Displaying 20 results from an estimated 400 matches similar to: "lm on group"
2006 Feb 09
1
glmm.admb - bug and possible solution??
Dear Dr Skaug and R users,
just discovered glmm.admb in R, and it seems a very useful tool.
However, I ran into a problem when I compare two models:
m1<-glmm.admb(survival~light*species*damage, random=~1, group="table",
data=bm, family="binomial", link="logit")
m1.1<-glmm.admb(survival~(light+species+damage)^2, random=~1,
group="table", data=bm,
2006 Feb 20
1
var-covar matrices comparison:
Hi,
Using package gclus in R, I have created some graphs that show the
trends within subgroups of data and correlations among 9 variables (v1-v9).
Being interested for more details on these data I have produced also the
var-covar matrices.
Question: From a pair of two subsets of data (with 9 variables each, I
have two var-covar matrices for each subgroup, that differ for a
treatment on one
2011 May 12
1
(no subject)
#subject: type III sum of squares - anova() Anova() AnovaM()
#R-version: 2.12.2
#Hello everyone,
#I am currently evaluating experimental data of a two factor
experiment. to illustrate de my problem I will use following #dummy
dataset: Factor "T1" has 3 levels ("A","B","C") and factor "T2" has 2
levels "E" and "F". The
2011 Apr 13
4
is this an ANOVA ?
Hi all,
I have a very easy questions (I hope). I had measure a property of plants, growing in three different substrates (A, B and C). The rest of the conditions remained constant. There was very high variation on the results.
I want to do address, whether there is any difference in the response (my measurement) from substrate to substrate?
2002 Nov 27
2
Error message: missing value where logical needed
Dear all,
I often import data sets from other programs that contain user defined
missing values. As an example consider a variable MXPLOCO with a user
defined missing value of as -9.
> summary(MXPLOCO)
Min. 1st Qu. Median Mean 3rd Qu. Max. NA's
-9.000 4.750 5.000 5.349 6.000 8.500 2.000
The following command successfully converts the value -9 to NA. However,
2007 Nov 05
1
Making the video plugin + patched MPlayer work with other backends
Hi,
I'm wondering how I can make my patched up mplayer work with other
MPlayer frontends, such as mplayer-plugin, GMPlayer, SMPlayer and
KMPlayer. When I play a video using mplayer normally with:
mplayer video.ext,
It detects the compiz video output and works fine, however when it is
called from other players (AFAIK, it just creates a window then asks
mplayer to display in it) with mplayer
2017 Oct 28
2
HELP relevel INTERCEPT-COMPARISONS
Dear colleagues,
How can I do to "relevel" the intercept?
I need that the treatment "Db" be the intercept, and have p-values for the comparisons with the others treatments.
I used the function "relevel" but it did not work out to have what I want.
Thanks for your help,
Xavier
T1 <- read.table(file.choose(), h=T)
> head(T1)
treatment replicate Time
2012 Aug 07
1
lm with a single X and step with several Xi-s, beta coef. quite different:
Hi, (R version 2.15.0)
I am running a pgm with 1 response (earlier standardized Y) and 44
independent vars (Xi) from the same data =a2:
When I run the 'lm' function on single Xi at a time, the beta
coefficient for let's say X1 is = -0.08 (se=0.03256)
But when I run the same Y with 44 Xi-s with the 'step' function (because
I left direction parameter empty, I assume a backward
2005 May 27
1
logistic regression
Hi
I am working on corpora of automatically recognized utterances, looking
for features that predict error in the hypothesis the recognizer is
proposing.
I am using the glm functions to do logistic regression. I do this type
of thing:
* logistic.model = glm(formula = similarity ~., family = binomial,
data = data)
and end up with a model:
> summary(logistic.model)
Call:
2011 Aug 26
1
matrix bands
Dear R developers,
I was looking for a function analogous to base::diag() for getting and
setting bands of a matrix. The closest I could find was Matrix::band(),
but this was not exactly what I wanted for two reasons. Firstly,
Matrix::band() returns a matrix rather than just the specified band.
Secondly, Matrix::band() cannot be used for setting the values for a
matrix band.
Setting or
2009 Apr 01
1
Noobie ANOVA intercept question
Dear R list,
I've been attempting to interpret the results from a three-way ANOVA. I
think I understand contrasts and the R defaults for these (treatment
contrasts). My question is: what is the intercept in this test? As far as I
can tell, its NOT the expected value of a point that belongs to the first
level of all three explanatory factors (because there is only one point that
satisfies these
2017 Jun 24
3
Help please
Hello,
I need some help on a regression I am running please. I am running a multiple regression in R and I am getting weird outputs and would like your help in resolving it.
This is the code I run:
Reg = lm (Final$Y.t.-Final$Y.t.1. ~ Final$ Y.t.1. + Final$Cor + Final$Gov+ Final$Inv+ Final$TrOp + Final$Pop+ Final$Sch , data = Final)
summary(Reg)
And the output I get is pasted below. As
2013 Apr 17
1
mgcv: how select significant predictor vars when using gam(...select=TRUE) using automatic optimization
I have 11 possible predictor variables and use them to model quite a few
target variables.
In search for a consistent manner and possibly non-manual manner to identify
the significant predictor vars out of the eleven I thought the option
"select=T" might do.
Example: (here only 4 pedictors)
first is vanilla with "select=F"
>
2004 Aug 16
2
using nls to fit a four parameter logistic model
Shalini Raghavan
3M Pharmaceuticals Research
Building 270-03-A-10, 3M Center
St. Paul, MN 55144
E-mail: sraghavan at mmm.com
Tel: 651-736-2575
Fax: 651-733-5096
----- Forwarded by Shalini Raghavan/US-Corporate/3M/US on 08/16/2004 11:25
AM -----
Shalini
2007 Mar 01
3
Simplest question ever...
Let's say i have
a = c(1, 4, 5)
b = c(2, 6, 7)
and i have matrix m, what's an efficient way of access
m[1, 2], m[4, 6], m[5, 7]
like of course m[a, b] = is not going to do, but what's an expression that
will allow me to have that list?
Thanks!
--
View this message in context: http://www.nabble.com/Simplest-question-ever...-tf3329894.html#a9258932
Sent from the R help mailing list
2013 Apr 25
0
tables: proper use of Hline() in tabular()
Dear all,
I am unable to understand how Hline() works in tabular(). I've read
the vignette and the help page, and here this example compiles
perfectly fine:
latex( tabular( Species + Hline() + 1
~ Heading()*mean*All(iris), data=iris) )
However, if I try it on my own data it fails. Consider this:
set.seed(1)
Xa <- data.frame(p=rep(c("First group","Second
2013 Jun 05
2
combining two different matrizes
Hello together,
this is ma first post, so please aplogize me if post this in the wrong
section.
I have problem concerning ma two matrizes.
After a regressione and so on, I got two matrizes
Matrixres contains the results of ma calculation.
Matrixr contains my detiene, which where Aldo used for the regression.
Please ser the following code:
#Datei einlesen
residual =
2008 Aug 01
1
importing explicitly declared missing values in read.spss (foreign)
There is a problem when importing an spss-file containing explicitly declared
missing values in R using the read.spss function from the foreign package.
I'm not sure these problems are the same in every version of spss, I am
using the latest version 16.0.2.
I included http://www.nabble.com/file/p18776776/missingdata.sav
missingdata.sav and
2013 Apr 11
2
Read the data from a text file and reshape the data
I have a data set for different time intervals. The data has three comment
lines before data for each time interval. For each time interval there are
500 data points. I want to change the dataset such that I have the following
format:
t1 t2 t3 ................
0.00208 0.00417 0.00625 .................
a1 a2 a3 ...................
2007 Aug 28
2
Efficient way to parse string and construct data.frame
Hi all,
I have this list of strings
[1] "1 ,2 ,3" "4 ,5 ,6"
Is there an efficient way to convert it to data.frame:
V1 V2 V3
1 1 2 3
2 4 5 6
Like I can use strsplit to get to a list of split strings.. and then use say
a = strsplit(mylist, ",")
data.frame(V1 = lapply(a, function(x){x[1]}), V2 = lapply(a,
function(x){x[2]}),.....)
but i'm