similar to: make a grid with longitude, latitude and bathymetry data

hello, I have a problem to open an hdf file. i have downloaded the package 'hdf5' as it was advised on R seek. But when i try to load the file, the R console sends me an eror message: setwd("C:/Documents and Settings/Karine/Bureau/data/") #install.packages('hdf5') library("hdf5") sea_ice <- hdf5load("asi-s6250-20090704-v5i.hdf", load =

Hi everybody. i have 2 datasets : one with a long grid a lat grid and a bathymetry grid the second one only has the long and lat coordinates. So i want to know the bathymetry associated to the second dataset. I thought it was a good idea to do an interpolation between the two datasets. I find a script doing that on matlab but i want to do it on R. Do you how to do it? for ii =

Hi everybody, I have a longitude vector and a latitude one. Associated to these coordinates, i have a matrix with some data at some coordinates but not all. Lon <- seq(136.025,144.975,0.05) Lat <- rev(seq(-66.975,-65.525,0.05)) dim(z) <- c(Lon,Lat) And i have tried to apply to these data a kriging function. But first i need to reshape these 3 variables to have a dataframe

Hi, I have date and time in a format like this: " 2007-02-21 05:19:00". Do you which function i can use to derterminate the difference in time between this value and an other one. For exemple: this one : 2007-02-21 05:19:00 and this one : 2007-02-20 14:21:53 Thanks a lot, Karine H. _________________________________________________________________

hi, I have my data time expressed in character string exple "5:20" (hour:min) and i want to convert these in times recognized by R. I have tried the POSIXct function: balise07$Hour <- as.POSXIct(balise07$Hour) but it didn't work. Do you know why? Do you know how i can convert my string character in a real time? Thanks Karine HEERAH Master 2 mention

Hi, I am using the nls function and it stops because the number of iterations exceeded 50, but i used the nls.control argument to allow for 500 iterations. Do you have any idea why it's not working? fm1 <- nls(npe ~ SSgompertz(npo, Asym, b2, b3), data=f,control=nls.control(maxiter=500)) Thanks for your help, Cheers, Karine.

hi everybody, How can you plot some dates? I mean how can i have the tickmarks with the label of each date on my x axis? The dates i use are in POSIXct format, i don't know if it matters. thanks a lot Karine _________________________________________________________________ Consultez vos emails Orange, Gmail, Yahoo!, Free ... directement depuis HOTMAIL !

I am trying to create a NetCDF file with bathymetry (a matrix) and then to add a grid type (an integer) as variables. This is the relevant part of the code: library(ncdf) wfile="my_file.nc" msv=-10 grdtp=2 # Dimensions d1=dim.def.ncdf("lon","degrees",as.double(lon)) d2=dim.def.ncdf("lat","degrees",as.double(lat)) # Variables

Dear R Users, Using the following R-script I created the first image > require(akima) > require(spatial) > dep <- interp(long, lat, depth, xo=seq(1,990,10), yo=seq(1,990,10), + extrap=FALSE, ncp=0,duplicate = "mean", dupfun = NULL) http://r.789695.n4.nabble.com/file/n3431391/Rpics.bmp Where "long" are x-coordinates between 1 and 1000, "lat" are

Hi, I am using the nls function and it stops because the number of iterations exceeded 50, but i used the nls.control argument to allow for 500 iterations. Do you have any idea why it's not working? fm1 <- nls(npe ~ SSgompertz(npo, Asym, b2, b3), data=f,control=nls.control(maxiter=500)) Error in nls(y ~ exp(-b2 * b3^x), data = xy, algorithm = "plinear", start = c(b2 =

Hi everybody, I am using the contour function to draw isobares. And i would like to to bold contours for an interval of 500m and weak contour for an interval of 100m. Can someone help me with this? Thanks a lot Karine _________________________________________________________________ [[elided Hotmail spam]] [[alternative HTML version deleted]]

Hi Team, Need your guidance in building SPDF objects from Latitude, Longitude Information available. I am using package "plotGoogleMaps" which is really awesome but it requires SPDF objects to build the maps. I have a data frame which have Latitude and Longitude information and wanted to convert it in SPDF for making maps. Please help me to find suitable package or function to convert

Dear R-helpers, I get GPS readings with bug counts (bugs meaning insects in this case) made along rows in crop fields and use these to make maps of bug distribution. The GPS readings are not quite accurate enough for my purpose, so since I know what row each reading is made in, I adjust the latitudinal coordinate using: grd<-lm(lat~lon+Row,data)

Good day to you all, I have lightning data containing date, time, latitude and longitude. I hope that distribution of latitude and longitude will give number of lightning occurrence in a region. I have used factor function to sum up the number of events on latitude and longitude axis and saved as x and y. But when I tried to plot the two, I had and error message ( Error in image.default(x, y, z) :

Hi all, I would like to know a way of calculating the distance between 2 points when I already have the longitude and latitude of the points. For example : Point 1 : 52? 9'54.00"N 4?25'8.40"E Point 2 : 52?27'46.80"N 4?33'18.00"E Distance between point 1 and point in km .... Is there any functions already available for this ? Any help will be much

Hi All, I have a data frame with three columns i.e., pc, lat, lon. The pc column is populated with list of postcodes, and I want to execute R command that can get me the lat and lon for the every item in the pc column and populate the respective lat and lon columns. Is there any package that could be used? Any help will be really appreciated. Many Thanks and Kind Regards -- Muhammad

Hi All, I''m having a problem with Rails truncating latitude and longitude values. In my database (mySQL) table, my lat/lng columns are defined as Decimal(25,20), but I get different precision values depending on what I do. If I post, via XML, a value of 37.436490000000006 to my controller, what gets inserted into the db table is 37.43648999999999900000. Then, when I fetch the record in a

I am trying to set up a Grass project and need to set up the region so that I can view the map. I can look at a map and find the lat/lon, but the map projection is in UTM NAD38 WGS84 and I need to set the eastings and northings. Is there a package that will help me calculate this in R. thanks -- Stephen Sefick Let's not spend our time and resources thinking about things that are so little

I see several mapping libraries but cannot find how to do a simple task. Starting with a vector of zip codes (in the United States and in Canada) I would like to automatically lookup the corresponding coordinates. Can you suggest a package and function that I should turn to? I would also like to automatically pull in the altitude, and some climate data. -- Farrel Buchinsky [[alternative HTML

I have a dataset giving traffic between pairs of ports, and the lat/lon of each port, roughly as follows: sample data as follows > df2VisitTrips[1:4,] Origin Destination NumberOfTrips OriginLatitude OriginLongitude DestinationLatitude DestinationLongitude 1 P1 P16 1 39.45965 -80.15633 40.76111 -79.54583 2 P1 P3