similar to: write.csv and header

I want to create a data.frame of time and date for a year. I started with the idea of simply producing two vectors (time and date) The first part ( time) is easy. rep(1:24, 365) But how do I get a series of 24 dates for O1 January 2005 and repeat this to 31 December 2005. It should be easy but I don't see it. Thanks

Dear all, Is there a way to generate K numbers of integer (K = 10^6). The maximum value of the integer is 200,000 and minimum is 1. And the occurrences of this integer follows a lognormal distribution. - Gundala Viswanath Jakarta - Indonesia

Hi all, I wonder if there is any way to calculate a moving average on an irregular time series, or use the rollapply function in zoo? I have a set of dates where I want to check if there has been an event 14 days prior to each time point in order to mark these timepoints for removal, and can't figure out a good way to do it. Many thanks in advance! Gustaf Example data:

Hi all, I'm currently preparing some figures that will be submitted to PloS One. In their guidelines they state that they will only accept figures in tiff or eps format, with the warning that eps figures will be converted to tiff format ( see http://www.plosone.org/static/figureGuidelines.action ). Because of this conversion, I figured I'd generate tiff-format figures from the beginning.

Hi to everyone, I am starting to work with a model that is not familiar to me. The model would be like that: y = . - a*max(Q(i) - Q(0), 0) + . where Q(i) is the accumulated effect of a variable at time i and Q(0) a threshold above it there is effect on y. The value of Q(i) could be estimated as: Q(i+1) = Q(i) + b*max(s(i) - s(0), 0) + c*min(s(i) - s(0), 0) + . Where s

Hi all, Is there a simple function already implemented for getting the ISO weeks of a Date object? I couldn't find one, and so wrote my own function to do it, but would appreciate a pointer to the "default" way. If a function is not yet implemented, could the code below be of interest to submit to CRAN? Best Regards, Gustaf --------------------

Hi all, In lattice plots, is there any option to position the panel strips with text below each subgraph, instead of above? i.e. in: Depth <- equal.count(quakes$depth, number=8, overlap=.1) xyplot(lat ~ long | Depth, data = quakes) ,is there any way to make "Depth" appear below the subgraphs, instead of above? I've been looking through the lattice documentation and the list

Hi all, I hope that there is someone that can help me out here. I am trying to load() a workspace on os x (R 2.11.0) that was saved in windows XP (R 2.9). In that workspace, there's a data.frame with names that contain swedish characters. These characters become garbled, which is a major problem. >From the R windows FAQ, I read: "Note though that character data in a workspace will be

Hi all, I'm trying to download a file from the net, and the download.file command leaves it corrupted, i.e excel cannot open it. It seems as if it's going ok, however. Does anyone have an idea of what's going on? regards, Gustaf Rydevik ---- >download.file(url="http://www.who.int/entity/whosis/whostat2006_demographics.xls",destfile="whodem.xls") trying URL

Hi all, This is perhaps more a statistics question than an R question, but I hope it's OK anyhow. I have some data (see below) with the number of tests positive to subtype H1 of a virus, the number of tests postive to subtype H3, and the total number of tests. This is for two different groups, and the two subtypes are mutually exclusive. What is the best way to test if the proportion of H1

Hi all, I have a time series which contain data collected weekly from week 26 to week 25 the following year. How do I plot this data, so that the x-axis is displaying the week numbers, ordered as in the data? Thanks in advance, Gustaf --- x<-c(26:52,1:25) y<-rnorm(52)+1:52 plot(x,y) ## How do I get the x axis to be ordered by the current ordering of x? -- Gustaf Rydevik, M.Sci. tel:

Hello and sorry that I still haven?t found a solution for my problem. I need to extract the lower and upper triangle from a square matrix including the diagonal. This diagonal is not zero in that special case. I tried with as.dist w<-as.dist(w, diag = TRUE) > w 1 2 3 4 5 1 0 2 2 0 3 3 8 0 4 4 9 14 0 5 5 10 15 20 0 but found no way to keep the diagonal that is in the

Hi, I ran into this issue previously and managed to solve it, but I've forgotten how and am getting frustrated... I have a data frame (see below) with scandinavian characters in R (2.7.1) running on a Win Xp-computer. I save the data frame in an RData-file on a usb stick, and load() it in R (2.8.0) running on OS X 10.5. Now the name of the data frame and all factor labels with scandinavian

Sorry about this one being long, and I apologise beforehand if there is something obvious here that I have missed. I am new to creating my own functions in R, and I am uncertain of how they work. I have a data set that I have read into a data frame: > gctable[1:5,] refseq geometry X60_origin X60_terminus length kingdom 1 NC_009484 cir 1790000 773000 3389227 Bacteria 2

Hi all, I'm writing a function that will automatically generate a report based on answers to a questionnaire. The exact questions and answers to the questionnaire can vary. One of the question types is in a "matrix" format, where the agreement to several statements can be indicated on a scale. I'm planning to plot this on a multilevel barplot, and only labeling each "bar

Dear all, How can I get the duplicated elements from a vector? For example, x <- c("yes", "no", "yes", "yes", "no", "not sure"), how can I filter out all the elements which occured >=2 times? Thanks for any help! Regards, Leon

Hello, everyone I have a piece of code that looks like this: mrets <- merge(mrets, BMM.SR=apply(mrets, 1, MyFunc, ret="BMM.AV120", stdev="BMM.SD120")) mrets <- merge(mrets, GM1.SR=apply(mrets, 1, MyFunc, ret="GM1.AV120", stdev="GM1.SD120")) mrets <- merge(mrets, IYC.SR=apply(mrets, 1, MyFunc, ret="IYC.AV120",

Rahul Agarwal Analyst Equities Quantitative Research UBS_ISC, Hyderabad On Net: 19 533 6363 hi let me explain you the problem we have a database which is in this format Stocks 30-Jan-08 28-Feb-08 31-Mar-08 30-Apr-08 a 1.00 3.00 7.00 3.00 b 2.00 4.00 4.00 7.00 c 3.00 8.00 655.00 3.00 d 4.00 23.00 4.00 5.00 e 5.00 78.00 6.00 5.00 and we have a query

Dear ALL, Does anyone know how to get the complete code program for any build-in function in R, e.g. when I tape mean in the R-console, I get the following:  mean function (x, ...) UseMethod("mean") <environment: namespace:base> but I need the full mean function. Thank in advance, Alphonse. [[alternative HTML version deleted]]

I think the argument supporting the use of bootstrap to determine coefficients, as opposed to just running linear regression on the whole dataset, is the comparison of Rsq and prediction errors between these two approaches - page 1502. There's a substantial difference in favor of the bootstrap approach. -- Michal J. Figurski Gustaf Rydevik wrote: > The url for the mentioned paper is