Displaying 20 results from an estimated 3000 matches similar to: "ADF test : how to deal with the missing values ?"
2007 Aug 16
2
ADF test
Hi all,
Hope you people do not feel irritated for repeatedly sending mail on Time series.
Here I got another problem on the same, and hope I would get some answer from you.
I have following dataset:
data[,1]
[1] 4.96 4.95 4.96 4.96 4.97 4.97 4.97 4.97 4.97 4.98 4.98 4.98 4.98 4.98 4.99 4.99 5.00 5.01
[19] 5.01 5.00 5.01 5.01 5.01 5.01 5.02 5.01 5.02 5.02 5.03 5.03 5.03
2013 Apr 30
1
ADF test --time series
Hi all,
I was running the adf test in R.
CODE 1:
adf.test(data$LOSS)
Augmented Dickey-Fuller Test
data: data$LOSS
Dickey-Fuller = -1.9864, Lag order = 2, p-value = 0.5775
alternative hypothesis: stationary
CODE 2:
adf.test(diff(diff(data$LOSS)))
Augmented Dickey-Fuller Test
data: diff(diff(data$LOSS))
Dickey-Fuller = -6.9287, Lag order = 2, p-value = 0.01
alternative
2013 Mar 22
4
error while extracting the p-value from adf.test
Hello all,
I tried to extract the p-value from adf.test in tseries; however, I got the error message such as
> ht=adf.test(list.var$aa)
> ht$p-value
Error in ht$p - value : non-numeric argument to binary operator
> ht
Augmented Dickey-Fuller Test
data: list.var$aa
Dickey-Fuller = -2.3147, Lag order = 4, p-value = 0.4461
alternative hypothesis: stationary
> ht$data
[1]
2010 Oct 29
3
Dickey Fuller Test
Dear Users, please help with the following DF test:
=====
library(tseries)
library(timeSeries)
Y=c(3519,3803,4332,4251,4661,4811,4448,4451,4343,4067,4001,3934,3652,3768
,4082,4101,4628,4898,4476,4728,4458,4004,4095,4056,3641,3966,4417,4367
,4821,5190,4638,4904,4528,4383,4339,4327,3856,4072,4563,4561,4984,5316
,4843,5383,4889,4681,4466,4463,4217,4322,4779,4988,5383,5591,5322,5404
2013 Jun 23
1
Scaling Statistical
Short question: Is it possible to use statistical tests, like the Augmented
Dickey-Fuller test, in functions with for-loops? If not, are there any
alternative ways to scale measures?
Detailed explanation: I am working with time-series, and I want to flag
curves that are not stationary and which display pulses, trends, or level
shifts.
>df
DATE ID VALUE2012-03-06 1
2007 Dec 08
2
time series tests
Hi all,
Can anyone clear my doubts about what conclusions to take with the following what puts of some time series tests:
> adf.test(melbmax)
Augmented Dickey-Fuller Test
data: melbmax
Dickey-Fuller = -5.4075, Lag order = 15, p-value = 0.01
alternative hypothesis: stationary
Warning message:
p-value smaller than printed p-value in: adf.test(melbmax)
2004 Oct 13
4
incomplete function output
Dear R users,
I have a function (below) which encompasses several tests.
However, when I run it, only the output of the last test is
displayed. How can I ensure that the function root(var)
will run and display the output from all tests, and not
just the last one?
Thank you,
b.
root <- function(var)
{
#---Phillips-Perron
PP.test(var, lshort = TRUE)
PP.test(var, lshort = FALSE)
2008 Dec 08
1
About adf.test
Dear sir,
I am a new user of R statistical package. I want to perform
adf.test(augmented dickey fuller test), which packages I need to install in
order to perform it. I am getting following message on my monitor.
*x<-rnorm(1000)
> adf.test(x)
Error: could not find function "adf.test"
*I am waiting for your response.
Kamlesh Kumar.
--
Kamlesh Kumar
Appt. No. - QQ420,
2003 Jun 03
1
tseries "adf.test"
I have a question regarding the adf.test command in the tseries library.
I have a vector of time series observations (2265 daily log prices for the
OEX to be exact). I also have this same data in first-differenced form. I
want to test both vectors individually for staionarity with an Augmented
Dickey-Fuller test. I noticed when I use the adf.test command from the
tseries library, the general
2005 May 23
3
Dickey-Fuller Test
Hi All ,
Could you please tell using which library ,Dickey-Fuller Test can be run?
Thanks a lot
__________________________________________________
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2010 Aug 23
1
Dickey–Fuller test in R
Hi,
While doing the adf test using ur.df
?price.df2=ur.df(y=log(price),type = "drift", selectlags="AIC")
summary(price.df2)?
It gives two values for ?value of test statistic is: -1.5992?? 2.32?
one value is the t-test (or t-ratio), what is the other one?
Please help.
TIA
Aditya
2004 Jan 13
3
How can I test if a not independently and not identically distributed time series residuals' are uncorrelated ?
I'm analizing the Argentina stock market (merv)
I download the data from yahoo
library(tseries)
Argentina <- get.hist.quote(instrument="^MERV","1996-10-08","2003-11-03", quote="Close")
merv <- na.remove(log(Argentina))
I made the Augmented Dickey-Fuller test to analyse
if merv have unit root:
adf.test(merv,k=13)
Dickey-Fuller = -1.4645,
2008 Feb 26
2
Obtaining values from adfstat objects
Hi,
I'm using the ADF.test function in the uroot package to obtain an
adfstat-class object. I'm wondering how I can extract the values (test
statistic, p value, etc.) from this class, since it doesn't seem to have
usual values. I get the following summary, but I'm not sure how to do
anything with these values -- how can I put the number into another
variable?
--------- ------ -
2003 Jun 10
1
Regression output labels
Hello to all-
1. When I run a regression which implements the augmented Dickey-Fuller
test, I am confused about the names given to the regressors in the output.
I understand what "xGE" stands for in a standard "lm" test involving an
independent variable GE for instance, but if I lags and or differences are
included in the model, what do the following "output" stand
2011 Jun 06
2
Problem in R documentation
I am not able to run Dickey-Fuller test.
adf.test() function is not working. It is showing 'Error: could not find
function "adf.test"
Can any tell how to call "time series" library?
--
Siddharth Arun,
4th Year Undergraduate student
Industrial Engineering and Management,
IIT Kharagpur
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2008 Apr 04
1
Problems with Unit Root testing using ur.df function
Hi All,
I'm new to R and am trying to run a unit root test on the vector "y" (a time
series of inflation (i.e. changes in the Consumer Price Index quarter on
quarter)).
I've run the Augmented-Dickey-Fuller Test below (R's URCA package). It gives
me an error that it cannot find the function ur.df unless I comment out the
third last line of code (see below).
I try to call
2009 Dec 27
4
how to create a simple loop ?
I have a 5-row matrix called “data”. There are headers.
it look like this :
Row 1 Row2 Row3 Row4 Row5
Line1 … … … …
Line2 … … … …
Line3 … … … …
…
Line 1838 … … … …
I want to calculate several simple arithmetic means for Row5, that
2009 May 15
1
Dickey-Fuller Tests with no constant and no trend
R has a Dickey-Fuller Test implementation (adf.test) that tests for unit
roots in an autoregressive process with a constant and linear trend. Is
there a DF implementation that doesn't use the constant or trend?
Thanks,
Jake.
--
View this message in context: http://www.nabble.com/Dickey-Fuller-Tests-with-no-constant-and-no-trend-tp23565210p23565210.html
Sent from the R help mailing list
2009 Mar 20
1
Dickey Fuller test of a time series (problem)
Hi all,
I tried to do a Dickey Fuller test with R using adf.test with a time series of german stock prices. I have 10 stocks from 1985 to 2009 with monthly stock prices. So if you do the math I have 289 values for each stock.
I tried to do the test for each stock alone and had the 289 values of my first stock listed in R.
When I tried to do the test with command adf.test(x, k=1) the following
2006 Apr 06
1
How to implement an iterative unit root test
Hello,
How can an interative unit root test be implemented in R?
More specifically, given a time series, I wish to perform the Dickey
Fuller Test on a daily basis for say the last 100 observations. It would
be interative in the sense that this test would be repeated each day for
the last 100 observations.
Given the daily Dickey Fuller estimates of delta for the autoregressive
process
d(Y(t))