similar to: Data frame/read.ftable

I am generating an ftable (by running ftable on the results of a xtabs command) and I am getting the following. ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?Var1? Var2 date ? ? ? ? ? ? ? ? group? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 2007-01-01? ? ? ? ? q1 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?1? ? 9 ? ? ? ? ? ? ? ? ? ? ?q2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?

How can I export an ftable object in the same format that appears in R command window? For testing that i was using this example that is in help of this function. ## Start with a contingency table. ftable(Titanic, row.vars = 1:3) ftable(Titanic, row.vars = 1:2, col.vars = "Survived") ftable(Titanic, row.vars = 2:1, col.vars = "Survived") ## Start with a data frame. x <-

Dear R-developers, I would like to suggest a 'method' slot for format.ftable() (see an adjusted 'format.ftable()' below, taken from the source of R-2.15.2). At the moment, format.ftable() contains several empty cells due to the way the row and column labels are printed. This creates problems (= unwanted empty columns/rows) when converting an ftable to a LaTeX table; see an

Dear all, an hopefully quick table question. I have the following data: Two objects that are 2*9 matrix with nine column names (Dis1, ..., Dis9) and the row names (2010,2020). The content are frequencies (numeric). In want to create a table that is along the lines of ftable(UCBAdmissions) and should looks like this: Dis1 | ...| Dis9 2010|2020|....|2010|2020 (first row,first column is the value

Dear listmembers, I have a little question: I have my data organized as follow sic level area a 211 2.4 b 311 2.3 b 322 0.2 b 322 0.5 c 100 3.0 c 100 1.5 c 242 1.5 d 222 0.2 where levels and sics are factors. I'm trying to obtain a matrix like this: level 211 311 322 100 242 222 sic a 2.4 0 0

The ftable structure is not an ordinary matrix. Instead, it has the body of the table with several cbind- and rbind-ed rows and columns of label information. The example in ?ftable has two row factors and two column factors. Continuing with the example in ?ftable, enter tmp <- ftable(mtcars$cyl, mtcars$vs, mtcars$am, mtcars$gear, row.vars = c(2, 4), dnn =

I would like to suggest that an 'append' argument be added to write.ftable(). This would allow, for example, the user to append ftable() output to a text report. I have attached an svn patch to ftable.R that makes the proposed change to write.ftable(). [A very trivial change since 'append' is simply passed to cat().] I have also attached a patch to read.ftable.Rd which documents

Dear expeRts, What's the easiest way to convert an ftable object to a matrix such that the row names of the ftable object are shown in the first couple of columns of the matrix? This is (typically) required, for example, when the final goal is to print the matrix via xtable. Below is a rather complicated example of how to do it... Cheers, Marius ## Goal: convert an ftable() to a

I apologize in advance if this is the wrong forum for this report/request, and for the fact that I have not read the code for ftable.formula in any detail. >From reading the documentation for ftable.formula, I expected that the following two calls to ftable would produce the same results: data(UCBAdmissions) ftable(UCBAdmissions, row.vars = "Dept", col.vars = c("Gender",

Hoping someone can help me with xtabs and ftable. I'm trying to get a pair of ftables (possibly more) next to each other. For example: > dunhill_lights_xtab<-ftable(xtabs(grossedupobs ~ gender+age_group + dunhill_lights, data = ciggs)) > dunhill_lights_xtab dunhill_lights No Yes gender age_group Female

Dear latexRs, I tried to make a latex printout of a simple categorial ftable. It should look like the output of print.ftable. Any ideas how to get the syntax of summary.formula right. Or some alternative? As far I see, xtable does not have method for ftable. Dieter library(Hmisc) n=500 sex <- factor(sample(c("m","f"), n, rep=TRUE)) treatment <-

This bug shows up in ftable() in both r-patched and r-devel: > x <- c(1,2) > y <- c(1,2) > z <- c(1,1) > ftable(z,y) y 1 2 z 1 1 1 > ftable(z,x) x 1 z 1 2 Since x and y are identical, the two ftable results should be the same, but they are not. I've only been able to see this when the column variable is named "x", so it looks like a

Further to the discussion between Murray Jorgensen and Brian Ripley, it seems to me better to choose tabulations that will not come and bite you. Suppose your data are sligtly irregular, e.g. (for the sake of the argument): data( warpbreaks ) warpbreaks$variant <- rep( 1:5, len=54 ) attach( warpbreaks ) tb <- table( wool, tension, variant ) tb # in this case you would like to see: tp

Further to the discussion between Murray Jorgensen and Brian Ripley, it seems to me better to choose tabulations that will not come and bite you. Suppose your data are sligtly irregular, e.g. (for the sake of the argument): data( warpbreaks ) warpbreaks$variant <- rep( 1:5, len=54 ) attach( warpbreaks ) tb <- table( wool, tension, variant ) tb # in this case you would like to see: tp

Dear List, possibly called Frank, I tried to create an ftable lookalike of the following data set in LaTeX/Sweave with summary(formula,..), but I could not get it to work for count tables; numeric tables work fine. summary(formula,...,fun="table") does not give the full cross breakdown. Other suggestions welcome. Note that in the output there should be empty fields on repeated

dear all, i'm just about to do some straightforward contingency tables using ftables (and ctab() for percents). the problem: factor "a" are regions, factor "b" are subregions. every region "a" consists of some subregions "b", but obviously not every subregion "b" is part of every region "a". if i use the ftable() function, the

Dear R People: I have the following data set with the columns DATE, GENDER, and Co. Co has 8 possible options. > a.df[1:10,] DATE GENDER Co 1 2009-04-16 F Rash 2 2009-04-16 F Other 3 2009-04-16 M Botulinic 4 2009-04-16 M Other 5 2009-04-16 M Constitutional 6 2009-04-16 F Other 7 2009-04-16

I need to do some fairly deep tables, and ftable() offers most of what I need, except for the weighting. With smaller samples, I've just used replicate to let me have a weighted data set, but with this data set, I'm afraid replicate is going to make my data set too big for R to handle comfortably. That being said, is there some way to weight my table (similar to wtd.table) but offer the

Hi all, When I try the following with pkg Survey it returns the error below: ftable(svyby(~INCOME, ~AGECL+RACECL, svymean, design=q50), rownames=list(AGECL=c("<35", "35-44", "45-54", "55-64", "65-74", ">=75"), RACECL=c("white non hispanic", "non white or

I am experimenting with parallel processing using foreach and seem to be missing something fundamental. Cool stuff. I've gone through the list and seen a couple of closely related issues, but nothing I've tried seems to work. I know that the results from foreach are combined, but what if there is more than one variable within the loop? Below is a snippet (non-functioning) of code that I