similar to: starting html help for a package?

Displaying 20 results from an estimated 4000 matches similar to: "starting html help for a package?"

2008 Dec 03
3
alternative way to replicate()
Dear all, I'm looking for an alternative way to replicate the "2," string for an x number of times, and end up with one string containing "2," x times. I can partly achieve this using replicate(). > y <- rep("2,", times=3) > y [1] "2," "2," "2," The output that I am looking for is, however, "2,2,2,". I also tried
2011 Oct 03
2
extracting p-values in scientific notation
Dear all How does print.htest display the p-value in scientific notation? > (x <- cor.test(iris[[1]], iris[[3]])) Pearson's product-moment correlation data: iris[[1]] and iris[[3]] t = 21.65, df = 148, p-value < 2.2e-16 alternative hypothesis: true correlation is not equal to 0 95 percent confidence interval: 0.8270 0.9055 sample estimates: cor 0.8718 Above the p-value comes
2008 Oct 30
2
"A critique of R and S-PLUS"
Dear all, The other day I stumbled on this article, "A critique of R and S-PLUS" [1], and got curious on whether the points outlined are (still) valid. The article is quite old, dating 2004, but was updated several times. Regards, Liviu [1] http://fluff.info/blog/arch/00000041.htm -- Do you know how to read? http://www.alienetworks.com/srtest.cfm Do you know how to write?
2011 Aug 19
2
display only the top-right half of a correlation matrix?
Dear all Is there an easy way to display only one half (top-right or bottom-left) of a correlation matrix? > require(Hmisc) > rcorr(as.matrix(mtcars[ , 1:4])) mpg cyl disp hp mpg 1.00 -0.85 -0.85 -0.78 cyl -0.85 1.00 0.90 0.83 disp -0.85 0.90 1.00 0.79 hp -0.78 0.83 0.79 1.00 n= 32 P mpg cyl disp hp mpg 0 0 0 cyl 0 0 0 disp 0 0
2009 Oct 14
3
currency conversion function?
Dear all Is there any R function that would perform currency conversion using up-to-date exchange rates? I would be looking for a function that allows to download recent exchange rates (say, from Yahoo!) and then use these in converting currencies (say, USD to EUR). I am not sure whether r-sig-finance would be more appropriate, but the (off-)topic feels general enough to me. Thank you Liviu --
2011 Aug 10
3
convert 'list' to 'vector'?
Dear all How does one convert a "non-symmetric" list to a vector? See below: > x <- list() > x[[1]] <- letters[1:5] > x[[2]] <- letters[6:10] > x[[3]] <- letters[11:12] > x [[1]] [1] "a" "b" "c" "d" "e" [[2]] [1] "f" "g" "h" "i" "j" [[3]] [1] "k"
2009 Aug 20
4
expanding 1:12 months to Jan:Dec
Dear R users I would like to do some spreadsheet style expansion of dates. For example, I would need to obtain a vector of months. I approached in an obviously wrong way: > paste(01:12) [1] "1" "2" "3" "4" "5" "6" "7" "8" "9" "10" "11" "12" > as.Date(paste(01:12),
2009 May 15
4
replace "%" with "\%"
Dear all, I'm trying to gsub() "%" with "\%" with no obvious success. > temp1 <- c("mean", "sd", "0%", "25%", "50%", "75%", "100%") > temp1 [1] "mean" "sd" "0%" "25%" "50%" "75%" "100%" > gsub("%",
2012 May 05
3
alarm() doesn't beep
Dear all I'd like to make a beeping sound in R, but alarm() doesn't beep? I checked ?alarm but I couldn't find any pointers to system configuration. Any ideas? Regards Liviu > sessionInfo() R version 2.14.2 (2012-02-29) Platform: x86_64-pc-linux-gnu (64-bit) locale: [1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C [3] LC_TIME=en_US.UTF-8 LC_COLLATE=en_US.UTF-8 [5]
2012 Jul 10
3
fill 0-row data.frame with 1 line of NAs
Dear all Is there a simpler method to achieve the following: When I obtain an empty data.frame after subsetting, I need for it to contain one line of NAs. Here's a dummy example: > (.xb <- iris[ iris$Species=='zz', ]) [1] Sepal.Length Sepal.Width Petal.Length Petal.Width Species <0 rows> (or 0-length row.names) > dim(.xb) [1] 0 5 > (.xa <-
2011 Aug 10
2
round() a data frame containing 'character' variables?
Dear all It is difficult to use round(..., digits=2) on a data frame since one has to first take care to remove non-numeric variables such as 'character' or 'factor': > head(round(iris, 2)) Error in Math.data.frame(list(Sepal.Length = c(5.1, 4.9, 4.7, 4.6, 5, : non-numeric variable in data frame: Species > head(round(iris[1:4], 2)) Sepal.Length Sepal.Width Petal.Length
2009 Aug 26
2
faulty formatting of toLatex(sessionInfo())
Dear all I am writing an Sweave document and have encountered formatting issues with the "locale" part of toLatex(sessionInfo()). The fact that there is no spaces between the various "locale" variables means that LaTeX cannot easily find an appropriate place to break the lines, and some will get printed off screen. Below is the text output, and this .pdf document [1] shows the
2011 Mar 06
4
sorting & subsetting a data.frame
Dear all This may be obvious, but I cannot get it working. I'm trying to subset & sort a data frame in one go. x <- iris x$Species1 <- as.character(x$Species) ##subsetting alone works fine with(x, x[Sepal.Length==6.7,]) ##sorting alone works fine with(x, x[order(Sepal.Length, rev(sort(Species1))),]) ##gets subsetted, but not sorted as expected with(x, x[(Sepal.Length==6.7) &
2009 Dec 21
2
checking Rd cross-references ... WARNING
Dear all I am getting this strange error when checking my package. Would you have an idea what causes it? Thank you Liviu * checking Rd cross-references ... WARNING Error in .find.package(package, lib.loc) : there is no package called 'KernSmooth' Calls: <Anonymous> -> lapply -> FUN -> .find.package Execution halted > sessionInfo () R version 2.10.0 (2009-10-26)
2010 Oct 23
1
command to start R and Rcmdr?
Dear all I would like to start R with Rcmdr from the cli, without tweaking Rprofile.site. This has been discussed in the past [1], but I don't see a solution that (1) could be used with any working directory and (2) would avoid starting Rcmdr on every R start-up. Personally I tried the following, which starts R but not Rcmdr liv at liv-laptop:~$ R --interactive -e 'require(Rcmdr)'
2011 Nov 24
2
proper work-flow with 'formula' objects and lm()
Dear all I have a work-flow issue with lm(). When I use > lm(y1~x1, anscombe) Call: lm(formula = y1 ~ x1, data = anscombe) Coefficients: (Intercept) x1 3.0001 0.5001 I get as expected the formula, "y1 ~ x1", in the print()ed results or summary(). However, if I pass through a formula object > (form <- formula(y1~x1)) y1 ~ x1 > lm(form, anscombe) Call:
2011 Apr 07
1
plyr workaround to converting by() to a data frame
Dear all Is there a clean plyr version of the following by() and do.call(rbind, ...) construct: > df<-data.frame(a=1:10,b=11:20,c=21:30,grp1=c("x","y"),grp2=c("x","y"),grp3=c("x","y")) > dfsum<-by(df[c("a","b","c")], df[c("grp1","grp2","grp3")], range) >
2012 Apr 10
1
plyr: set '.progress' argument to default to "text"
Dear all Is it possible to set globally the option .progress = "text" to all the apply functions in 'plyr'. For example, current default is daply(..., .progress = "none"). I would like to set it to daply(..., .progress = "text"), so as to avoid writing the argument every time I call such a function. I looked into ?daply and ?create_progress_bar without much
2011 Nov 24
2
understanding all.equal() output: "Mean relative difference"
Dear all How should one parse all.equal() output? I'm specifically referring to the 'mean relative difference' messages. For example, > all.equal(pi, 355/113) [1] "Mean relative difference: 8.491368e-08" But I'm not sure how to understand these messages. When they're close to 0 (or 1xe-16), then it's intuitive. But when they're big, > all.equal(1, 4)
2009 Jun 02
2
variance does not equal serial covariance of lag zero?
Dear all, Does this make any sense: var() = cov() != acf(lag.max=0, type="covariance")? I have daily data of IBM for May 2005, and I'm using the logarithmic return: > ibm200505$LRAdj.Close [1] NA 0.0203152 0.0005508 -0.0148397 -0.0025182 0.0092025 -0.0013889 [8] 0.0098196 -0.0103757 -0.0274917 0.0005716 -0.0159842 -0.0074306 0.0091710 [15] 0.0002898 0.0226306