similar to: sum specific rows in a data frame

Dear R users, I have been trying to compute the following function and need it to work with n=15000, but it would only compute for smaller ns, such as n=1000 and not above. I was wondering if anyone would have a solution for this problem! Thank you very much for your kind support! Sincerely, Nan ------ Wi <- function(n) { fun <- function(w,i){

Dear group, I know this issue has been already covered, and before you reply I must say I have read the R-FAQ and search the mailing list archive. I still can't manage to change my factor to numeric as I couldn't find any clear answer. Here is my df : Pose1 <- structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L, 8L), .Label = c(" SUGAR NO.11 May/10 ", "COTTON

Hello Everyone,   Learning about R and its wonderful array of functions. If it's not obvious, I usually try to find out what a function stands for. I think this helps me remember better.   One function that has me stumped is "sink." Can anyone tell me if this stands for something?   Thanks,   Paul         __________________________________________________ [[alternative HTML

Dear group, Here is my data frame: position100415 <- structure(list(DESCRIPTION = structure(1:9, .Label = c(" SUGAR NO.11 Jul/10 ", " SUGAR NO.11 May/10 ", "CORN May/10 ", "COTTON NO.2 Jul/10 ", "CRUDE OIL miNY May/10 ", "ROBUSTA COFFEE (10) Jul/10 ", "SILVER May/10 ", "SOYBEANS Jul/10 ", "WHEAT May/10

Dear R users, I have a data with 1000 variables named "x1", "x2", ..., "x1000", and I want to construct a formula like this format: ~x1+x2+...+x1000+x1:x2+x1:x3+x999:x1000+log(x1)+...+log(x1000) That is: the base variables followed by all interaction terms and all base feature log-transformations. I know I can use several paste functions to construct it. But is

Am Sa., 6. Apr. 2019 um 18:01 Uhr schrieb Rowland Penny via samba < samba at lists.samba.org>: > On Sat, 6 Apr 2019 17:21:26 +0200 > Martin Krämer <mk.maddin at gmail.com> wrote: > > > Hello Rowland, > > > > thanks for your help. > > Below my comments > > > > See here: > > > > > > http://apt.van-belle.nl/ > > >

At the moment I've no host with which to test ppp/lp things on. If you (or anyone) could provide complete regexes, (each beginning with ^ and ending with $) I will patch the rules accordingly. If not, sending the full log lines is a good start. Thanks! -- [ Todd J. Troxell ,''`. Student, Debian GNU/Linux Developer, SysAdmin, Geek :

I'm trying to read two data sets in json format from a single .js file. I've tried fromJSON() in both RJSONIOIO and RJSON packages, but they require that the lines be pre-parsed somehow in ways I don't understand. Can someone help? > wheat <- readLines("http://mbostock.github.com/protovis/ex/wheat.js") > str(wheat) chr [1:70] "var wheat = [" "

Dear R-users, I have a dataset as like below, and I want to subtotal the values of rice,wheat and maize by year for each fid. fid      year     rice     wheat      maize ------------------------------------------------ 1        1995      5        NA           NA 1        1995      NA        3           NA 1        1995      NA       NA           2 1        1996      4        NA           NA 1  

Hi all, I am trying to use nonlinear regression (nls) to analyze some seed germination data, but am having problems with error codes. The data that I have closely matches the germination dataset included in the drc package. Here is the head of the data temp species start end germinated TotSeeds TotGerminated Prop 1 10 wheat 0 1 0 20 0 0.0 2 10 wheat

Hi Guys. I have a matrix which has names in every other column and the other one is empity ("") example X10000 X10001 X10002 [1,] "A" "G" "A" "G" "G" [2,] "G" "G" "A" "G" "A" [3,] "G" "G" "A" "A" "A"

How do I make the delimiter for cut be a single character with hex value 1e? I tried in a script file: DELIMITER='\x1e' DD=`echo $DATA | cut -f 1 --delimiter $DELIMITER` and it tells me: cut: the delimiter must be a single character Jerry

Hi everyone! I have a data frame with 1112 time series and I am going to randomly sampling r samples for z times to compose different portfolio size(r securities portfolio). As for r=2 and z=10000,that's: z=10000 A=seq(1:1112) x1=sample(A,z,replace =TRUE) x2=sample(A,z,replace =TRUE) M=cbind(x1,x2) # combination of 2 series Because in a portfolio with x1[i]=x2[i],(i=1,2,...,10000) means a 1

Hi Keep your messages in the list, you increase your chance to get some answer. I changed your data to groupedData object (see below), but I did not find any problem in it. plot(wlg) gives reasonable picture and I am not such expert to see any problem with data. Seems to me, that something has to be wrong with nlsList function. > wheat.list <- nlsList(Prop ~ SSlogis(end,Asym, xmid,

Dear group, I have these 2 following data frame: allcon <- structure(list(DESCRIPTION = structure(1:17, .Label = c("COFFEE C Jul/10", "COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB NATURAL GAS May/10", "ROBUSTA COFFEE (10)

Dear group, I have 3 data frames I would like to merge. Here they are: pose16 <- structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11

Dear group, Here is my data frame: > dput(u) structure(list(DESCRIPTION = structure(c(2L, 5L, 6L, 7L, 9L, 11L, 12L, 15L, 14L, 16L, 1L, 10L, 3L, 4L, 13L, 8L, 17L), .Label = c("COFFEE C Jul/10", "COPPER May/10", "CORN Jul/10", "CORN May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "HENRY HUB

Hello, I have recently download and compiled version 3.7.1p2 of openssh, but am having authentication issues with it. I have been using 3.6.1p1 with no problems. Both versions were compiled on the same Solaris 8 host. That host uses ldap for its name service. Both were compiled using the same openssh config options: --prefix=/opt/openssh --with-pam --with-zlib=/opt/openssh/lib However, the

Dear group, Here is my df : df3 <- structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10", "WHEAT Jul/10", "SPCL HIGH GRADE ZINC USD",

Dear all R2.10 WinXP I have a dataset dealing with the way different wheat cultivars build their yield. Wheat ears are organised in spikelets where the spikelets can be numbered from the bottom, with even numbers on one side and odd on the other. I know how many kernels there were in each spikelet after some months spent counting them... Now I want to illustrate the differences between the