similar to: lineplot.CI in "sciplot": option "ci.fun" can't be changed?

Hi to all, Does anybody knows why this is giving an error? data(ToothGrowth) # Two-way design with options bargraph.CI(dose, len, group = supp, data = ToothGrowth, xlab = "Dose", ylab = "Growth", cex.lab = 1.5, x.leg = 1, col = "black", angle = 45, cex.names = 1.25, density = c(0,20), legend = TRUE) Error in dn.call[[1]] :

Hi, I would like to have lineplot.CI and barplot.CI to actually plot confidence intervals , instead of standard error. I understand I have to use the ci.fun option, but I'm not quite sure how. Like this : > qt(0.975,df=n-1)*s/sqrt(n) but how can I apply it to visualize the length of the student's T confidence intervals rather than the stdandard error of the plotted means

Is it possible to add standard error bars to the means on interaction plots? Thanks Murray -- Murray Pung Statistician, Datapharm Australia Pty Ltd 0404 273 283 [[alternative HTML version deleted]]

Hello, When using bargraph.CI in package sciplot can the bars for each group be different colors? How do I select the color for each group? When I use this instead of the default (SD vs SE): bargraph.CI(x.factor = dose, response = len, data = ToothGrowth, ci.fun= function(x) c(mean(x)-sd(x), mean(x) + sd(x)) ) Am I getting 95% CI bars? Thank you kindly, Michael Just

Hi List, I have a problem plotting data using the lineplot.CI command in the sciplot package. I want to plot the data of 2 experimental cases using different lines (traces). Time is on the X-axis. The tricky thing is that the data collection in the second case started later than for the first case. This is to say: the first n data points for the second case are missing. So far so good. However,

Hi there, I am a beginner. I would like to change the error bars in the bargraph.CI function from the default (se) to (sd). The help file says ci.fun= function(x) c(fun(x)-se(x), fun(x)+se(x)) Is there a simple way of telling the function what (x) precisely is - I already define in in the of the bargraph.CI function and assume that is should be able to use that information. cheers, Herwig --

Thank you for your guys reply for my previous question. But I got one more question about the boxplot. With the code in the R-help: boxplot(len ~ dose, data = ToothGrowth, boxwex = 0.25, at = 1:3 - 0.2, subset = supp == "VC", col = "yellow", main = "Guinea Pigs' Tooth Growth", xlab = "Vitamin C dose mg", ylab =

Hi all, I I need to manipulate the x axis in a stripchart. I will use one of the data sets included in R to explain what I need to do. attach(ToothGrowth) stripchart(len[supp=='VC']~dose[supp=='VC'], vertical=TRUE, group.names=c('A','A','A')) stripchart(len[supp=='OJ']~dose[supp=='OJ'], add=TRUE, vertical=TRUE, at=c(1:3)+.1,

Dear List, ? I am creating a boxplot with two subsets, very similar to the example by Roger Bivand at ?boxplot (reproduced below).? I am trying to change the labels on the x-axis to have one number to cover both subsets.? I can do this in other plots by using axis=FALSE followed by a separate axis() command.? I have also tried variations in the names= argument but can't get it to work.?

Dear list, How can I add the mean and standard deviation to each of the boxplots using the example provided in the boxplot function? boxplot(len ~ dose, data = ToothGrowth, boxwex = 0.25, at = 1:3 - 0.2, subset = supp == "VC", col = "yellow", main = "Guinea Pigs' Tooth Growth", xlab = "Vitamin C dose mg",

Hi folks Run; > ToothGrowth > attach(ToothGrowth) > toothgrowth=lm(len~dose) adding abline: > abline(toothgrowth) I got it done adding single abline. How to add more ablines on the same diagram? I found following thread, applying "mapply" command; Plotting multiple ablines http://www.mail-archive.com/r-help@r-project.org/msg51543.html mapply(abline, (converge$kY +

Hi folks, Win7 64bit R 1.12.0 I run following command on R:- > ToothGrowth > attach(ToothGrowth) > plot(dose,len) > matrics=lm(len~dose) > abline(metrics) Error in int_abline(a = a, b = b, h = h, v = v, untf = untf, ...) : plot.new has not been called yet Only a grey diagram is displayed without content > plot(abline(metrics)) Error in int_abline(a = a, b = b, h = h, v

Hi, I want to plot means with standard deviations of Total Nitrogen (TN) across 4 stations (S1-S4) and over 3 years (2007-2009). I want this plot in one panel. I do not want medians (bwplot, boxplot). I have tried a few different packages and it seems that ggplots with plotmeans was the fastest (I am not extremely skilled in writing my own scripts). Unfortunately, there is no grouping

I'm trying to plot a scatterplot of two variables using pch to plot different characters based on a third factor. Here is my example > data("ToothGrowth") > attach(ToothGrowth) > levels(supp) [1] "OJ" "VC" > plot(len ~ dose,pch=as.numeric(supp)) > legend(locator(1),pch=as.numeric(supp),legend=levels(supp)) The command as.numeric(supp) returns 2 2

Dear all How does one resolve the variance between the actual availability of data sets in the default implementation with those mentioned in the documentation? I am unable to attach some of the datasets, even though help() is available for the same datasets. For example, "ToothGrowth" is a dataset that is widely mentioned in the documentation as being part of the base install.

I'm sorry but that is not a working example. A working example needs to create the plots being used. For example, stealing some code from https://rpkgs.datanovia.com/ggpubr/reference/ggarrange.html #================================================================= data <https://rdrr.io/r/utils/data.html>("ToothGrowth")df <- ToothGrowthdf$dose <- as.factor

I'm trying to create a bargraph of means with standard error bars using the function bargraph.CI (in the sciplot package). Like this: bargraph.CI(x.factor, response,data,xlab, ylab, par(family="serif"),font=11) However, an error message comes up when I try to use the par funtion. Does the character font/style need to be changed in a different way for this kind of plot? Or am I

Hi, sorry for bothering your guys. I will trying to make some nice graph using boxplot. when I check the help file of boxplot, there is a sample code as: boxplot(len ~ dose, data = ToothGrowth, add = TRUE, boxwex = 0.25, at = 1:3 + 0.2, subset = supp == "OJ", col = "orange") legend(2, 9, c("Ascorbic acid", "Orange juice"),

This relates to a message from Christophe Pallier to r-help some time ago. Like myself, he finds aggregate very useful, but the interface a little cumbersome. I've implemented a more compact formula interface, found at the bottom of this message: data(ToothGrowth) # I used to aggregate like this: aggregate(list(len=ToothGrowth$len),

Is it possible to format the x axis, so that days are spaced proportionately? i.e. a larger space between 50 & 100, than 0 and 5? Have not had any luck with axis.POSIXct(). Many thanks Murray try <- structure(list(visit = structure(as.integer(c(1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5)), .Label = c("Screening", "0",