similar to: Error: object of type 'closure' is not subsettable

Displaying 20 results from an estimated 10000 matches similar to: "Error: object of type 'closure' is not subsettable"

2009 Dec 20
3
Object of type 'closure' not subsettable
Hi all, How can I overcome the error "object of type 'closure' not subsettable" I ran the following script seq <- paste(seq(1914, 1916, by=1), "*.y", sep=".") # make sequence c <- 3 # total number of files d2 <- file # creates dummy file # Input sequence in loop for (i in 1:3){ list <- list.files("~/ukcp09/txt/x.djf", seq[[i]]) file
2011 Aug 18
3
Error message: object of type 'closure' is not subsettable
Dear R-users I need to calibrate kappa, rho, eta, theta, v0 in the following code, see below. However when I run it, I get: y <- function(kappahat, rhohat, etahat, thetahat, v0hat) {sum(difference(k, t, S0, X, r, implvol, q, kappahat, rhohat, etahat, thetahat, v0hat)^2)} > nlminb(start=list(kappa, rho, eta, theta, v0), objective = y, lower =lb, > upper =ub) Error in dots[[1L]][[1L]] :
2013 Mar 14
1
error: object of type 'closure' is not subsettable
Hi all, when i run this script: >read.table("Angelika.txt",header=T,sep="\t") >mytable=read.table("Angelika.txt",header=T,sep="\t") >for ( dye in c("A","B","C","F","G","K","L","M")) + { + for (cond in 1:8) + { + measurement =
2010 Mar 19
1
Sweave and " object of type 'closure' is not subsettable" error
Hello folks: I have a data frame which includes two numeric vectors: "Pa1" and "Ingr" (which represents income).  I run the following code on the R console: ingreso <- factor(ifelse(Ingr<=3000,"bajo","alto")) tapply(Pa1,ingreso,summary) boxplot(Pa1~ingreso) and it works fine.  However, when I "Sweave" through an rnw file containing that
2012 Nov 27
1
Problem in Starting R Server - object of type 'closure' is not subsettable
Hi All, I am trying to start R Server to run some Java Script in my local machine using the library, 'Rook'. I use Windows 7. And my codes are following, > library(Rook) > myD3dir <- 'D:\\STUDIES\\Java script\\d3-master' > s <- Rhttpd$new > s$start(quiet=TRUE) and i get the following error for the above line, Error in s$start : object of type
2012 Jul 26
1
loop for, error: obj type 'closure' not subsetable
Hi everyone, I've got the following problem: I've got a matrix [1000,2] and two vectors. In very matrix row there is two coefficients b0 and b1. The vectors are two variables x and y. I want to do a loop to take b0 and b1 and with x and y calculate the residual of a linear model and calculate the second order coefficient of autocorrelation. What I did is : rho<-function(mat, x,y){
2011 Apr 11
0
Package fgui returns error: Object of type closure is not subsettable
Hello All, I have written three functions. First: To input user specified SAS dataset and plot the boxplots of relevant variables. Second: Extract the number of hours, minutes etc. from a variable describing a time-point using regular expressions. E.g. 'Per1, Day 2, 24 Hour' would be separated into three columns, Per (value 1), Day (value 2) and Hour (value 24) Third:
2012 Feb 15
5
Abrir multiples archivos
Hola, Alguien podría ayudarme en la siguiente cuestión: Trato de abrir múltiples archivos ncDF para dejarlos disponibles para trabajar luego con ellos. Intento hacerlo con un blucle pero no consigo lo que quiero. El código es el siguiente: setwd("/Users/jaime/Desktop/2008") a<-list.files() a library(ncdf) for (i in 1:length(a)) {
2012 Oct 16
3
Excluding all teh columns from a data frame if the standard deviation of that column is zero(0).
Hi All, I have a data frame where nearly 10K columns of data, where most of them have standard deviation( of all rows) as zero. I want to exclude all the columns from the data frame and proceed to further processing. I tried like blow. *data <- read.csv("data.CSV", header=T) for(i in 2:ncol(data)) if(sd(data[,i])==0){ df[,i] <-NULL } * where I have the data columns from
2010 Oct 03
2
R data opening problem
Dear Sir/Madam, I have just installed R for Windows. I am trying to open a stata file and I have a problem. I have used the following commands: > install.packages("foreign") > library(foreign) > data.name <- read.dta(file.choose()) # then I choose a kelleya.dta file and click on open and then I use the following command: > summary(kelleya) Error in object[[i]]
2010 Jan 17
2
Strange results from Windows 7
Hello, I am a newbie. I can run the following code stored in "test.txt" without error using my XP machine: x <- scan("C:\\Rwork\\A.txt") x10 = filter(x, rep(1/10,10), sides=1) x x10 for(i in 10:length(x)){ if (x[i] > x10[i]) diff[i]="b" else diff[i]="s" } However, if I run it in another PC that uses Windows 7, the following error occurs:
2008 Mar 09
2
p-adjust using Benjamn and Hochberg
Hello, I am trying to use the p.adjust function for multiple testing. here is what i have 9997 201674_s_at 0.327547396 9998 221013_s_at 0.834211067 9999 221685_s_at 0.185099475 I import them from excel have have the gene symbol as well as the pvalue here is the issue > pa<-p.adjust(pt,method="BH") Error in p[nna] : object is not
2011 Mar 04
2
Reading in and manipulating multiple data sets from the same input file
Hi, I am attempting to write code which will read in my data which is of this form: X1 Y1 X2 Y2 .... Xn Yn 0 0 0 0 0 0 1 0 1 255 1 0 2 255 2 0 2 255 3 0 3 0
2019 Mar 26
3
bugs in head() and tail()
(Using R 3.5.3). I found bugs in head() and tail(). The following works: > f = function () 1 > head (f) 1 function () 2 1 However, the following does not: > class (f) = "f" > head (f) Error in x[seq_len(n)] : object of type 'closure' is not subsettable [[alternative HTML version deleted]]
2012 Aug 15
3
Basic question -loading data
Hi all, New user here - I include the following command in the prompt read.csv("document.csv", header = TRUE ) and the output shows up. But when I include the following command summary(data) I get the following message "Error in object[[i]] : object of type 'closure' is not subsettable" Can someone please advise why R is not reading my data? Thanks
2017 Jul 24
5
Ifelse statements and combining columns
Hi everyone, I'm having some trouble with my ifelse statements. I'm trying to put 12 conditions within 3 groups. Here is the code I have so far: dat$cond <- ifelse(test = dat$cond == "cond1" | dat$cond == "cond2" | dat$cond == "cond3" dat$cond == "cond4" yes = "Uniform" no = ifelse(test =
2010 Feb 26
2
Problem accessing sub-methods of functions stored in a vector
Hi folks, I am having trouble accessing sub-functions when the main function is stored in an array. For example, the following test code works fine: fcns = c(abs, sqrt) fcns[[1]](-2) fcns[[2]](2) However, when I try to access sub-functions declared within list() in a function, this only works directly. When I try to access these within an array only the first declared sub-function is run.
2008 Jan 03
1
question from Blue book
Hi R people: On page 235 of the Blue Book (Becker, Chambers, and Wilks), there is a "compose2" function. compose2 <- function(f,g) { gg <- substitute(g1(x)) print(gg) gg[[1]] <- g ff <- substitute(f1(y)) print(ff) ff[[1]] <- f ff[[2]] <- gg print(ff) fun <- function(x){ NULL } fun[[2]] <- ff fun } However, when I run this function using sum
2011 Dec 06
2
Why can't I figure this out? :S
Hi, so I don't speak computer and I have no idea what this code is telling the program to do, but I apparently need to be able to find and isolate influencial observations. Problem, I have no idea what the error means and where it may be from in the code. error I get is below the code { ## OLS results NameC<- lm(gpanew~female+female:lastinit+agenew+canadian+mom_ed+yearstudy) ## default:
2011 Jul 12
3
Help in error removal
Dear all, I am new to programming in R. I deal with microarray data,which is a data frame object type. I need to carry out a few statistical procedures on this, one of them being the pearson corelation. I need to do this between each row which is a gene. So the desired result is a square matrix with the pearson corelation value between each row. So the first column would be (1,1)=0,(1,2),(1,3)