similar to: barchart() {Lattice} -- auto.key()

Displaying 20 results from an estimated 4000 matches similar to: "barchart() {Lattice} -- auto.key()"

2009 Dec 02
1
Fw: Re: Help: barchart() {Lattice}
I HAVE BEEN ASKED TO BE REMOVED FROM THIS LIST OVER 20 TIMES, PLEASE CAN I BE REMOVED!!!!!!!!!!!!! --- On Thu, 3/12/09, Peng Cai <pengcaimaillist@gmail.com> wrote: From: Peng Cai <pengcaimaillist@gmail.com> Subject: Re: [R] Help: barchart() {Lattice} To: "Felix Andrews" <felix@nfrac.org> Cc: r-help@r-project.org Received: Thursday, 3 December, 2009, 10:17 AM Got it
2009 Dec 02
2
Help: barchart() {Lattice}
Hi R Users, I'm using following data/code (data is attached also) to produce a stacked barplot. # Sample Data: Names Col1 Col2 Col3 Row1 -20 40 -10 Row2 30 -20 40 Row3 30 10 -20 Row4 20 20 -10 # R Code: dta<-read.table("data.txt", header=TRUE, row.names="Names") barchart(data.matrix(dta), horizontal=FALSE, stack=TRUE, par.settings = simpleTheme(col =
2009 Nov 26
3
barchart() {Lattice} help.
Hi R Users, I'm trying to plot a stacked barplot. Here is data: Sample Col1 Col2 Col3 Row1 -2 4 -1 Row2 3 -2 4 Row3 3 5 -2 Row4 4 1 -1 I'm using following R code: library(lattice) dta<-read.table("data.txt", header=TRUE, row.names="Sample") barchart(data.matrix(dta), horizontal=FALSE, stack=TRUE, col=2:4,
2009 Aug 27
1
generating multiple sequences in subsets of data
I'm running into a problem I can't seem to find a solution for. I'm attempting to add sequences into an existing data set based on subsets of the data. I've done this using a for loop with a small subset of data, but attempting the same process using real data (200k rows) is taking way too long. Here is some sample data and my ultimate goal >
2008 Sep 04
1
restricted bootstrap
Hello List, I am not sure that I have the correct terminology here (restricted bootstrap) which may be hampering my archive searches. I have quite a large spatially autocorrelated data set. I have xy coordinates and the corresponding pairwise distance matrix (metres) for each row. I would like to randomly sample some number of rows but restricting samples such that the distance between them is
2013 May 01
1
Combine multiple tables into one
Hi, May be this helps: dat1<- as.data.frame(table1) ?dat2<- as.data.frame(table2) names(dat2)<-c("V3","V4") library(plyr) res<-join(dat1,dat2,type="full") ?res[is.na(res)]<- 0 ?res #? V1 V2 V3 V4 #1? 1? 1? 0? 0 #2? 1? 2? 0? 0 #3? 0? 0? 0? 1 #4? 0? 0? 0? 4 ?combinedtable<-as.matrix(res) ?colnames(combinedtable)<- NULL ?combinedtable #???? [,1] [,2]
2009 Mar 05
3
Dropping rows conditionally
Dear R-help team, I am getting addicted to using R but keep on getting many challenges on the way especially on data management (data cleaning). I have been wanting to drop all the rows if there values are `NA' or have specific values like 1 or 2 or 3. mdat <- matrix(1:21, nrow = 7, ncol=3, byrow=TRUE, dimnames = list(c("row1",
2012 Feb 14
4
Color cells of a matrix as in Excel
All, I frequently make spreadsheets in Excel in which I rank values in columns by stop-light colors (red is bad, yellow is OK, green is good). Image and heatmap expect a matrix in which all the data are in the same scale, but I frequently have different scales in different columns. ie. Column one runs from 1-10 while column 2 runs from 1-100. I thus need to define a separate color ramp for each
2007 Nov 12
1
update matrix with subset of it where only row names match
I guess this has a simple solution: I have matrix 'mat1' which has row and column names, e.g.: A B C row1 0 0 0 row2 0 0 0 .... rown 0 0 0 I have a another matrix 'mat2', essentially a subset of 'mat1' where the rownames are all in 'mat1' e.g.: B row3 5 row8 6 row54 7 I want to insert the values of matrix mat2 for column B (in reality it could be some or
2011 Nov 07
2
adjusting levelplot color scale to data
Hi guys, I have a matrix with values varying from approximately -0.7 to 0.33 that I want to create a heatmap/levelplot with. When I execute the levelplot function for my matrix, I end up getting colors that are adjusted to the max and min rather than around 0. In other words, ideally I would like to have a color ramp that goes from red (negative number), to white (0), to blue (positive);
2008 Dec 16
2
converting a data-frame by a defined rule
Hi, I have a data frame with several columns. Now I want to transfer the data into a new variable (also a data frame), but I only want a part of the data, defined by a rule ... for example; I have following data frame: row1 row2 row3 x 2 3 x 1 4 y 5 3 y 2 3 I know want a data frame, only with lines containing x in row1. I know how to do that for one row (f <-
2012 Mar 09
1
index values of one matrix to another of a different size
> Hello, > > Is this the fastest way to use indices from one matrix to reference rows > in another smaller matrix? I am dealing with very big data (lots of columns > and I have to do this lots of times). > > ######sample data ############## > vals = matrix(LETTERS[1:9], nrow=3,ncol=3) > colnames(vals) = c('col1','col2','col3') > rownames(vals)
2010 Sep 06
1
Creating named.list from two matrix columns
Hi Friends, I am new to R. On R utility class pages, creating "named.list" is described with this command : new("named.list",a=1,b=2) For large matrix having two columns, such as : "row1" 2334 "row2" 347 "row3" 379 ... I want to create a named.list like : $row1 [1] 2334 $row2 [1] 347 ... Can anyone explain how "named.list"
2014 Sep 26
2
[LLVMdev] Canonicalizing vector masking.
Hi, I received an internal test case from a game team (it wasn't about this in particular), and I was wondering if there was maybe an opportunity to canonicalize a particular code pattern: %inputi = bitcast <4 x float> %input to <4 x i32> %row0i = and <4 x i32> %inputi, <i32 -1, i32 0, i32 0, i32 0> %row0 = bitcast <4 x i32> %row0i to <4 x float>
2007 Dec 07
0
(PR#10500) Bug#454678: r-base-core: Crash when calling
I would say this was user error (insisting on editing non-existent rownames), although the argument is documented. You could argue that there are implicit rownames, but they would be 1, 2 ... not row1, row2 .... And rownames(mat) is NULL. For an interactive function the best solution seems to be to throw an error when the user asks for the impossible. I'll fix it for 2.7.0: it
2011 Jan 14
4
test
Hi, i have that table Thesis Day A B C 1 0 83.43 90.15 22.97 1 0 85.50 94.97 16.62 1 0 83.36 95.38 20.70 1 0 84.47 92.16 23.58 1 0 83.98 95.33 19.39 1 0 82.86 93.78 24.55 1 0 83.39 92.67 19.56 1 0 85.17 95.24 17.95 1 0 81.62 93.32 28.49 1 0 82.99 92.85 19.73 1 0 81.11 95.67 27.20 1 0 83.39 94.69 16.51 1 0 79.56 89.87 30.39 1 0 80.54 93.32 21.76 1 0 82.11 92.58 22.17 1 14 85.65 94.00 19.19 1 14
2013 Oct 25
0
[LLVMdev] Is there pass to break down <4 x float> to scalars
Liu Xin <navy.xliu at gmail.com> writes: > I think we are solving a same problem. I am working on shader language > too. I am not satisfied with current binaries because vector operations > are kept in llvm opt. > > glsl shader language has an operation called "swizzle". It can select > sub-components of a vector. If a shader only takes components "xy"
2009 Dec 27
4
how to create a simple loop ?
I have a 5-row matrix called “data”. There are headers. it look like this : Row 1 Row2 Row3 Row4 Row5 Line1 … … … … Line2 … … … … Line3 … … … … … Line 1838 … … … … I want to calculate several simple arithmetic means for Row5, that
2006 Mar 28
1
weights in glm (PR#8720)
Full_Name: Robert Pusz Version: 2.2.1 OS: Windows Submission from: (NULL) (157.25.9.126) Hello, In my opinion something is wrong with 'weights' option in glm. My code is following: ###begin of the code#### cl <- c(5012, 106, 3410, 5655, 1092, 1513, 557, 1351, 3133, 2063, 3257, 4179, 5582, 5900, 8473, 4932, 3463, 5596, 2262, 0, 2638, 1111, 4881, 4211, 6271, 5257, 6926, 6165, 0, 0,
2010 May 11
1
create a data.frame for aov
Hi R-experts, I try to find a way to transfer a matrix to a data.frame that is used as input of aov. can you give me advice for that? >mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("Col1", "Col2", "Col3"))) >mdat      Col1 Col2 Col3 row1    1    2    3 row2   11   12   13 ===>