Displaying 20 results from an estimated 700 matches similar to: "help in function in R akin to macro in SAS"
2010 Jun 02
1
how to label the som notes by the majority vote
HI, Dear R community,
I am using the following codes to do the som. I tried to label the notes by
the majority vote. either through mapping or prediction.
I attached my output, the left one dont have any labels in the note, the
right one has more than one label in each note. I need to have only one
label for each note either by majority vote or prediction.
Can anyone give some suggestions or
2013 Jul 24
1
Help to improve prediction from supervised mapping using kohonen package
I would really like some or any advice on how I can improve (or fix??)
the following analysis. I hope I have provided a completely runnable
code - it doesn't produce any errors for me.
The resulting plot at the end shows a pretty poor correlation (just
speaking visually here) to the test set. How can I improve the
performance of the mapping and prediction?
Here are some of the data
2010 Feb 19
3
Omitting members of a sequence
Hello, this is just a point of curiosity with me. I want a sequence of
numbers from 64 to 70, omitting the 2nd and 4th numbers. I can do it
these ways:
> seq(64, 70)[-c(2, 4)]
[1] 64 66 68 69 70
> foo <- 64:70
> foo[-c(2, 4)]
[1] 64 66 68 69 70
But how come this doesn't work?
> 64:70[-c(2, 4)]
[1] 64 65 66 67 68 69 70
Just wondering.
--
Stuart Luppescu -=- slu .at.
2011 Aug 16
2
Assignment working differently inside ifelse()
Hello all, I need to extract rows and columns from a data frame and put
them in a matrix. In some cases, there are no rows in the data frame
meeting the selection criteria. For those rows I want to put a row of
0's in the matrix. Here's my clumsy code:
tab1.m1 <- matrix(0, nrow=2, ncol=4)
tab1.m1[1,] <- ifelse(length(as.matrix(tab1[tab1$comp==the.comp & tab1$schlid==the.schl
2012 Mar 22
2
Order of terms in formula changes aov() results
Hello, This one is very perplexing. I have teacher observation data,
with factors teacher ID, observer ID, component, grade and subject. When
I do this,
aov(data=ratings.prin.22, rating ~ obsid.f + tid.f + subject.f + grade.f + comp.f)
I get this:
Terms:
obsid.f tid.f grade.f comp.f Residuals
Sum of Squares 306.23399 221.38173 1.70000 14.52831 279.05780
Deg. of
2011 Jan 23
2
Ordering box plots
Hello all, I want box plots by group to display in order of increasing
mean (or median) of each group but can't seem to figure it out and
couldn't find anything on R-seek, either.
My data looks like this:
meas unit sid grade rsprti
1 2.24 1002 99999902 NA 0.8600000
2 3.04 1007 43589520 3 0.9400000
3 4.95 2002 39910470 5 1.5300000
4 2.24 2002 39986280 5
2011 Apr 21
1
Stymied by plyr
Hello, This is my first time trying to use plyr, and I'm getting
nowhere. I have teacher ratings data (1:4), on 10 components, by
external observers and internal observers, in schools in areas. I want
to calculate the percentage of each rating given on each component, by
each type of observer, within each school, within each area. The data
look like this:
unit area ext.obs rating comp
11
2011 Nov 20
1
Need help with table() and apply()
Hello, I am having trouble getting counts of values in rows of a data
frame. I'm trying to use apply, but it's not working.
This gives a sample of the kind of data I'm working with:
rating.1 <- factor(sample(1:4, size=10, replace=T), levels=1:4)
rating.2 <- factor(sample(1:4, size=10, replace=T), levels=1:4)
rating.3 <- factor(sample(1:3, size=10, replace=T), levels=1:4)
2002 Aug 02
3
I know this is wrong, but why?
My mind has become corrupted by having to use SAS too much. I wanted to
calculate the difference of elements of two vectors if the signs are the
same. I tried it the corrupted way first:
if (effects1[,3] < 0 & effects0[,3] < 0) {
imprv1 <- effects0[,3] - effects1[,3]
} else if (effects1[,3] > 0 & effects0[,3] > 0) {
imprv1 <- effects1[,3] - effects0[,3]
} else {
2010 Jun 29
2
Conditionally constructing columns in a data frame
Hello, I have to construct 5 new columns in a data frame depending on
the value of another of the columns in the data frame. The only way I
could figure out to do this was to subset the data frame five times, do
the variable construction, and then rbind the subsets back together.
Here's part of the code I used:
read001 <- read[read$existstr=="001",]
read001$era1end <- NA
2007 Apr 18
1
[Bridge] Problem loading bridge.o
Hello, I want to add wireless capability to my Gentoo-linux based
firewall/router at home, so I bought a Netgear MA311 PCI and installed
the hostap package. I load the hostap_pci module and the wlan0 interface
comes up fine. I can detect the signal from a wireless enabled laptop.
Now I'm thinking I'm going to bridge the wlan0 interface and the eth1
interface, and run the firewall with br0
2010 Sep 01
5
[semi-OT] Using fortune() in an email signature
Hello, As you can see from my signature in this message, I use the R
fortune function to generate a fortune, which is then fed to the
signature program, which constructs a named pipe containing the
fortune-bearing sig, which is then included in mail messages. The
problem is that it's got extraneous junk in it and I can't figure out
how to get rid of it. This is the command that generates
2002 May 19
3
How to shade part of a density plot
I'm trying to shade part of a density plot. The code I'm trying (using
the Old Faithful data as an example) is something like this:
# The Old Faithful geyser data
data(faithful)
d <- density(faithful$eruptions, bw = "sj")
plot(d)
polygon(d[d$x>4], col = "wheat")
I expected that the part of the curve to the right of 4 on the x axis
should be shaded, but nothing
2004 Oct 11
3
split and rlm
Hello, I'm trying to do a little rlm of some data that looks like this:
UNIT COHORT perdo adjodds
1010 96 0.39890 1.06894
1010 97 0.48113 1.57500
1010 98 0.36328 1.21498
1010 99 0.44391 1.38608
It works fine like this: rlm(perdo ~ COHORT, psi=psisquare)
But the problem is that I have about 100 UNITs, and I want to do a
2010 Jul 05
3
How to determine if R is 64 bit compiled under Unix-alike?
Under MacOS I had R64 executive and it was clear. Under Ubuntu, which I
do not have administrative rights to, there is only R executive. It
seems that I can allocate more than 3GB of memory, however not
everything seems to work the same/right as with R64 under MacOS.
Pms.
2010 Jul 14
1
Multilevel IRT Modelling
Dear All,
does anybody know of a package (working under Linux) for multilevel IRT
modelling?
I'd love to do this without having to go on WINSTEPS or the like..
thanks for the attention!
Federico Andreis
-----
Dr. Federico Andreis
Universit? degli Studi di Milano-Bicocca, PhD Student
MEB Department, Karolinska Institutet, Stockholm, Visiting PhD Student
--
View this message in context:
2010 Apr 15
2
r-loop
HI, Dear community,
I am building the following loop,
ww<-function(file) {
lossw<-vector()
for (x in seq(0.1, 0.9, by=0.1)) {
cat('xweight ', x, '\n')
lossw[i] <- cross.validation(file, x)$avg
}
return(lossw) }
MY question is how to index the lossw[i]?
for (i in 1:9)
for (x in seq(0.1, 0.9, by=0.1))
Thanks so much!
2001 Dec 13
3
emacs 21.1, R-1.3.1, and ESS
On RedHat linux 7.2, I upgraded (?) Emacs and R at the same time and now
I'm getting some funny business with R and ESS. I reinstalled ESS from
the tarball and re-byte-compiled. In particular, help.start() does
work, and ESS works to send text regions to the R process, but ?function
does not return anything, and the status line says
"ESS process not ready. Finish your command
2010 Mar 03
1
help R IRT simulation
hello R,
This is about simulation in psychomtrics in IRT in R. I want to simulate b
parameters(item difficulty) with moments of fixed values of mean, st.d,
skewness and kurtosis. Is there any specific IRT package in R with those
functions to control those moments? I have seen other programs that can
control mean and st.d but not skewness and kurtosis.
Thank you,
helen L
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2010 Aug 23
5
trajectory plot (growth curve)
Hi there,
I want to make trajectory plots for data as follows:
ID time y
1 1 1.4
1 2 2.0
1 3 2.5
2 1.5 2.3
2 4 4.5
2 5.5 1.6
2 6 2.0
...
That is, I will plot a growth curve for each subject ID, with y in
the y axis, and time in the x axis. I would like to have all growth
curves in the same plot. Is there