similar to: read.table: mysterious line omissions

Hello, I am currently using R to run an external program and then read the results the external program sends to the stdout which are tsv data. When R reads the results in it converts it to to a list of strings which I then have to maniuplate with a whole slew of commands (which, figuring out how to do was a reall challenge for a newbie like myself)--see below. Here's the code I'm

Wow.. thanks for the deluge of responses! Aggregate seems like the way to go here. But, suppose that instead of integers in column V2, I actually have dates (and instead of keeping the minimum integer, I want to keep the earliest date): > df =

Hi all, I'm feeling a little guilty to ask this question, since I've written a solution using a rather clunky for loop that gets the job done. But I'm convinced there must be a faster (and probably more elegant) way to accomplish what I'm looking to do (perhaps using the "merge" function?). I figured somebody out there might've already figured this out: I have

Hi All, I'm trying to use the "sample" function within a loop where the vector being sampled from (the first argument in the function) will vary in length and composition. When the vector is down in size to containing only one element, I run into the "undesired behaviour" acknowledged in the ?sample help file. I don't want sample(10,1) to return a number from

Hi, I'm requesting you don't berate me for asking this question: I clearly don't have the gist of factors. I have two dataframes, A and B. Each of them has a column containing strings (they're labels). I want to, one-by-one in a loop, compare the particular string in an entry from dataframe A to an entry in B, to see if they're the same. The problem, when posing the

Hi, A noobie question: I'm simply trying to run a conditional statement that evaluates if a substring is found within a larger string. I find that if it IS found, my function returns TRUE (great!), but if not, the condition does not evaluate to FALSE. ex): if( grep("hi", "hop", fixed = TRUE) ) print('yes, your substring is in your string') else

Hi all, I'm hoping this question has a simple answer, but I can't find it through searching or trying commands. I have a list of numeric vectors called 'husk'. I'd just like to treat the set of all numbers from all vectors in the list as if it were one large vector, because I'd like to extract information, such as what is the max entry from all the numbers. > husk

I''ve discovered that most of the documentation changes were omitted from the released 1.4.3 tarball and RPM. The updated documentation is available now on Sourceforge and will be available on the other mirrors shortly. In a few days, I''ll release 1.4.3a with the updated documentation but I want to wait to be sure that there are no other problem fixes that need to be included

"lpt1" through "lpt9" and "com1" through "com9" are in fact "special" file names under various versions of Microsoft Windows. However, "R Extensions" says only that "lpt1" through "lpt4" and "com1" through "com3" cannot be used as filenames, and "R CMD check" checks for just these

Hi, Here are the issues I found: Typos ----- (a) Found: It a parallel version of ?evalq?, "is" missing. (b) Found: 'parLapplyLB', 'parSapplyLB' are load-balancing versions, intended for use when applying ?FUN? to 'parLapplyLB' has no 'FUN' arg (more on this below). (c) Found: 'clusterApply' calls 'fun' on the first

It did not convert over some things: protocol imap { listen = *:143 mail_plugins = quota imap_quota imap_client_workarounds = outlook-idle ssl_listen = *:993 } protocol pop3 { pop3_uidl_format = %f mail_plugins = quota pop3_client_workarounds = outlook-no-nuls oe-ns-eoh } protocol lda { mail_plugins = quota cmusieve

Anybody have an idea why I would get a non-integer value for the number of days here? > difftime('2004-08-05','2001-01-03',units='days') Time difference of 1309.958 days Would you just round off? Best, Jon

Last one for you guys: The command: length(gregexpr('cus','hocus pocus')[[1]]) [1] 2 returns the number of times the substring 'cus' appears in 'hocus pocus' (which is two) It's returning the number of **disjoint** matches. So: length(gregexpr('aa','aaa')[[1]]) [1] 1 returns 1. **What I want to do:** I'm looking for a way to count

Hi R-help, I am interested in comparing two vectors of data observations to see if they come from the same distrubution (and have settled on the Kolmogorov-Smirnov test to do this).. I'd prefer to use all my data points, but computationally speaking, this is proving to be troublesome due to the size of my vectors (the larger of the two is about 90 million observations). I suppose I could

Hi all, I'm trying to generate a grid of four plots. The first 2 appear just fine, but the final 2 will not appear in the grid, instead overwriting the first two. Any ideas on how to get them all in the same window would be greatly appreciated. Cheers, Jonathan library(fields) par(mfrow=c(2,2)) #2x2 plot windows plot(c(2,4),c(2,2)) # works fine plot(c(2,4),c(2,2)) # works fine

Hi All: Let's say I have two dataframes (Condition1 and Condition2); each being on the order of 12,000 and 16,000 rows; 1 column. The entries contain dates. I'd like to calculate, for each possible pair of dates (that is: Condition1[1:10,000] and Condition2[1:10,000], the number of days difference between the dates in the pair. The result should be a matrix 12,000 by 16,000. Really,

Hi, There must be an easy way to do this, but I'm not finding it.. I'd just like to know the syntax to move up and down folder levels, without necessarily entering a full file path. Also, how to construct file and folder paths using variables. For example 1, if I wanted to print to the screen the contents of a file called myFile.txt using the bash shell, I'd use the following:

Hi r-help community, This question isn't so much a syntax/coding one, but here goes: Let's say I have matrix of arbitrary dimensions and I'd like to reorder the rows in such a way that I could maximize the sum of the entries along the diagonal. For example, for this 3x3 matrix: [,1] [,2] [,3] [1,] 3 4 13 [2,] 9 1 2 [3,] 2 11 1 rearranging the rows

Hi All, My R installation is acting strangely and I'm hoping somebody might have an idea what's going on: I can't seem to load the "RMySQL" function. It seems to have installed without a problem, but when I enter: library(RMySQL) R tells me: Error in utils::readRegistry("SOFTWARE\\MySQL AB", hive = "HLM", maxdepth = 2) : Registry key

Sorry, maybe it's easy but I haven't found anything useful: how can I obtain a list C that contains all the members in the list B that are not in list A? This are lists of nanes, not numbers! Thank you Gabriele Zoppoli, MD Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University of Genova, Genova, Italy Guest Researcher, LMP, NCI, NIH, Bethesda MD Work: 301-451-8575