Displaying 20 results from an estimated 1000 matches similar to: "polygon graph"
2008 Nov 04
1
perform Kruskal-Wallis test without using the built-in command in R
Hi,
again i am stuck in my presentation, and i have never learn R before in my
life but need this to be done, so please help me out for a favour:
http://www.nabble.com/file/p20333155/kew.dat kew.dat
run this in R and these comes up:
Month Year Rain
1 Jan 1900 74.400000
2 Feb 1900 80.500000
3 Mar 1900 23.600000
4 Apr 1900 23.600000
5 May 1900 25.100000
6
2013 Apr 01
0
ggplot2 label problem
I have a problem to plot label (Year) only for significant values (in this
case spoz and sneg).
I use this code, but don't work with labels.
library(ggplot2)
ggplot(data1, aes(x = Year, y = value,fill=type,width=1))+
geom_bar(stat="identity",position="identity")+
scale_y_continuous(breaks = round(seq(-100, 100, by = 10),10))+
theme_bw()
Thank you!
the data used is:
2013 Apr 08
2
How can I extract part of the data in a panel dataset?
Taking the Grunfeld data, which is built-in in R, for example,
(1)How can I construct a dataset (or dataframe) that consists of the data
of all firms in 1951?
(2)How can I calculate the average capital in each form over the period
1951-1954?
What I can imagine is to categorize the data by firm, and then select the
data between 1951 and 1954 for each firm, but how can I do it?
Thanks,
Miao
2010 Sep 22
2
Unique subsetting question
Hi all,
I'm looking at a large data set, and I'm interested in removing rows where
only one variable is duplicated. Here's an example:
> presidents
Qtr1 Qtr2 Qtr3 Qtr4
1945 NA 87 82 75
1946 63 50 43 32
1947 35 60 54 55
1948 36 39 NA NA
1949 69 57 57 51
1950 45 37 46 39
1951 36 24 32 23
1952 25 32 NA 32
1953 59
2012 Dec 17
1
subset handling
Dear Rui and UseRs,[a text file has also been attached, in case the format of my email is difficult to get]I am extremely sorry that I am bothering you once again, but I?ll have to get to the bottom of it. The following command
sp <- lapply(split(agg, agg$st), function(x) x[order(x$year, x$month), ])
gave me an output with monthly mean of population(as under). i am not able to apply
2013 Mar 29
1
problem with data
Hello all!
I have a problem with my data in R. When I want to plot the following data,
I have a problem with y scale. The maximum value is cc. 10 degrees and in R
is about 100.
I use this code:
fasy<-read.table("gridd1.txt",sep="\t",dec=",",header=T,row.names=1)
# here are the years:
x <- as.numeric(rownames(fasy))
# extract a series that you want to plot:
y
2016 Mar 12
0
Regression in strptime
OK, .Internal is not necessary to reproduce oddity in this area. I also see things like (notice 1980)
> strptime(paste0(sample(1900:1999,80,replace=TRUE),"/01/01"), "%Y/%m/%d", tz="CET")
[1] "1942-01-01 CEST" "1902-01-01 CET" "1956-01-01 CET" "1972-01-01 CET"
[5] "1962-01-01 CET" "1900-01-01 CET"
2011 May 30
0
gls and phi1 >1 (phi larger than one)
Dear all,
I am stuck with a problem that might be trivial for most of you (and
therefore is a bit embarrassing for me...):
I want to calculate a generalized least squares regression using two
time series (Y depending on X) with an autoregressive correlation
structure of order two (the data along time are given below). I use
'gls' from package 'nlme':
Calib.gls <- gls(Y~X,
2009 Jan 23
2
Dates in Common
I have two collections of dates and I want to figure out what dates they have
in common. This is not giving me what I want (I don't know what it is giving
me). What is the best way to do this?
Tom
> data1
[1] "1948-02-24 EST" "1949-04-12 EST" "1950-05-29 EDT" "1951-05-21 EDT"
[5] "1951-12-20 EST" "1953-01-22 EST"
2007 Sep 27
1
add a row to a data frame
Hi everybody,
I've a data.frame "d" like this:
0 2 4 6 8 10 12 14 16 X0 X2
X4
1945 350 NA NA NA NA NA NA NA NA 0.3848451 0.0000000 0.0000000
1946 408 NA NA NA NA NA NA NA NA 1.4202009 0.0000000 0.0000000
1947 511 NA NA NA NA NA NA NA NA 3.2540522 0.0000000 0.0000000
1948 342 215 NA NA NA NA NA NA
2013 Mar 13
2
merge datas
Hello all!
I have a problem with R. I try to merge data like this:
structure(c(2.1785, 1.868, 2.1855, 2.5175, 2.025, 2.435, 1.809,
1.628, 1.327, 1.3485, 1.4335, 2.052, 2.2465, 2.151, 1.7945, 1.79,
1.6055, 1.616, 1.633, 1.665, 2.002, 2.152, 1.736, 1.7985, 1.9155,
1.7135, 1.548, 1.568, 1.713, 2.079, 1.875, 2.12, 2.072, 1.906,
1.4645, 1.3025, 1.407, 1.5445, 1.437, 1.463, 1.5235, 1.609, 1.738,
1.478,
2019 Dec 15
0
[vhost:linux-next 12/12] drivers/vhost/vhost.c:1968:11: note: in expansion of macro 'min'
tree: https://git.kernel.org/pub/scm/linux/kernel/git/mst/vhost.git linux-next
head: b072ae74df177c3ad7704c5fbe66e3f10aad9d4e
commit: b072ae74df177c3ad7704c5fbe66e3f10aad9d4e [12/12] vhost: use vhost_desc instead of vhost_log
config: s390-debug_defconfig (attached as .config)
compiler: s390-linux-gcc (GCC) 7.5.0
reproduce:
wget
2013 Apr 07
2
group data in classes
Hello all!
I have a problem to group my data (years) in 10 years classes. For example
for year
year decade
1598 1590-1600
1599 1590-1600
1600 1590-1600
1601 1600-1610
---
my is like this>
[1] 1598 1599 1600 1601 1602 1603 1604 1605 1606 1607 1608 1609 1610 1611
1612
[16] 1613 1614 1615 1616 1617 1618 1619 1620 1621 1622 1623 1624 1625 1626
1627
[31] 1628 1629 1630 1631 1632 1633
2002 May 31
2
error in seq.POSIXt?
I am trying to extract only the winters (defined to be 01-Dec through
28-Feb) of daily data from 1948-2002. There are 90 days in each winter
season. I wrote the following code to gather the winter dates into a
single vector:
DJF <- NULL
for(year in 1949:1999) {
temp.begin <- strptime(paste("01/12", year-1, sep="/"), "%d/%m/%Y")
temp.end <-
2008 Oct 14
6
Doing a Task Without Using a For Loop
Assume that I have the dataframe "data1", which is listed at the end of this
message. I want count the number of lines that each person has for each
year. For example, the person with ID=213 has 15 entries (NinYear) for 1953.
The following bit of code calculates NinYear:
for (i in 1:length(data1$ID)) {
data1$NinYear[i] <- length(data1[data1$Year==data1$Year[i] &
2011 Feb 16
1
Timeseries Data Plotted as Monthly Boxplots
Hello, I'm trying to develop a box plot of time series data to look at the
range in the data values over the entire period of record.
My data initially starts out as a list of hourly data, and then I've been
using this code to make this data into the final ts array.
# Read in the station list
stn.list <- read.csv("/home/kbennett/fews/stnlist3", as.is=T, header=F)
# Read in
2004 Mar 09
0
Re: R-help Digest, Vol 13, Issue 8
On Mon, 8 Mar 2004 r-help-request at stat.math.ethz.ch wrote:
> Send R-help mailing list submissions to
> r-help at stat.math.ethz.ch
>
> To subscribe or unsubscribe via the World Wide Web, visit
> https://www.stat.math.ethz.ch/mailman/listinfo/r-help
> or, via email, send a message with subject or body 'help' to
> r-help-request at stat.math.ethz.ch
>
>
2016 Jun 02
1
[PATCH -next 2/2] virtio_net: Read the advised MTU
Hi,
[auto build test ERROR on next-20160602]
url: https://github.com/0day-ci/linux/commits/Aaron-Conole/virtio-net-Advised-MTU-feature/20160603-000714
config: i386-allmodconfig (attached as .config)
compiler: gcc-6 (Debian 6.1.1-1) 6.1.1 20160430
reproduce:
# save the attached .config to linux build tree
make ARCH=i386
Note: the
2016 Jun 02
1
[PATCH -next 2/2] virtio_net: Read the advised MTU
Hi,
[auto build test ERROR on next-20160602]
url: https://github.com/0day-ci/linux/commits/Aaron-Conole/virtio-net-Advised-MTU-feature/20160603-000714
config: i386-allmodconfig (attached as .config)
compiler: gcc-6 (Debian 6.1.1-1) 6.1.1 20160430
reproduce:
# save the attached .config to linux build tree
make ARCH=i386
Note: the
2011 Jun 08
1
R command window
Hello.
I'm a visually impaired statistician, working at the National Institute of Public Health in Denmark.
I would like to use R for some analysis and have succesfully installed version 2.13.0 on my Windows XP labtop.
I then would like to run R interactively but unfortunately the textfont of the command line in the R window is very hard for me to read. I use a special program called