Displaying 20 results from an estimated 3000 matches similar to: "Alignment of x-axis labels"
2006 May 18
2
matrix transformation into 3 columns II.
Dear R-users
Sorry for posting the previous message too soon before I have finished it.
I have matrix (mprecip) with headers:
> dim(mprecip)
[1] 6268 170
> mprecip
date GilzeRijen Eindhoven Volkel ZuidLimburg Arcen Ubachsberg
1 01/01/1978 NA 0.0 NA 0.1 NA NA
2 01/02/1978 NA 0.0 NA 0.0 NA NA
3
2010 Apr 15
1
Unwanted boxes in legend
Dear all,
I am using the following code to generate a legend in my plot (consisting of both bars and points), but end up with boxes around my points:
legend(10, par("usr")[4], c("A", "B", "C", "D"), fill=c(NA,NA, "grey28", NA), pch=c(16,4,NA,18), col=c("red","blue","grey28","yellow"), lty=FALSE,
2010 May 18
2
Function that is giving me a headache- any help appreciated (automatic read )
note: whole function is below- I am sure I am doing something silly.
when I use it like USGS(input="precipitation") it is choking on the
precip.1 <- subset(DF, precipitation!="NA")
b <- ddply(precip.1$precipitation, .(precip.1$gauge_name), cumsum)
DF.precip <- precip.1
DF.precip$precipitation <- b$.data
part, but runs fine outside of the function:
days=7
2018 Apr 18
0
How to replace numeric value in the column contains Text (Factor)?
The simplest would be to convert precip to character and then back to a factor if you really want it to be a factor. This will also remove the levels that no longer exist.
str(dat)
# 'data.frame': 5 obs. of 3 variables:
# $ Sites : Factor w/ 5 levels "Site1","Site2",..: 1 2 3 4 5
# $ temp : num 14 15 12 12.5 17
# $ precip: Factor w/ 5 levels
2005 Nov 15
1
combination xyplot and barchart?
Dear R community,
I am having trouble determining how to create the graph I want
utilizing my relatively limited knowledge of R. So far I have been
using the lattice library to create most of what I need.
The dataset (enviro) consists of 2 variables (Temp and Precip) for each
Day of a 2-yr period (Year). I wish to display Temp and Precip along
the y axis plotted by Day on the x axis to allow
2006 Jan 16
1
label of second y-axis in xyplot (lattice)
Dear group,
First I provide you with an example, I found in the newsgroup. Then I'd like to explain my problem to you by means of the output.
enviro <-
data.frame(Year = rep(2001:2002, each = 365),
Day = rep(1:365, 2),
Precip = pmax(0, rnorm(365 * 2)),
Temp = 2 + 0.2 * rnorm(365 * 2))
xyplot(Precip + Temp ~ Day | Year,
2024 Nov 06
1
Using multiple dat files
"It seems therefore that there is no other way than read in individually >
100 weather tables using read.tables., right? Using file.choose() doesn't
change the work."
Yes. With that many files, file.choose() does not make sense. However, I
still do not understand what is the problem with using lapply() on the
character vector of file names with read.table() as you did in your
2011 Feb 17
3
summing 15 minute precip data to daily
Hi all,
i'm sure there is an easy way to do this, but i'm stumped, so any help would
be appreciated.
i have a single column of data for precipitation every 15 minutes over a
year. i want to sum the precip to daily data.
so the first 96 records = the first day, the second 96 records = the second
day, and so on....
is there a way to write a for loop that would sum the data to daily, and
2010 Oct 19
1
Problems with a specific calculate.
Hello friends of R,
My name is Toni, i'm 25 and I'm working on the Meteorological Investigation team from Balearic Islands.
I had contact to you because I have a problem:
I done a file for every day since 1912 about precipitation. That file has the following structure:
> str(Ast)
Loading required package: sp
Formal class 'SpatialPixelsDataFrame' [package "sp"]
2018 Apr 18
3
How to replace numeric value in the column contains Text (Factor)?
Hi R user,
Would you mind to help me on how I can change a value in a specific column
and row in a big table? but the column of the table is a factor (not
numeric).
Here is an example. I want to change dat[4:5,3]<-"20" but it generated NA>
do you have any suggestions for me?
dat<-structure(list(Sites = structure(1:5, .Label = c("Site1", "Site2",
2009 Jul 12
1
variance explained by each predictor in GAM
Hi,
I am using mgcv:gam and have developed a model with 5 smoothed predictors
and one factor.
gam1 <- gam(log.sp~ s(Spr.precip,bs="ts") + s(Win.precip,bs="ts") + s(
Spr.Tmin,bs="ts") + s(P.sum.Tmin,bs="ts") + s( Win.Tmax,bs="ts")
+factor(site),data=dat3)
The total deviance explained = 70.4%.
I would like to extract the variance explained
2012 Oct 04
3
R combining vectors into a data frame but without a continuous common variable
Hello,
I have two different files which I'd like to combine to make one data frame
but I've no idea how to do it! The first file has two columns; one is the
date, the following is a binary code for debris flow events. Then my other
file has also two columns; the date and then precipitation data.
The thing is, is that the two date columns don't all contain the same dates.
The binary
2013 Apr 18
1
Arranging two different types of ggplot2 plots with axes lined up
Hi all,
I want to arrange two ggplot2 plots on the same page with their x-axes
lined up - even though one is a boxplot and the other is a line plot. Is
there a simple way to do this? I know I could do this using facetting if
they were both the same type of plot (for example, if they were both
boxplots), but I haven't been able to figure it out for two different types
of plots.
Below is my
2010 Sep 15
1
Difficulty creating Julian day in data frame
Hi,
I'm attempting to add a "Julian Day" column to a data frame.
Here is my code and the resulting data frame:
vic.data <- read.table("C:/VIC/data/vic.data.csv", header=F)
names(vic.data) <- c("year", "month", "day", "precip", "evap",
"runoff", "baseflow", "Tsup",
2011 Dec 09
3
ggplot with geom_tile
Dear R-users,
I am trying to make a plot with ggplot-geom_tile(), but cannot remove some unwanted (white) lines through my plot.
Below a reproducible example:
#####
library(ggplot2)
tot=as.data.frame(rep(seq(-50,50,5),each=21))
names(tot)="precip"
temp=rep(seq(-5,5,0.5),21)
tot$temp=temp
disc=array(dim=c(21,21))
for(i in 1:21){
for(y in 1:21){
temp<-
2009 Jul 27
1
Creating new data frame using loop
Hi all,
I sent a request round last week asking for help with using a "for" loop to read and separate a large dataset. The response I got worked great, but now I have another problem with using my loop.
Basically I have a number of different files containing columned data. There are 132 datasets, named such that I have something in the form...
precip_colxxx.txt
...where xxx is a
2007 Sep 10
1
overlay lattice histograms with goodness-of-fit pdfs
Hello,
I am new to R exploratory data analysis and plotting. Is anyone aware of a way
to overlay a set of conditional histograms with conditional PDFs? Below, I
generate a lattice plot of precipitation histograms based on different months
and stations, given a subset of the dataset:
histogram(~ data | month * station,
data = sta.stack[sta.stack[,"type"]=="precip" &
2024 Nov 06
3
Using multiple dat files
Dear community
To import multiple .dat weather files I am using list.files().
I intend to use the R package ?ClimInd? to calculate different agroclimatic indicators.
Question: Is there another solution to import multiple .dat files so that I can select elements from the list, e.g. one specific weather file (example AAR_DailyWeather)?
# Import multiple .dat files weather data
filelist <-
2008 Sep 04
2
using complete.cases() with nested factors
Hello,
This maybe a newbie question. I have a dataframe that looks like the sample
at the bottom of the email. I have monthly precipitation data from several
sites over several years. For each site, I need to extract years that have
a complete series of 12 monthly precipitation values, while excluding that
year for sites with incomplete data. I can't figure out how to do this
gracefully
2010 Nov 16
1
Force evaluation of variable when calling partialPlot
Greg,
Two thoughts:
1. It might be possible that 'vars' is a reserved word of sorts and if you change the name of your vector RF might be happier
2. A way that works for me is to call importance as follows:
sel.imp <- importance(sel.rf, class=NULL, scale=TRUE, type=NULL)
and then use the 'names' of the imp data frame to be absolutely clear to RF you are talking about the