similar to: categorization

Hi, new to R and ggplot2. I've been trying to get a facet plot in which the order of the facets is as I require, rather than ordered numerically, alphabetically, by Roman numerals, mean (answers to these were posted here after much searching). Here's some test code to demonstrate what I get. series = c('C2','C4','C8','C10','C15','C20') ids =

Hi I am using the following script to average a set of data 0f 62 columns into 31 colums. The data consists of values of ln(0.01) or -4.60517 instead of NA's. These need to be averaged for each row (i.e 2 values being averaged). What I would I need to change for me to meet the conditions: 1. If each run of the sample has a value, the average is given 2. If only one run of the sample has a

Hi all, Could someone tell me how to split a word. c("AA") to c("A","A") Thanks! Phoebe [[alternative HTML version deleted]]

Ultimately my aim is to get a plot of density faceted by 2 factors with a horizontal boxplot overlaid on each density plot in the grid to indicate summary stats. So I've been experimenting with creating boxplots and density plots. Here's some representative data. series = c('C2','C4','C8','C10','C15','C20') ids =

Hi all, I'm hoping to add texts into a plot. I'm using text() to do it. I wonder if the text() allow me to make the text vertically printed? Thanks in advance for help, phoebe [[alternative HTML version deleted]]

I have 8 cofactors possibly affecting one and only one variable. I make conditional histograms: <-pdf(file="tst3.pdf",paper="special",width=36,height=36) <-histogram(~Oversized|dat$c1*dat$c2*dat$c5*dat$c6*dat$c7*dat$c8*dat$c9*dat$c10,nint=21,layout=c(32,8),data=dat,type="count") <-dev.off() This works (compliments to R developers!) but it does generate a

hello, i can't figure out how to set position of panels of my stripplot - i`d like the panels of one level of the factor stage (nr. of panels within each stage, A: 12, B: 12, C: 12, D: 4, each panel representing a site) to be in one column, with A to D from left to right and with descending site.nr at each row. like: A1 B1 C1 D1 A2 B2 .. .. A3 .. .. .. how is this achieved? any help

Hi all, Is there a function that allow me to concatenate each value in a vector to a string? x<-c("a","b","c","d") output string = a+b+c+d Thanks, phoebe [[alternative HTML version deleted]]

Hi All, I have problem about the factor features. I read in a .cvs file, a column which is supposed to be numeric, but it becomes factor level data after reading in. mydata[,"newXaxis"] [1] 0 0.430010601 11.23198508 25.00940297 37.75338045 45.98289639 [7] 48.92328133 52.51142822 61.12359751 63.85832121 70.98927949 77.16550181 [13] 97.73545713 113.6588007 118.6588007

Hi, my data set is data.frame(id, yr, y, l, e, k). I would like to estimate Lee and Schmidts (1993, OUP) model in R. My colleague wrote SAS code as follows: ** procedures for creating dummy variables are omitted ** ** di# and dt# are dummy variables for industry and time ** data a2; merge a1 a2 a; by id yr; proc sysnlin maxit=100 outest=beta2; endogenous y; exogenous l e k

1: x86/mwait_idle: remove assumption of one C-state per MWAIT flag 2: x86/mwait_idle: export both C1 and C1E 3: x86/mwait_idle: initial C8, C9, C10 support Signed-off-by: Len Brown <len.brown@intel.com> Signed-off-by: Jan Beulich <jbeulich@suse.com>

Hi there, I would like to draw a scatter plot and fit a smooth line by loess. Below is the data. However, the curve line started from 0, which my "resid" list doesn't consist of 0 value. It returned some warnings which I don't know if this is the reason affecting such problem. Here I also attached the warning messages. Please let me know if there is a solution to fix this. Thank

hello, i need to calculate ci's for each of 4 groups within a dataset, to be able to infere about differences in the variable "similarity". the problem is that data within groups is dependent, as assigned by the blocking-factor "site". my guess was to use a block bootstrap but samples within in these blocks / sites are not of same length. i was not able to find a method to

Hi, Can someone tell me how to draw a histogram for the following summary? Richard Minnie Albert Helen Joe Kingston 12 33 56 67 15 66 The summary tell that Richard has occurrence 12, Minnie has occurrence 33, and so on. I would like to view this summary in a histogram. I want the X-axis be the person name (Richard, Minnie, ....), Y-axis be the

hello, i'd appreciate help with my glmer. i have a dependent which is an index (MH.index) ranging from 0-1. this index can also be considered as a propability. as i have a fixed factor (stage) and a nested random factor (site) i tried to model with glmer. i read that it's possible to use a quasibinomial distribution, for this kind of data, which i than actually did - but firstly (1)

Hi: After compiling rsync2.5.6 using on SVR4 on Intel HW, Please help # ./rsync --version rsync: --version: unknown option rsync error: syntax or usage error (code 1) at main.c(994) # ./rsync --help Segmentation Fault - core dumped Here is log of compilation. Script started on Sat Jun 21 05:56:15 2003 # make cc -I. -I. -g -DHAVE_CONFIG_H -I./popt -c rsync.c -o rsync.o NCR High

Hi all, I would like to check if a string contains "." in it. If yes, I would like to know the position of "." in the string. Eg: X<-"NM1236.3" In above example, "." is at position 7. I tried functions grep() and match(). It seems they couldn't detect ".". Thanks in advance for your help, Sityee [[alternative HTML version deleted]]

Hi all, I'm wondering if there is a function that can return summary statistics: N=total number of observation, # missing, mean, median, range, standard deviation. As I know, summary() returns some of info I've mentioned above. Thanks, SY [[alternative HTML version deleted]]

I am trying to code the following excel formula in R. a b c Result Formula 1 10 0.1 #N/A IF(B2<20,NA(),C2+IF(ISERROR(D1),0,D1)) 2 20 0.2 0.2 IF(B3<20,NA(),C3+IF(ISERROR(D2),0,D2)) 3 30 0.3 0.5 IF(B4<20,NA(),C4+IF(ISERROR(D3),0,D3)) 4 40

Hi all, Thanks for Aleksandar Beserminji great job: https://reviews.llvm.org/D50437 It is not easy to reproduce the LLVMBUG-38221[1] by building OpenJDK8, it needs some workaround https://raw.githubusercontent.com/xiangzhai/jdk8u-dev/master/Workaround-compile-with-llvm.patch LLVM toolchain[2] is just able to compile OpenJDK8 for mips64el now: http://hg.loongnix.org/ 1.