similar to: Dataframe help

Hi, I have two columns that contain numbers along with letters (as shown below) and have different lengths. Each entry in the first column is likely to be found in the second column at most once. For each entry of the first column, if that entry is found in the second column, I would like to get the corresponding index. For instance, if the first entry of the first column is 5th entry in the

It's generally a very good idea to examine the structure of data after you have read it in. str(data2) would have shown you that read.csv() turned your strings into factors, and that's why the == operator no longer does what you think it does. use ... data_2 <- read.csv("excel_data.csv", stringsAsFactors = FALSE) ... to turn this off. Also, the %in% operator will achieve

Combining and completing the advice from Greg and Boris the complete solution is two lines: data_2 <- read.csv("excel_data.csv", stringsAsFactors = FALSE) match_list <- match( data_2$data1, data_2$data2 ) The vector match_list will have the matching position when it exists and NA's otherwise. Its length will be the same as the length of data_2$data1. You should get

hi there I have a dataframe abc 123 345 abc 345 456 lmn 567 345 hkl 568 535 lmn 096 456 lmn 768 094 i want the uniques of column 1 and there corresponsing column 2 and 3 output abc 123 345 lmn 567 345 hkl 568 535 cbind(DF1[,1],DF1[which(unique(DF1[,1]),c(2,3)]) but didnt work kindly let me know how to go abt it ramya -- View this message in context:

Hi there, I have a dataframe length.unique.info > length.unique.info abc 12 345 def 16 550 lmn 6 600 I want those names that fall under the condition (length.unique.info[,2][i] <=5 && length.unique.info[,3][i] >=500) abcder<-length.unique.info[which(length.unique.info[,2][i] <=5 && length.unique.info[,3][i] >= 500),1] will "&&" look for

hi there, I have a list of list objects i need to remove the top layer [[1]] [1].0 "ABC" "DEF""LMN" [1].1 "WER" "ERT" "TRY" [[2]] [2].0 "ASD","wer""qwe" [2].1 "wdv""ghj""ggj" I wanna avoid the top layer...that is [[1]] [[2]] shouldnt be there just a simple list is wat i need.

Dear R helpers, I have a data.frame as given below - dat1 = data.frame(date = as.Date(c("3/30/12","3/29/12","3/28/12","3/27/12","3/26/12", "3/23/12","3/22/12","3/21/12","3/20/12", "3/30/12","3/29/12","3/28/12","3/27/12",

Dear R helpers Suppose I have a vector as vect1 = as.character(c("ABC", "XYZ", "LMN", "DEF")) > vect1 [1] "ABC" "XYZ" "LMN" "DEF" I want to reverse the order of this vector as vect2 = c("DEF", "LMN", "XYZ", "ABC") Kindly guide Regards Vincy [[alternative HTML

Dear R helpers   I have some variables say ABC, DEF, PQR, LMN and XYZ. I am choosing any three varaibles at random at a time for my analysis and name these files as input1.csv, input2.csv and input3.csv. So if I choose variables say ABC, DEF and PQR, I am passing the specifications of these variables to input1.csv, input2.csv and input3.csv respectively.   This means in another case even if I

I have a function that fits polynomial models for the orders in n: lmn <- function(d,n){ models=list() for(i in n){ models[[i]]=lm(y~poly(x,i),data=d) } return(models) } My data is: > d=data.frame(x=1:10,y=runif(10)) So first just do it for a cubic: > mmn = lmn(d,3) > predict(mmn[[3]]) 1 2 3 4 5 6 7 8

Dear R Forum, I have a data.frame as df = data.frame(date = c("2013-04-15", "2013-04-14", "2013-04-13", "2013-04-12", "2013-04-11"), ABC_f = c(62.80739769,81.04525895,84.65712455,12.78237251,57.61345256), LMN_d = c(21.16794336,54.6580401,63.8923307,87.59880367,87.07693716), XYZ_p = c(55.8885464,94.1358684,84.0089114,98.99746696,64.71083712),

Hello all, I am new to Rails. I don''t know whether it is possible are not. In my application, I need get data from one table , then arrange these data in table in textfield, then I need to edit data in all rows in single form. At the end I need to save these data back to databse. How can I do this Is this possible <%= tag("input" , {:type => '''',

Is there a way to pass the database name in config/database.yml to a migration task such that the appropriate (test, development or production) DB is created by the initial migration? What I would like to do is to get this sort of thing to work: class RbacDataStructures < ActiveRecord::Migration def self.up create_database <<dbname from database.yml>> class

Dear R-help, I think I have kinda isolated the problem I had to the following: i <- 0 while( {i <- i + 1} < 5) { if(i < 3) next print(i) } This seems to go into an infinite loop. After I break the execution, i has the value 1. At the R prompt, if I start from i <- 0 and keep typing {i <- i + 1} < 5, it eventually evaluate to TRUE. So why does the while loop not work?

Prof. Tierney, Thanks very much for the info. Why does the loop work if I move the assignment out of the condition? E.g., the following works: i <- 0 while(i < 5) { i <- i + 1 if(i < 3) next print(i) } Regards, Andy > -----Original Message----- > From: Luke Tierney [mailto:luke at nokomis.stat.umn.edu] > Sent: Tuesday, October 02, 2001 3:36 PM > To: Liaw, Andy

https://bugzilla.mindrot.org/show_bug.cgi?id=2765 Bug ID: 2765 Summary: ssh-copy-id appears to hang indefinitely when the target user has no password Product: Portable OpenSSH Version: 6.6p1 Hardware: All OS: Linux Status: NEW Severity: trivial Priority: P5

https://bugzilla.mindrot.org/show_bug.cgi?id=2503 Bug ID: 2503 Summary: The sshd log files are insufficient to detect sessions Product: Portable OpenSSH Version: 7.1p1 Hardware: All OS: All Status: NEW Severity: enhancement Priority: P5 Component: sshd Assignee:

I was trying to do a SIP call between two Asterisk servers (1.4.21.2) 1) On the caller server, I coded the following in extensions.conf Dial(SIP/1166:password at asterisk-callee); 2) On the callee server, I coded the following in sip.conf [1166] type=friend ; Friends place calls and receive calls context=incoming ; Context for incoming calls from this user

I R-helpers #I have a data panel of thousands of firms, by year and industry and #one dummy variable that separates the firms in two categories: 1 if the firm have an auditor; 0 if not #and another variable the represents the firm dimension (total assets in thousand of euros) #I need to create two separated samples with the same number os firms where #one firm in the first have a corresponding

Folks I am using sendmail as my mail server. SELINUX is disabled. I observe messages in Centos 7 (and 6) in /var/log/messages, similar to: saslauthd[2765]: do_auth : auth failure: [user=bettie] [service=smtp] [realm=] [mech=pam] [reason=PAM auth error] I guess that this is because somebody tried to access one of the SMTP ports with a logon attempt. This is understandable; there are