similar to: newb question: chron and hist()

I understand this isn't a r specific question. I'm switching departments to work with the analytics team at my company as a "service" side manager to better incorporate the analytics process into product design / production. We're an online gaming company. As I'm going through tools like R, rapidminer, tableau, I was also thinking that I should get some formal training

I'm just beginning R, with book Using R for Introductory Statistics, and one of the early questions has me baffled. The question is, create the sequence: 1,2,3,4,5,4,3,2,1 using seq() and rep(). Now, as a programmer, I am punching myself to not be able to figure it out.. I mean, as simple as a for loop, but using seq, I am stumped. I would think c(1:5, 4:1) would be the brute force method

Hi list, this is my second try for first post on this list (I tried to post via email and nothing appeared in my email-inbox, so now I try to use the nabble-web-interface) - I hope that you will only have to read one post in your inbox! Okay, my question ... I was able to plot a histogram and add the density()-line to this plot. I was able to plot a cumulative form of this histogram. Yet, I was

Hello dear useRs and wizaRds, I encountered the following problem using the hist() method for the 'times' classes from package 'chron'. You should be able to recreate it using the code: library(chron) # pasted from chron help file (?chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92")) class(dts)

Hi R, Does 'savePlot' will not work in the batch mode? I get the below error: > x=c(1,2,3,4,5,6,7) > hist(x) > savePlot("D:\\Test\\histo",type="jpeg") Error in savePlot("D:\\Test\\histo", type = "jpeg") : can only copy from 'windows' devices Execution halted The same works in the interactive mode. What

Hi r-users,   I would like to overlap a smooth line on the histogram.  I tried using spline but it does not work. sq     <- seq(0,900,by=50) sq.50  <- as.character(sq) datobs <- sum_pos ## first, plot histogram histo <- hist(datobs,breaks=sq,freq=F) ## extract counts from histogram and calculate the probability in ## each specified interval. Also check the length of the interval is

Dear all, May be question seems trivial for most of the R users, but really at least for me, this comes out to be very problematic. Suppose I have the following data: > r [1] -0.0008179960 -0.0277968529 -0.0105731583 -0.0254050262 0.0321847131 0.0328170674 [7] 0.0431894392 -0.0217614918 -0.0218366946 0.0048939739 -0.0012212499 0.0032533579 [13] -0.0081533269 -0.0098725606

Hi all, I am generating histograms with the following R script : #!/usr/bin/Rscript out_file = "histo.png" png(out_file) scan("values.csv") -> myvalues hist(myvalues, breaks = 50) dev.off() print(paste("Plot was saved in:", getwd())) I want the histogram to have a larger number of breaks, but a smaller break width, the idea is to make it appear smoother

> So far, I've noticed that --dtx alone doesn't seem to do anything, but --vad does > and the combination --dtx with --vad does more. The lone exception is for wide > and ultra-wide coding at quality 0, --vad, alone, makes the file slightly larger. > At all other sized the ordering is always: plain==--dtx, then --vad, then --vad > with --dtx. All you say look normal to me.

Hi there I have a problem with using Sweave in combination with the option driver = cacheSweave. Whichever code I try to run - when it comes to converting the tex file into pdf it comes up with the same errors (\csname \endcsname errors). Does anybody have an idea what it going wrong? > Sweave("pgfSweave-example.Rnw",driver = cacheSweaveDriver) Writing to file

> All you say look normal to me. Okay, clarification requires less code to be written than a bug. :) > > Does that makes sense? I would have thought that --dtx alone would have = > doen it, > > but maybe it needs perfect digital silence to work? Or only uses the voi= > ce activation > > to know when there's silence? > > DTX requires the VAD to know when

Hallo, ich schreibe einfach mal deutsch, und hoffe dass Du das auch verstehst (if not write me back in English). OS X 10.3.9 Ich habe R 2.1.0 installiert, und das Programm hat auch funktioniert. Will wenig sp??ter wieder mit R arbeiten, es l??sst sich aber nicht mehr starten. "Das Programm R wurde unerwartet beendet", w??hrend ich versuche es durch Doppelklicken auf das R.app-symbol

> My question is not about statistics but more obviously about an R command. > I would like to plot an histogram with a logarithmic scale. I have > searched through R documentation and have read about the "log" option. > What matters is that it does not work with the hist() function. I'm > working with R version 1.2.3 . Maybe the problem has been solved in R 1.3 > .

I'm running a: for band in n w u do for quality in 0 1 2 3 4 5 6 7 8 9 10 do for complexity in 3 do for vad in "" "--vad" do for dtx in "" "--dtx" do echo speexenc -${band} --quality ${quality} --comp ${complexity} ${vad} ${dtx} input.${band}.wav

Dear guRus, I would like to loop over a medium amount of Sweave code, including both R and LaTeX chunks. Is there any way to do so? As an illustration, can I create a .tex file like this using a loop within a .Rnw file, where the "1,2,3" comes from some iteration variable in R? ################################################ \documentclass{article} \usepackage{Sweave} \begin{document}

Hi folks, My wife and I are taking a long weekend to celibrate our anniversary. I won't be around again until Wednesday to answer email or do anything else on Vorbis. Yeah, I know, I usually answer my email once a month anyway (so likely no one would notice me being gone), but just so folks know if anything really juicy comes up :-) I'll be merging my latest branch with mainline

> >>>>> "PD" == Peter Dalgaard BSA <p.dalgaard at biostat.ku.dk> writes: > > PD> "Venables, Bill (CMIS, Cleveland)" <Bill.Venables at cmis.CSIRO.AU> > PD> writes: > >> The fact that every elementary book on statistics does it this way > >> does not make it correct. To be helpful, a histogram really