similar to: help in function in R akin to macro in SAS

Displaying 20 results from an estimated 900 matches similar to: "help in function in R akin to macro in SAS"

2010 Jun 02
1
how to label the som notes by the majority vote
HI, Dear R community, I am using the following codes to do the som. I tried to label the notes by the majority vote. either through mapping or prediction. I attached my output, the left one dont have any labels in the note, the right one has more than one label in each note. I need to have only one label for each note either by majority vote or prediction. Can anyone give some suggestions or
2013 Jul 24
1
Help to improve prediction from supervised mapping using kohonen package
I would really like some or any advice on how I can improve (or fix??) the following analysis. I hope I have provided a completely runnable code - it doesn't produce any errors for me. The resulting plot at the end shows a pretty poor correlation (just speaking visually here) to the test set. How can I improve the performance of the mapping and prediction? Here are some of the data
2010 Feb 19
3
Omitting members of a sequence
Hello, this is just a point of curiosity with me. I want a sequence of numbers from 64 to 70, omitting the 2nd and 4th numbers. I can do it these ways: > seq(64, 70)[-c(2, 4)] [1] 64 66 68 69 70 > foo <- 64:70 > foo[-c(2, 4)] [1] 64 66 68 69 70 But how come this doesn't work? > 64:70[-c(2, 4)] [1] 64 65 66 67 68 69 70 Just wondering. -- Stuart Luppescu -=- slu .at.
2011 Aug 16
2
Assignment working differently inside ifelse()
Hello all, I need to extract rows and columns from a data frame and put them in a matrix. In some cases, there are no rows in the data frame meeting the selection criteria. For those rows I want to put a row of 0's in the matrix. Here's my clumsy code: tab1.m1 <- matrix(0, nrow=2, ncol=4) tab1.m1[1,] <- ifelse(length(as.matrix(tab1[tab1$comp==the.comp & tab1$schlid==the.schl
2012 Mar 22
2
Order of terms in formula changes aov() results
Hello, This one is very perplexing. I have teacher observation data, with factors teacher ID, observer ID, component, grade and subject. When I do this, aov(data=ratings.prin.22, rating ~ obsid.f + tid.f + subject.f + grade.f + comp.f) I get this: Terms: obsid.f tid.f grade.f comp.f Residuals Sum of Squares 306.23399 221.38173 1.70000 14.52831 279.05780 Deg. of
2011 Jan 23
2
Ordering box plots
Hello all, I want box plots by group to display in order of increasing mean (or median) of each group but can't seem to figure it out and couldn't find anything on R-seek, either. My data looks like this: meas unit sid grade rsprti 1 2.24 1002 99999902 NA 0.8600000 2 3.04 1007 43589520 3 0.9400000 3 4.95 2002 39910470 5 1.5300000 4 2.24 2002 39986280 5
2011 Apr 21
1
Stymied by plyr
Hello, This is my first time trying to use plyr, and I'm getting nowhere. I have teacher ratings data (1:4), on 10 components, by external observers and internal observers, in schools in areas. I want to calculate the percentage of each rating given on each component, by each type of observer, within each school, within each area. The data look like this: unit area ext.obs rating comp 11
2011 Nov 20
1
Need help with table() and apply()
Hello, I am having trouble getting counts of values in rows of a data frame. I'm trying to use apply, but it's not working. This gives a sample of the kind of data I'm working with: rating.1 <- factor(sample(1:4, size=10, replace=T), levels=1:4) rating.2 <- factor(sample(1:4, size=10, replace=T), levels=1:4) rating.3 <- factor(sample(1:3, size=10, replace=T), levels=1:4)
2002 Aug 02
3
I know this is wrong, but why?
My mind has become corrupted by having to use SAS too much. I wanted to calculate the difference of elements of two vectors if the signs are the same. I tried it the corrupted way first: if (effects1[,3] < 0 & effects0[,3] < 0) { imprv1 <- effects0[,3] - effects1[,3] } else if (effects1[,3] > 0 & effects0[,3] > 0) { imprv1 <- effects1[,3] - effects0[,3] } else {
2010 Jun 29
2
Conditionally constructing columns in a data frame
Hello, I have to construct 5 new columns in a data frame depending on the value of another of the columns in the data frame. The only way I could figure out to do this was to subset the data frame five times, do the variable construction, and then rbind the subsets back together. Here's part of the code I used: read001 <- read[read$existstr=="001",] read001$era1end <- NA
2007 Apr 18
1
[Bridge] Problem loading bridge.o
Hello, I want to add wireless capability to my Gentoo-linux based firewall/router at home, so I bought a Netgear MA311 PCI and installed the hostap package. I load the hostap_pci module and the wlan0 interface comes up fine. I can detect the signal from a wireless enabled laptop. Now I'm thinking I'm going to bridge the wlan0 interface and the eth1 interface, and run the firewall with br0
2010 Sep 01
5
[semi-OT] Using fortune() in an email signature
Hello, As you can see from my signature in this message, I use the R fortune function to generate a fortune, which is then fed to the signature program, which constructs a named pipe containing the fortune-bearing sig, which is then included in mail messages. The problem is that it's got extraneous junk in it and I can't figure out how to get rid of it. This is the command that generates
2002 May 19
3
How to shade part of a density plot
I'm trying to shade part of a density plot. The code I'm trying (using the Old Faithful data as an example) is something like this: # The Old Faithful geyser data data(faithful) d <- density(faithful$eruptions, bw = "sj") plot(d) polygon(d[d$x>4], col = "wheat") I expected that the part of the curve to the right of 4 on the x axis should be shaded, but nothing
2004 Oct 11
3
split and rlm
Hello, I'm trying to do a little rlm of some data that looks like this: UNIT COHORT perdo adjodds 1010 96 0.39890 1.06894 1010 97 0.48113 1.57500 1010 98 0.36328 1.21498 1010 99 0.44391 1.38608 It works fine like this: rlm(perdo ~ COHORT, psi=psisquare) But the problem is that I have about 100 UNITs, and I want to do a
2010 Jul 05
3
How to determine if R is 64 bit compiled under Unix-alike?
Under MacOS I had R64 executive and it was clear. Under Ubuntu, which I do not have administrative rights to, there is only R executive. It seems that I can allocate more than 3GB of memory, however not everything seems to work the same/right as with R64 under MacOS. Pms.
2010 Jul 14
1
Multilevel IRT Modelling
Dear All, does anybody know of a package (working under Linux) for multilevel IRT modelling? I'd love to do this without having to go on WINSTEPS or the like.. thanks for the attention! Federico Andreis ----- Dr. Federico Andreis Universit? degli Studi di Milano-Bicocca, PhD Student MEB Department, Karolinska Institutet, Stockholm, Visiting PhD Student -- View this message in context:
2001 Dec 13
3
emacs 21.1, R-1.3.1, and ESS
On RedHat linux 7.2, I upgraded (?) Emacs and R at the same time and now I'm getting some funny business with R and ESS. I reinstalled ESS from the tarball and re-byte-compiled. In particular, help.start() does work, and ESS works to send text regions to the R process, but ?function does not return anything, and the status line says "ESS process not ready. Finish your command
2010 Mar 03
1
help R IRT simulation
hello R, This is about simulation in psychomtrics in IRT in R. I want to simulate b parameters(item difficulty) with moments of fixed values of mean, st.d, skewness and kurtosis. Is there any specific IRT package in R with those functions to control those moments? I have seen other programs that can control mean and st.d but not skewness and kurtosis. Thank you, helen L [[alternative HTML
2010 Aug 23
5
trajectory plot (growth curve)
Hi there, I want to make trajectory plots for data as follows: ID time y 1 1 1.4 1 2 2.0 1 3 2.5 2 1.5 2.3 2 4 4.5 2 5.5 1.6 2 6 2.0 ... That is, I will plot a growth curve for each subject ID, with y in the y axis, and time in the x axis. I would like to have all growth curves in the same plot. Is there
2010 Apr 23
4
Intersection for two curves
Does anyone know of a method that I can get the intersection where the red and blue curves meet i.e. the value on the x-axis? x <- 1:10 y <- 10:1 plot(x,y) abline(lm(y~x),col="blue") abline(h=2.5,col="red") Muhammad