similar to: Recoding factor labels that are lists into first element of list

Good evening I often have as output from simulations a list of various values, vectors and matrices. Supposing that I then run said simulation several times, I often want to extract a particular result from each simulation for plotting and, ideally, put it in a matrix. A simple example v1 <- 1:5 v2 <- 6:10 other1 <- "stuff" other2 <- "stuff" set1 <-

Hi Everyone, I think I found a problem with the ifelse function: If the condition argument is NA, it treats it as true. Anyone agree or disagree with this? Jen -- Jennifer Dillon Doctoral Student Harvard Biostatistics Room 414B, Building 1 [[alternative HTML version deleted]]

Hi: I have a 2.1GB JSON file. Typically I use readLines() and jsonlite:fromJSON() to extract data from a JSON file. When I try and read in this file using readLines() R segfaults. I believe the two salient issues with this file are 1). Its size 2). It is a single line (no line breaks) I can reproduce this issue as follows #Generate a big file with no line breaks # In R >

Hi, I'm trying to do a simple survival analysis on some data, and I'm having the following problem (here's my code and the error message): out <- Surv(fup,event=status) Error in Surv(fup, event = status) : argument "time2" is missing, with no default >From reading the documentation, it seems that I should be able to simply write: Surv(time1, event) if my data is

Thank you for your suggestion. Unfortunately, while R doesn't segfault calling readr::read_file() on the test file I described, I get the error message: Error in read_file_(ds, locale) : negative length vectors are not allowed Jen On Sat, Sep 2, 2017 at 1:38 PM, Ista Zahn <istazahn at gmail.com> wrote: > As s work-around I suggest readr::read_file. > > --Ista > > >

R Experts, I'm looking for some help with the geoR package. I'm trying to krig some data without using a global neighborhood. I would like to set my moving neighborhood to a distance, say 100 meters, where I know my data is spatially correlated. I have tried the ksline function, but that only allows my moving neighborhood to be set to a number of data points. But, since my data

Jeroen: Thank you for pointing me to ndjson, which I had not heard of and is exactly my case. My experience: jsonlite::stream_in - segfaults ndjson::stream_in - my fault, I am running Ubuntu 14.04 and it is too old so it won't compile the package corpus::read_ndjson - works!!! Of course it does a different simplification than jsonlite::fromJSON, so I have to change some code, but

Hello, I am almost a total novice, and I am sure there must be an easy (and basic) way to turn a variable of 1's and 2's into a variable of zeros and ones. This is in a data frame, but if I could do it with vectors, that's all I need. Can someone tell me how? Thanks so much, Jen

Hi Michael: I can confirm Martin's comment. I tested my software with r-devel (r74914) and it works, while with r-patched (r74914) it does not work (it hangs, as it did in R 3.5.0). I apologize for it taking so long for me to test this, but is there any chance this fix could make into R 3.5.1? Thanks. Jen. On Wed, Jun 13, 2018 at 6:24 AM, Michael Lawrence <lawrence.michael at gene.com

On the documentation page for DateTimeClasses, in the Examples section, there are the following two lines: format(.leap.seconds) # the leap seconds in your time zone print(.leap.seconds, tz = "PST8PDT") # and in Seattle's The second line (using print) seems to ignore the tz argument, and prints the dates in my time zone, while: format(.leap.seconds, tz =

>>>>> Michael Lawrence >>>>> on Tue, 12 Jun 2018 19:27:49 -0700 writes: > Hi Jen, This was already resolved for R 3.5.1 by just > disabling buffering on terminal file connections like stdin. and before R 3.5.1 exists, *and* as the change is also not yet available in R patched (!) this means using a version of "R-devel", e.g. for Windows

Hello, Researchers at Oregon State University are striving to conduct research to learn more about the free/open source software community landscape as it relates to older adults. We have identified you as a leader for a free/open source software community. If you?re interested, we will either do an in-person interview (if you are local to the Corvallis or Portland area), or an interview over the

Hi: I have also just stumbled into this bug. Unfortunately, I can not change the data my program receives from stdin. My code runs in a larger system and stdin is sent to a Docker container running my R code. The protocol is I read a line, readLines("stdin", n=1), do some actions, send output on stdout, and wait for the next set of data. I don't have control over this protocol, so

I'm new to R (previously used SAS primarily) and I have a genetics data frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3, ...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of the data is shown below: SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1 CC GG CT AA ID2 CC GG CC AA ID3 CC GG nc AA

Hi! Suppose I have a factor: > fac1 <- factor(rep(c("dog","cat","tree"),c(2,3,4))) > fac1 [1] dog dog cat cat cat tree tree tree tree Levels: cat dog tree > length(fac1) [1] 9 Now I want to get rid of the dogs: > fac1 <- fac1[3:9] > fac1 [1] cat cat cat tree tree tree tree Levels: cat dog tree > How should I remove the dog from the

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Hi, I have numerical variable that I want to recode into categories '0' and '1 and more' and do analysis with that data. I have tried various of possibilities to do so, but I am sucked and nothing is working. recode(Q12, "0='A';1:30='B'") cut(Q12, breaks=c(0,1,30), lables=c('0', '1 and more')) cat(Q12, "0=0;1-33=1") What should

Hello Could someone please direct me to the correct commands for adding accents (grave and aigu) to a letter in a plot title, label, or in added text? I'm sure there's a handy list somewhere, but I've failed in coming up with the correct search words to find it. Thank you muchly! Jen

Hi R-Helpers, I don't think I need to post a dataset for this question but if I do, I can. Anyway, I am having a lot of trouble with the ifelse command. Here is my code: vn$PM.DIST_flag <- ifelse( (vn$PM.EXP > 0.0) & (vn$PM.DIST.TOT != 1.0), 1, 0 ) And here is my output that doesn't make ANY sense: PM.EXP PM.DIST.TOT PM.DIST_flag 0 0 0 0 0 0 0 0 0 177502 1 0 31403

Hi All, I have some data where I am doing fairly simple calculations, nothing more than adding, subtracting, multiplying and dividing. I’m running into a problem when I divide one variable by another and when they’re both 0 I get NaN. I realize that if you divide a non-zero by 0 then you get Inf, which is, of course, correct. But in my case I never get Inf, just NaN because of the structure