similar to: subsetting a matrix with specified no of columns

Hi Michael and Abby, So one thing that could happen that would be backwards compatible (with the exception of something that was an error no longer being an error) is head and tail could take vectors of length (dim(x)) rather than integers of length for n, with the default being n=6 being equivalent to n = c(6, dim(x)[2], <...>, dim(x)[k]), at least for the deprecation cycle, if not

Hi, suppose I have a matrix (or dataframe) as a result from subsetting. mat <- matrix(1:20,ncol=2) mat[c(3,6,9),] <- NA cc <- complete.cases(mat) sub <- mat[cc,,drop=FALSE] sub <- sub * 2 #some caluculations with sub. now I would like to expand sub somehow so row 3,6, and 9 would be filled with NAs but the rest should be in place again. Is there a simple function for this?

Dear All, I have a correlation matrix say 'M' (4000x4000) for 4000 genes and I want to subset it to 'N' (190x190) for 190 genes. The list of those 190 genes are in variable 't'. So the idea is to read the names of genes from variable 't' and subset the matrix M accordingly. Any thoughts are welcome! Best Lee [[alternative HTML version deleted]]

>>>>> Fox, John >>>>> on Tue, 17 Sep 2019 12:32:13 +0000 writes: > Dear Herve, > Sorry, I should have said "matrices" rather than "data frames" -- brief() has methods for both. > Best, > John > ----------------------------- > John Fox, Professor Emeritus > McMaster University >

>>>>> Michael Chirico >>>>> on Sun, 15 Sep 2019 20:52:34 +0800 writes: > Finally read in detail your response Gabe. Looks great, > and I agree it's quite intuitive, as well as agree against > non-recycling. > Once the length(n) == length(dim(x)) behavior is enabled, > I don't think there's any need/desire to have

Hi, I am wondering how to write a function which sorts a matrix by giving a vector of column numbers. Suppose we have a matrix (or data frame) "Mat" and I want to obtain order(Mat[,1], Mat[,3], Mat[,6,], Mat[,8], Mat[,10], Mat[,13]) in order to sort the matrix by those columns. Is there a way to write a function so that I can give a vector of the column numbers c(1,3,6,8,10,13) and do

Finally read in detail your response Gabe. Looks great, and I agree it's quite intuitive, as well as agree against non-recycling. Once the length(n) == length(dim(x)) behavior is enabled, I don't think there's any need/desire to have head() do x[1:6,1:6] anymore. head(x, c(6, 6)) is quite clear for those familiar with head(x, 6), it would seem to me. Mike C On Sat, Jul 13, 2019 at

Awesome. Gabe, since you already have a workshopped version, would you like to proceed? Feel free to ping me to review the patch once it's posted. On Mon, Sep 16, 2019 at 3:26 PM Martin Maechler <maechler at stat.math.ethz.ch> wrote: > >>>>> Michael Chirico > >>>>> on Sun, 15 Sep 2019 20:52:34 +0800 writes: > > > Finally read in

I think of head() as a standard helper for "glancing" at objects, so I'm sometimes surprised that head() produces massive output: M = matrix(nrow = 10L, ncol = 100000L) print(head(M)) # <- beware, could be a huge print I assume there are lots of backwards-compatibility issues as well as valid use cases for this behavior, so I guess defaulting to M[1:6, 1:6] is out of the

Dear R-users, I would like to ask whether it's possible (for sure it would be), to plot each rows (or columns) in different graphs and in the same figure region without using the function "par" and then struggling around with "axes" and labels etc. Luckily, I would always have "rows + columns = even number" and the same "ylim". The next one could be a

Hi R-Help! I am trying to find a nicer way of extracting all the "complete" diagonals of a matrix. I am working with very large matrices that have many more rows than columns. I want to be able to extract each of the diagonals that are as long as the number of columns in the matrix. I have written a rather ugly function that presently does the job. It illustrates what I am trying to

Hi I have a matrix (4 x 950) and I want to remove 3 rows, where the values from the first column are 713, 714 and 715. I can select the rows, one by one, with mat[mat$first==713,] mat[mat$first==714,] ... but I'm unable to (i) select the 3 rows at once, (ii) select the matrix excluding those rows. How can I do it ? Thanks EJ

Dear Herve, The brief() generic function in the car package does something very similar to that for data frames (and has methods for other classes of objects as well). Best, John ----------------------------- John Fox, Professor Emeritus McMaster University Hamilton, Ontario, Canada Web: http::/socserv.mcmaster.ca/jfox > On Sep 17, 2019, at 2:52 AM, Pages, Herve <hpages at

Dear Herve, Sorry, I should have said "matrices" rather than "data frames" -- brief() has methods for both. Best, John ----------------------------- John Fox, Professor Emeritus McMaster University Hamilton, Ontario, Canada Web: http::/socserv.mcmaster.ca/jfox > On Sep 17, 2019, at 8:29 AM, Fox, John <jfox at mcmaster.ca> wrote: > > Dear Herve,

useR's, I have a matrix given by the code: mat <- matrix(c(rep(NA,10),1,2,3,4,5,6,7,8,9,10,10,9,8,NA,6,5,4,NA,2,1,rep(NA,10),1,2,3,4,NA,6,7,8,9,10),10,5) This is a 10x5 matrix containing missing values. All columns except the second contain missing values. I want to delete all columns that contain ALL missing values, and in this case, it would be the first and fourth columns. Any column

Hello. I've observed some odd behaviour. Most likely, it is already known and explained somewhere, but I can't find an explanation anywhere, so I would appreciate being pointed in the right direction. The issue with the following code is self explanatory: > mat <- matrix(c(c(1,1,1),c(2,2,2)),nrow=3) > mat[,c(1:3%/%2)] [,1] [,2] [1,] 1 1 [2,] 1 1 [3,] 1 1

Hi Martin et al. Sorry for not getting back onto this sooner. I've been pretty well buried under travel plus being sick for a bit, but I will be happy to roll up a patch for this, including documentation and put it into a wishlist item. I'll aim to do that at some point next week. Thanks @Martin Maechler <maechler at stat.math.ethz.ch> for engaging with us and being willing to

The data set consists of two sets of matrices, as labelled by the columns, T's and C's. > xy x T1 T2 T3 T4 T5 C1 C2 C3 C4 C5 [1,] 50 0.00 0.00 33.75 0.00 0.00 0.00 36.76 0.00 35.26 0.00 [2,] 13 34.41 0.00 0.00 36.64 32.86 34.11 35.80 37.74 0.00 0.00 [3,] 14 35.85 0.00 33.88 36.68 34.88 34.58 0.00 32.75 37.45 0.00 [4,] 33 34.56

Hello all, I'm working with a matrix that will have varying dimensions. It will populate an array such that the number of matrix columns will determine the number of 3rd dimension levels of the array. Rows will be the same for both. For this example lets say the array will have 2 columns, but that's not fixed. dim(arr)<-c(dim(mat)[1],2,dim(mat)[2]) I wish to repeat each matrix

useR's I have a matrix from which I want to take multiple subsets from, according to a particular scheme I will now describe. The matrix below (mat) is 5x5, and I want to take 9 subsets of it, each of dimension 3x3. The best way to explain what the result should look like is with the following: > dat <- c(3,6,1,9,12,9,2,10,6,5,3,13,1,4,8,9,4,6,10,11,2,7,3,5,10) > miss <-