similar to: Error with write.table

I just upgraded my version of R from 2.8.1 to 2.9.0. After doing so, I now have problems using the package installer to reinstall all my packages. Some download and install without problems, but for others, I get the spinning pinwheel and after even 10 minutes, nothing is downloaded. R stops responding. At first, I had not deleted the old version of 2.8.1 before installing 2.9.0. However, I

#I wish to find the "next non-NA" value within each row of a data-frame. #e.g. I have a data frame mydata. Rows 1, 2 & 3 have soem NA values. mydata <- data.frame(matrix(seq(20*6), 20, 6)) mydata[1,3:5] <-  NA mydata[2,2:3] <-  NA mydata[2,5] <-  NA mydata[3,6] <-  NA mydata[1:3,] #this loop accomplishes the task; I am tryign toi learn a "better" way for(i

I'm trying to understand how to plot individual growth curve trajectories, with the overall mean trajectory superimposed (preferably in a slightly thicker line, maybe in black) over the individual trajectories. Using the sleepstudy data in lme4, here is the code I have so far: library(lme4) library(lattice) xyplot(Reaction ~ Days, data = sleepstudy, group = Subject, type = 'l')

I have a data set of many rows and many columns in which both the rows and the columns have associated grouping factors. Is there a way to do what 'aggregate' does but in the other dimension? The way I have been doing this is to use 'aggregate' on the data in the usual way and then rotate the result and apply 'aggregate' again. This works but is a little messy and I was

I'm trying to obtain within-group correlations on a subset of variables. I first selected my variables using the following command: mydata$x<-mydata[c("iq","education","achievement")] I'd like to look at correlations among those variables separately for men and women. My gender variable in mydata is coded 1 (women) and 0 (men). I have successfully used

Converting a data.frame with a nested data.frame to a matrix fails: x <- structure(list(a = data.frame(letters)), class = "data.frame", row.names = .set_row_names(26)) as.matrix(x) #> Error in ncol(xj) : object 'xj' not found The offending code is here, in the definition of as.matrix.data.frame (source/base/all.R): for (j in pseq) {

Hi, R users: I want to fit my data into a normal distribution by using the command "fitdistr" in "MASS". I changed my data class from "ts" to "numeric" by >class(mydata)="numeric" but after using "fitdistr", I got the result below >fitdistr(mydata,"normal") mean sd NA NA (NA) (NA) the help doc of

I have a data set similar to the following: Color Score RED 10 RED 13 RED 12 WHITE 22 WHITE 27 WHITE 25 BLUE 18 BLUE 17 BLUE 16 and I am trying to to select just the values of Color that are equal to RED or WHITE, excluding the BLUE. I've tried the following: myComp1<-subset(dataset, Color =="RED" | Color == "WHITE")

Hello, I would like to use mapply to avoid using a loop but for some reason, I can't seem to get it to work. I've included copies of my code below. The first set of code uses a loop (and it works fine), and the second set of code attempts to use mapply but I get a "subscript out of bounds" error. Any guidance would be greatly appreciated. Xj, Yj, and Wj are also lists, and s2,

Is it possible to change the x-axis values in a histogram to reflect binned values? Here are my data: histexample<-c(6,7,7,8,8,8,9,9,9,9,9,10,10,10,10,10,10,10,11,11,11,11,11,11,12,12,12,12,13,13,13,14,14,14,15,16) hist(histexample) Now, I'll bin pairs of adjacent values together (e.g., 5-6, 7-8, 9-10, 11-12, 13-14, 15-16) using the following bins<-c(4.5,6.5,8.5,10.5,12.5,14.5,16.5)

Below is a version of [.data.frame that is faster for subscripting rows of large data frames; it avoids calling duplicated(rows) if there is no need to check for duplicate row names, when: i is logical attr(x, "dup.row.names") is not NULL (S+ compatibility) i is numeric and negative i is strictly increasing "[.data.frame" <- function (x, i, j,

Conversion of a data frame to a matrix using as.matrix() when a column of the data frame is POSIXt and all other columns are numeric has changed in R 1.9.0 from R 1.8.1. The new behavior issues a warning message and converts to a character matrix. In R 1.8.1, such an object was converted to a numeric matrix. Here is an example. #### R 1.9.0 #### > foo <- data.frame(

Is there a way to set up a regression in R that forces two coefficients to be equal but opposite in sign? I'm trying to setup a model where a subject appears in a pair of environments where a measurement X is made. There are a total of 5 environments, one of which is a baseline. But each observation is for a subject in only two of them, and not all subjects will appear in each

I got the error. I haven't been able to get a stand along case so that I can show it here. But could somebody give some clue on what could cause this error? Since I never defined xj[i], I don't understand where this error come from. Error in xj[i] : invalid subscript type 'list'

I am trying to reshape data that are in the wide format into the long format. The design is a repeated-measures design, which combined 3 levels of shape (circle, square, triangle) with 3 levels of color (Blue, Red, Green), for a total of 9 variables. The wide data look like this (sorry I couldn't get the columns to line up quite right: Subject CircleBlue CircleRed CircleGreen SquareBlue

I would like to suggest a modification to the make.names() function. The current implementation has two problems: 1. It doesn't check if a name matches an R keyword (like "function"). 2. The uniqueness algorithm is not invariant to concatenation. In other words, make.names(c("a","a","a"),unique=T) !=

I would like to suggest a modification to the make.names() function. The current implementation has two problems: 1. It doesn't check if a name matches an R keyword (like "function"). 2. The uniqueness algorithm is not invariant to concatenation. In other words, make.names(c("a","a","a"),unique=T) !=

Dear readers of the list, I have a problem a comparison of two data from a vector. The comparison yields FALSE but should be TRUE. I have checked for mode(), length() and attributes(). See the following code (R2.10.0): ----------------------------------------------- # data vector of 66 double data X =

Hi, I need this plot: given: x,y - numerical vectors of length N plot xi vs mean(yj such that |xj - xi|<epsilon) (running mean?) alternatively, discretize X as if for histogram plotting and plot mean y over the center of the histogram group. is there a simple way? thanks! -- Sam Steingold (http://sds.podval.org/) on CentOS release 5.6 (Final) X 11.0.60900031 http://thereligionofpeace.com

I'd like to log all console I/O for an entire session while maintaining normal console I/O. I'm working in Windows98, RGui, R1.1.1. The sink() function is not the answer since it diverts output from the console. In the RFAQ I see references to "...save the contents of the interaction buffer to a file..." and in the R-Help Archive "...just save the console output...". I