order to make the coefficients

Dear list, I have the following how-to-do it in R, questions. Suppose I have ten independent variables, and one dependent variable. I want to find the Pearson correlation of all the IVs with the DV, but not the correlation between the IVs. What I know so far, about R, that I have to type the cor () function ten times, each time requesting for a correlation between one IV and the DV. I was

Hi For first question, maybe I am completely wrong but cor(swiss[,-1], swiss[,1]) should give you what you want in one step. Second question Without an example it is hard to say but maybe aggregate is the way forward. > aggregate(iris[,1:4], list(iris$Species), function (x) c(mean=mean(x), sd=sd(x))) Group.1 Sepal.Length.mean Sepal.Length.sd Sepal.Width.mean Sepal.Width.sd 1

Dear R help; I'll preface this by saying that the example I've provided below is pretty long, turgid, and otherwise a deep dive into a series of functions I wrote for a simulation study. It is, however, reproducible and self-contained. I'm trying to do my first simulation study that's quite big, and so I'll say that the output of this simulation as I'd like it to be is

Gracias Jorge. Pero tiene que ser otra cosa. El Renviron está bien y unzip está en ese path. Y al hacerlo como indica Oscar no hay problema con el unzip Miraré como está en otro Linux que si funciona a ver que puede ser. Pero será después de Navidad. Saludos [[alternative HTML version deleted]]

Si. Pero no funciona. En ordenador curro si funciona y tb tiene linux. Seguiré investigando has probado con: install_github('paquete",username='usuario')? 2013/12/20 Jose Luis Cañadas Reche <canadasreche@gmail.com>: > Hola a todos. > > Estoy intentando instalar el paquete likert utilizando devtools y obtengo el > siguiente error > > library(devtools) >

Hola a todos. Estoy intentando instalar el paquete likert utilizando devtools y obtengo el siguiente error library(devtools) install_github('likert','jbryer') Installing github repo(s) likert/master from jbryer Downloading likert.zip from https://github.com/jbryer/likert/archive/master.zip Error en function (type, msg, asError = TRUE) : <not set> Me pasa también con

I am trying to use a new (to me) package (samr) and even when I try to run a very simple example, I get this "cannot open the connection" error. The reason I am writing to r-help rather than to the authors of samr is I think this may be a more general R problem rather than a samr-specific problem. Perhaps something with my installation and write access to some particular place ? I am

Gracias Oscar. Funciona perfectamente. Ya investigaré más adelante porque no funciona install_github Saludos y feliza navidad.. El 20/12/13 23:05, Oscar Perpiñan escribió: > tmp <- paste0(tempdir(), '/likert.zip') > download.file('https://github.com/jbryer/likert/archive/master.zip', > destfile=tmp, method='wget') > unzip(tmp,

Please forgive a stats question. I have to sets of data (unpaired) measured on an ordinal scale. I want to test to see if the two sets are different (i.e. do they have the same location): set1: 1,3,2,2,4,3,3,2,2 set: 4,4,4,3,3,5,4,4 What is the most appropriate non-parametric test to test location? Thanks, John Confidentiality Statement: This email message, including any attachments, is

I am looking at a data set containing two variables (x,y), each of which represents relative frequencies (rounded): data.frame(x = c(0.1,0.6,0.2,0.1), y = c(0.5,0.2,0.2,0.1)) x y 1 0.1 0.5 2 0.6 0.2 3 0.2 0.2 4 0.1 0.1 each of the rows reflects a "relation" between x and y, for example in row 4: 10% of the observations in x account for 10% of the observations in y. I

Dear Richard,? Thank you very much for your reply. I went through the code and it worked. I was also able to change the colours.? I was wondering if I can change the legend position; instead of being in the bottom to be on the left side.? I tried the following but without any success strip = FALSE strip.right = TRUE likert(t(hellisheidi), ReferenceZero=.5, xlab="X-lab",