similar to: How build hist combining data

Dear all, does anybody ever encountered the problem with diagnostic plots? x<-rnorm(100) y<-rnorm(100) plot(lm(x~y)) It gives the following message "Waiting to confirm page change..." and nothing happens. Thanks a lot! [[alternative HTML version deleted]]

Dear all, Does anybody know the probable reason why <= gives false when it should give true? These two variables are of the same type, and everything works in the cycle but then it stops when they are equal. this is the output result > Rk[47] <= RB[21] [1] FALSE > Rk[47] [1] 0.002842007 > RB[21] [1] 0.002842007 Thanks a lot. [[alternative HTML version deleted]]

Dear all, might seem and easy question but I cannot figure it out. floor(100*(.58)) [1] 57 where is the trick here? And how can I end up with the right answer? Thanks a lot everybody for your help. Trafim [[alternative HTML version deleted]]

Dear all, Are there any functions in R to reverse the order of the string. smth like reverse("abc") to get "cba"? Thanks a lot. [[alternative HTML version deleted]]

Dear all, I have a question is there a possibility to plot points with different symbols like stars, crosses? I looked at different types for plot command and didn't find anything like that. Thanks a lot. [[alternative HTML version deleted]]

I am trying, without success, to compile a custom locale for the utf-8 character set. I have issued this command: localedef --no-archive -f UTF-8 -i /usr/share/i18n/locales/en_CA at yyyy-mmm-dd en_CA at yyyy-mmm-dd.utf8 which produces the requisite files without reporting an error but which none-the-less insists on using the iso-8859-1 charset: LC_ALL=en_CA at yyyy-mm-dd locale charmap

Dear all, I would like to ask you if there is a possibility in R to give the names to graphs which are not const. For example, How to name each plot, or to add notes like a=x[i], b=y[i] in this cycle x<-c(1,2,3,4,5,6) y<-c(7,8,9,10,11,12) par(mfrow=c(2,3)) for (i in 1:6){ plot(x,y) } Thank you for your time and help! [[alternative HTML version deleted]]

Dear all, does anyone know how to define the structure of the required samples using function createDataPartition, meaning proportions of different types of variable in the partition? Smth like this for iris data: createDataPartition(y = c(setosa = .5, virginica = .3, versicolor = .2), times = 10, p = .7, list = FALSE) Thanks a lot for your help. Regards, Trafim [[alternative HTML version

Dear all, I would like to ask how to extract the p-value for the whole model from summary(lm). This didn't help a lot summary.lm summary(lm(speed~dist, cars)) Thanks a lot! [[alternative HTML version deleted]]

Dear R Helpers, I am trying to isolate a set of characters between two other characters in a long string file. I tried some of the examples on the R help pages and elsewhere, but I am not able to get it. Your help would be much appreciated. require(scrapeR)

Dear List, I'm trying to get diff/removed data and it's offset out. So I write a functions in receive_data. When I run backup, I found there is a weird behavior which I don't understand. i = recv_token(f_in, &data) will receive (i = -1, offset2 = 0) some where in the middle of the transfer procedure. That's to say, it's going to transfer the first data block from sender,

Hello, LLVM guys. I've tried to emit the following simple function to LLVM assmbly. --------------------------------------------------------- void test(long s, double* a) { char h = ttt(s); *a = s; mmm(); } --------------------------------------------------------- It's spat out as follows: --------------------------------------------------------- void %test(int %s, double* %a) {

Hello, is't possible to specify pattern in levels ? > y=c("ff","f","m","mm","fm","mf","ffm","mmf","mmm","fff"); > factor(y) [1] ff f m mm fm mf ffm mmf mmm fff Levels: f ff fff ffm fm m mf mm mmf mmm I want to specify levels using regexp ("f.*","m.*") or use

Dear R Helpers, I am trying to write a character value to the row of a data frame and am running into a problem that I don't have when I do this for numeric arguments. For example, the following works just fine: > test<-data.frame(number=numeric(1)) > test[1,]<-.5 > test number 1 0.5 But the following bombs out: > hold<-data.frame(symbol=character(1)) >

Hello all, I was wondering if the following behaviour of margin.table in R 1.3.0 is normal. > mm <- data.frame(x=c(0,0,1), y=c(1,1,0), z=c(0,1,0)) > margin.table(mm,1) [1] 1 2 3 <0 rows> (or 0-length row.names) while using 'apply(x,margin,sum)' I get > apply(mm,1,sum) 1 2 3 1 2 1 which appears to be normal. Similar behaviour when margin=2. On the other hand, the

Hi everyone, I have a vector of strings, each string made up by different number of words. I want to get a new vector which has only the first word of each string in the first vector. I came up with this: str <- c('aaa bbb', 'cc', 'd eee aa', 'mmm o n') str1 <- rep(1, length(str)) for (i in 1:length(str)) { str1[i] <- strsplit(str, "

# I have a dataframe in the following form: track <- c(rep('A', 3), rep('B', 4), rep('C', 4)) value <- c(0.15, 0.25, 0.35, 0.05, 0.99, 0.32, 0.13, 0.80, 0.75, 0.60, 0.44) df <- data.frame(track=factor(track), value=value) #> print(df) #track value #1 A 0.15 #2 A 0.25 #3 A 0.35 #4 B 0.05 #5 B 0.99 #6 B 0.32 #7 B 0.13

Please use dput() to post your example matrix. Rambler1 wrote > > I have run into a problem in my code. What I want to accomplish is this: > I have a user input stock symbols into a list and from there I run the > quantmod package to get historical data. I compute the correlation matrix > and then turn that matrix into a simple matrix with 1's or 0's depending > on

Hi everybody, well, I definitely don't understand anything. Why the hist function with freq=FALSE gives such a strange result??? R <- c(-1.10, 0.79, -1.17, -0.53, -0.26, -0.22, 0.29, -0.26, -0.26, 0.39) hist(R, freq=FALSE, breaks=10) Thanks everybody [[alternative HTML version deleted]]

Dear all, I have some error trying to bootstrap from a matrix. The error message is "Error in sample(n, n * R, replace = TRUE) : element 2 is empty; the part of the args list of '*' being evaluated was: (n, R)" vv <- c(0.5,3.2,5.4,1.1,1.4,1.2,2.3,2.0) Reg <- matrix(data=vv, nrow = 4, ncol = 2) bootcoeff <- function(x){ coefficients(lm(x[,1]~x[,2]))[2]+1 }