similar to: R ANOVA question

Hi, I am wondering if there is a simple way to fix the problem I am having. For unknown reason, I could not get the full name of the factors to be printed in the summary. I have tried to used summary.lm as well but the problem still persists. SJ$Weekday <-

Hi, I am trying to count weekday of the month using R. For example, 1/4/2001 is the 4th weekday of Jan, and 1/5/2001 is the 5th weekday of the month, and 1/8/2001 is the 6th weekday of the month, etc. I get as far as extracting the weekdays from a sequence of dates (see below). But I have not yet figured out a fast way of counting without using a For Loop. Does anyone know how to do such counting

On converting character variables to ordered factors, regression result has strange names. Is it possible to obtain same variable names with and without intercept? Thanks, Naresh mydf <- data.frame(date = seq.Date(as.Date("2024-01-01"), as.Date("2024-03-31"), by = 1)) mydf[, "wday"] <- weekdays(mydf$date, abbreviate = TRUE) mydf.work <- subset(mydf, !(wday

(Sorry for reposting. Please delete previous msgs. Thanks!) Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604

Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604 3 2010-05-31 Monday 0.74813943 4 2010-06-01 Tuesday

Hi all, probably really simple: I seem to be lacking some understanding for the character class: I have a bunch of dates in a dataframe and I want to add a string variable with the weekday for each date. If I use something like mydata$day <- weekdays (mydata$date), I can create subsets for each weekday (eg mydata=="Monday"), but summary (mydata$day) doesn't count the instances for

I'm an R noob and have a (maybe) stupid question... I have a table where I have the weekdays and a number for each weekday of entries: Thats what the table looks like... Now I want to have an pie3D plot of this, but obviously the order of the weekdays are not as one would expect... Friday Monday Saturday Sunday Thursday Tuesday Wednesday 119 173 80

Fellow R users, I am stumped on what would seem to be something fairly simple. I have a dataframe that has a variable named 'WEEK' that takes the numbers 1:26 (26 week time-period) with each number repeated five times consecutively (once for each weekday, Monday through Friday). Ex. 111112222233333.....2626262626. I would like to randomly extract two weekdays per five day week for

For what it's worth, I tried setting my Region | Formats setting to Spanish (Peru) in Windows 10 Control Panel, and got Spanish weekday and month results. I believe on Windows we use the Microsoft C strftime function to produce these strings, with the %A (for weekday) or %B (for month) formats. So this question probably needs to be addressed to Microsoft. Duncan Murdoch On 05/06/2017

Thank you Duncan and Rui for your time and interest in this issue. Maybe it is a problem with Windows 7 and Spanish, and not Windows 10. Let's wait for someone with the same enviroment, before assuming it's a problem with my PC/configuration. 2017-06-05 14:37 GMT-05:00 Duncan Murdoch <murdoch.duncan at gmail.com>: > For what it's worth, I tried setting my Region

R users, I am trying to generate a randomized weekday survey schedule that ensures even coverage of weekdays in the sample, where the distribution of variable DOW is random with respect to WEEK. To accomplish this I need to randomly sample without replacement two weekdays per week for each of 27 weeks (only 5 are shown). However, I need to sample from a sequence (3:7) that needs to be

Dear R community, I have a project with electricity load forecasting, and I got hourly data for system load. If you haven't worked with electricity before, seasonality comes in many flavors: a daily pattern, with a peak at around 7pm; a weekly pattern, in which we use more electricity on weekdays in comparison to weekends; a winter-summer pattern, with air conditioning and heaters playing an

Hi, I am wondering if there is a way to display the full anme of the regression coeffients/factors in the summary? Suppose I have a bogus data set using weekday as factor which has 7 levels such as: mydata <- sample(364) wk <- rep(1:7, 52) weekday <-

Question from an [R] novice... Hi, I have a vector of date/times like the one shown below (a truncated sample of a much longer list...) > dates[1:4] [1] "2006-03-16 08:41:00" "2006-03-16 10:28:00" "2006-03-16 11:03:00" [4] "2006-03-16 11:04:00" I would like to generate a weekday histogram showing the frequency of dates falling on each weekday. I know

Hello, I have a dataset which has fields giving both calendar date and weekday. I know better functions are now available, but I am still using chron because of the is.holiday() function and a homemade (even Heath Robinson would be ashamed) is.daylight() function. As a check for typos in the data input, I checked that the dates matched the weekdays. I'm getting some confusing results

Dear R-users, How do I obtain a sequence of dates consisting of only weekdays without the weekends in R? In S, I can do the following: timeSeq(from="12/17/2007", to="8/25/2008", by="weekdays") I tried using looking at timeSequence (fSeries package) and seq.Date (base package) but I do not know if I can specify "weekdays" rather than "day".

Hi Folks! I'm struggling with dates - but enough about my personal life..... I have two daily time series files. In one (x) the date format is Y/m/d and the other (y) is d/m/y. I used read.zoo on both and they read into R with no problem. Then I use: weekdays(as.Date(x$DATE)) and get what I expect - all the days of the week in my data set. When I use:

hi , all what's wrong with this command? exten => 222,1,GoToIfTime(11:00-14:00|mon,wed|*|*?1:3,1) as i got the error: -- Executing [222 at 95040:1] GotoIfTime("SIP/1001-00000099", "11:00-14:00|mon|wed|*|*?1:3|1") in new stack [Jan 20 11:21:11] WARNING[16804]: pbx.c:4118 get_range: Invalid day 'wed', assuming none but what should i do. if i want to set

Hello, This doesn't answer the question, but in portuguese it works as expected. > x <- as.Date("2017-06-05") > months(x) [1] "junho" > weekdays(x) [1] "segunda-feira" > sessionInfo() R version 3.4.0 (2017-04-21) Platform: x86_64-w64-mingw32/x64 (64-bit) Running under: Windows 7 x64 (build 7601) Service Pack 1 Matrix products: default

Hi, I want to reporte some strange behaviour with the "months" function, from base R. When using "months" to extract months from a date column, I'm getting the months in english, when I was expecting months in spanish. When using "weekdays" to extract days of week from a date column, I'm getting the the days in spanish (as expected). My understanding is