Displaying 20 results from an estimated 10000 matches similar to: "Error: object of type 'closure' is not subsettable"
2009 Dec 20
3
Object of type 'closure' not subsettable
Hi all,
How can I overcome the error "object of type 'closure' not subsettable"
I ran the following script
seq <- paste(seq(1914, 1916, by=1), "*.y", sep=".") # make sequence
c <- 3 # total number of files
d2 <- file # creates dummy file
# Input sequence in loop
for (i in 1:3){
list <- list.files("~/ukcp09/txt/x.djf", seq[[i]])
file
2011 Aug 18
3
Error message: object of type 'closure' is not subsettable
Dear R-users
I need to calibrate kappa, rho, eta, theta, v0 in the following code, see
below. However when I run it, I get:
y <- function(kappahat, rhohat, etahat, thetahat, v0hat) {sum(difference(k,
t, S0, X, r, implvol, q, kappahat, rhohat, etahat, thetahat, v0hat)^2)}
> nlminb(start=list(kappa, rho, eta, theta, v0), objective = y, lower =lb,
> upper =ub)
Error in dots[[1L]][[1L]] :
2013 Mar 14
1
error: object of type 'closure' is not subsettable
Hi all,
when i run this script:
>read.table("Angelika.txt",header=T,sep="\t")
>mytable=read.table("Angelika.txt",header=T,sep="\t")
>for ( dye in c("A","B","C","F","G","K","L","M"))
+ {
+ for (cond in 1:8)
+ {
+ measurement =
2010 Mar 19
1
Sweave and " object of type 'closure' is not subsettable" error
Hello folks:
I have a data frame which includes two numeric vectors: "Pa1" and "Ingr" (which represents income). I run the following code on the R console:
ingreso <- factor(ifelse(Ingr<=3000,"bajo","alto"))
tapply(Pa1,ingreso,summary)
boxplot(Pa1~ingreso)
and it works fine. However, when I "Sweave" through an rnw file containing that
2012 Nov 27
1
Problem in Starting R Server - object of type 'closure' is not subsettable
Hi All,
I am trying to start R Server to run some Java Script in my local machine
using the library, 'Rook'. I use Windows 7.
And my codes are following,
> library(Rook)
> myD3dir <- 'D:\\STUDIES\\Java script\\d3-master'
> s <- Rhttpd$new
> s$start(quiet=TRUE)
and i get the following error for the above line,
Error in s$start : object of type
2012 Jul 26
1
loop for, error: obj type 'closure' not subsetable
Hi everyone,
I've got the following problem:
I've got a matrix [1000,2] and two vectors. In very matrix row there is two
coefficients b0 and b1. The vectors are two variables x and y. I want to do
a loop to take b0 and b1 and with x and y calculate the residual of a linear
model and calculate the second order coefficient of autocorrelation. What I
did is :
rho<-function(mat, x,y){
2011 Apr 11
0
Package fgui returns error: Object of type closure is not subsettable
Hello All,
I have written three functions.
First: To input user specified SAS dataset and plot the boxplots of relevant
variables.
Second: Extract the number of hours, minutes etc. from a variable describing
a time-point using regular expressions.
E.g. 'Per1, Day 2, 24 Hour' would be separated into three
columns, Per (value 1), Day (value 2) and Hour (value 24)
Third:
2012 Feb 15
5
Abrir multiples archivos
Hola,
Alguien podría ayudarme en la siguiente cuestión:
Trato de abrir múltiples archivos ncDF para dejarlos disponibles para
trabajar luego con ellos. Intento hacerlo con un blucle pero no
consigo lo que quiero. El código es el siguiente:
setwd("/Users/jaime/Desktop/2008")
a<-list.files()
a
library(ncdf)
for (i in 1:length(a)) {
2012 Oct 16
3
Excluding all teh columns from a data frame if the standard deviation of that column is zero(0).
Hi All,
I have a data frame where nearly 10K columns of data, where most of them
have standard deviation( of all rows) as zero.
I want to exclude all the columns from the data frame and proceed to further
processing.
I tried like blow.
*data <- read.csv("data.CSV", header=T)
for(i in 2:ncol(data))
if(sd(data[,i])==0){
df[,i] <-NULL
}
*
where I have the data columns from
2010 Oct 03
2
R data opening problem
Dear Sir/Madam,
I have just installed R for Windows. I am trying to open a stata file and I have
a problem. I have used the following commands:
> install.packages("foreign")
> library(foreign)
> data.name <- read.dta(file.choose())
# then I choose a kelleya.dta file and click on open and then I use the
following command:
> summary(kelleya)
Error in object[[i]]
2010 Jan 17
2
Strange results from Windows 7
Hello,
I am a newbie.
I can run the following code stored in "test.txt" without error using my
XP machine:
x <- scan("C:\\Rwork\\A.txt")
x10 = filter(x, rep(1/10,10), sides=1)
x
x10
for(i in 10:length(x)){
if (x[i] > x10[i]) diff[i]="b" else diff[i]="s"
}
However, if I run it in another PC that uses Windows 7, the following
error occurs:
2008 Mar 09
2
p-adjust using Benjamn and Hochberg
Hello,
I am trying to use the p.adjust function for multiple testing.
here is what i have
9997 201674_s_at 0.327547396
9998 221013_s_at 0.834211067
9999 221685_s_at 0.185099475
I import them from excel have have the gene symbol as well as the pvalue
here is the issue
> pa<-p.adjust(pt,method="BH")
Error in p[nna] : object is not
2011 Mar 04
2
Reading in and manipulating multiple data sets from the same input file
Hi,
I am attempting to write code which will read in my data which is of this
form:
X1 Y1 X2 Y2 .... Xn Yn
0 0 0 0 0 0
1 0 1 255 1 0
2 255 2 0 2 255
3 0 3 0
2019 Mar 26
3
bugs in head() and tail()
(Using R 3.5.3).
I found bugs in head() and tail().
The following works:
> f = function () 1
> head (f)
1 function ()
2 1
However, the following does not:
> class (f) = "f"
> head (f)
Error in x[seq_len(n)] : object of type 'closure' is not subsettable
[[alternative HTML version deleted]]
2012 Aug 15
3
Basic question -loading data
Hi all,
New user here - I include the following command in the prompt
read.csv("document.csv", header = TRUE )
and the output shows up.
But when I include the following command
summary(data)
I get the following message "Error in object[[i]] : object of type 'closure' is not subsettable"
Can someone please advise why R is not reading my data?
Thanks
2017 Jul 24
5
Ifelse statements and combining columns
Hi everyone,
I'm having some trouble with my ifelse statements.
I'm trying to put 12 conditions within 3 groups. Here is the code I have so
far:
dat$cond <- ifelse(test = dat$cond == "cond1" | dat$cond == "cond2" |
dat$cond == "cond3" dat$cond == "cond4"
yes = "Uniform"
no = ifelse(test =
2010 Feb 26
2
Problem accessing sub-methods of functions stored in a vector
Hi folks,
I am having trouble accessing sub-functions when the main function is
stored in an array. For example, the following test code works fine:
fcns = c(abs, sqrt)
fcns[[1]](-2)
fcns[[2]](2)
However, when I try to access sub-functions declared within list() in a
function, this only works directly. When I try to access these within an
array only the first declared sub-function is run.
2008 Jan 03
1
question from Blue book
Hi R people:
On page 235 of the Blue Book (Becker, Chambers, and Wilks), there is a "compose2" function.
compose2 <- function(f,g) {
gg <- substitute(g1(x))
print(gg)
gg[[1]] <- g
ff <- substitute(f1(y))
print(ff)
ff[[1]] <- f
ff[[2]] <- gg
print(ff)
fun <- function(x){ NULL }
fun[[2]] <- ff
fun
}
However, when I run this function using sum
2011 Dec 06
2
Why can't I figure this out? :S
Hi, so I don't speak computer and I have no idea what this code is telling
the program to do, but I apparently need to be able to find and isolate
influencial observations. Problem, I have no idea what the error means and
where it may be from in the code.
error I get is below the code
{
## OLS results
NameC<- lm(gpanew~female+female:lastinit+agenew+canadian+mom_ed+yearstudy)
## default:
2011 Jul 12
3
Help in error removal
Dear all,
I am new to programming in R.
I deal with microarray data,which is a data frame object type. I need to carry out a few statistical procedures on this, one of them being the pearson corelation. I need to do this between each row which is a gene. So the desired result is a square matrix with the pearson corelation value between each row. So the first column would be (1,1)=0,(1,2),(1,3)