similar to: Turn dates into age

say i have a column of data like this... 2 3 4 2 1 6 6 4 7 and i want it in three columns like this 226 314 467 ...so i can make a contour plot. How do i do this? -- View this message in context: http://old.nabble.com/one-long-column-of-data--%3E-three-small-columns-tp26163165p26163165.html Sent from the R help mailing list archive at Nabble.com.

hello folks, Im trying to clean out a large file with data i dont need. The column im manipulating in the file is called "legal_status" There are three kinds of rows i want to remove. Those that have "Private", "Private (Op", or "Unknown" in the legal_status column. I wrote this code but i get errors and it says im missing a TRUE/ False thingy...im

i just found the following list, i wondered if anybody could add to this as i have to characterize a large data set and am new to R...the list below was so helpful....can you add to this??? Just to forestall confusion amongst those who would like to use one of the functions called "describe"... Hmisc package - describe numeric name count of observations count of missing

if ive got an incomplete data set thats got thousands of rows and 80 columns with random missing fields...like this say... 3 b 3 4 1 1 x 2 ? how do i turn it into.... 3 b 3 4 missing 1 1 x 2 ...i.e., i want to insert the word "missing" into the fields that are empty? -- View this message in context:

can you do Logistic regression in R, if so how do you do it and how do you test the fit of a model? -- View this message in context: http://n4.nabble.com/Logistic-regression-tp1059870p1059870.html Sent from the R help mailing list archive at Nabble.com.

I have 20 columns of data, and in column 5 I have a value of 17600 but I dont know which row this value is in (i have over 300,000 rows). I'm trying to do 2 things: 1) I want to find out which row in column 5 has this number in it. 2) Then I want to print out that row with all the column headers so i can look at the other parameters in the row that are associated with this value. How do i

Is this book worth its dollar? If so, why?, if not, why not? Cheers. -- View this message in context: http://n4.nabble.com/Ggplot2-Elegant-Graphics-for-Data-Analysis-Use-R-2009-Paperback-tp931702p931702.html Sent from the R help mailing list archive at Nabble.com.

Please help me persuade IT to install R on my computer! All suggestions welcome. Our IT department run scared when you mention software that they have no working experience of. I need to know the pros and cons of having R on corporate desktops. Please no funny stuff, this is quite a serious issue for us. Pros and cons would be good. Thanks. -- View this message in context:

Hi all, I am strugling with date formates and caliculating diferent operations like different between 2 dates and getting minimum in vector of dates that is i m working with dates in formate "6/22/1992 12:00:00 AM" and the vector is [1] 6/4/1992 12:00:00 AM 2/13/1992 12:00:00 AM 6/19/1992 12:00:00 AM [4] 2/11/1992 12:00:00 AM 6/22/1992 12:00:00 AM 10/3/1991

I want to go through a column in data called date_abandoned....data["date_abandoned"]....and remove all the rows that have numbers greater than 1,010,000. The dates are in the format 20091114 so i'm just going to treat them as numbers for clean up purposes. I know that i use subset but not sure how to proceed from there. -- View this message in context:

I want to do a non homogeneous poisson process model in R. Any advice, or know of places where i can get some, ive googled it but nothing came up relating to R. -- View this message in context: http://old.nabble.com/non-homogeneous-poisson-process-tp26378037p26378037.html Sent from the R help mailing list archive at Nabble.com.

> exampledata <- rnorm(10000) > summary(exampledata) Min. 1st Qu. Median Mean 3rd Qu. Max. -4.030000 -0.666200 -0.023390 -0.009384 0.664700 4.092000 > desc <- function(mydata) { + require(e1071) + quantls <- quantile(x=mydata, probs=seq(from=0, to=1, by=0.25)) + themean <- mean(mydata) + thesd <- sd(mydata) + kurt <-

Hi WizaRds, (I've cross-posted to r-sig-finance because a lot of people there use 'zoo' objects). I'm trying to plot 2 time series lined up with par(mfrow=c(2,1)), so that the time index is the same for the two series. The data have monthly frequency. An example will illustrate: # data for these dates (monthly frequency) do not have NAs: require(zoo) monthly.dates<-

Hello everyone, I have a data generated in a way similar to the following library(chron);library(zoo) date<- seq(as.Date("1990-01-01"),, as.Date("2000-12-31"), by = 1) obs<- zoo(rnorm(length(date), mean = 10, sd = 2.5), order.by = date) monthly<- function(date) as.Date(as.yearmon(Date)) result<- data.frame ( Date = obs = aggregate(obs, monthly, sum)) Now, I want

I'm not sure how to best explain what I am after but here goes. I have a data frame with 2 geographical factors. One is the major region the other is the component regions. I am trying to process all the regions at the same time without using "for". So I need (think, I do) a list of matrices each structured according to the number of subregions within each region. So is there a

Hi, I have the next procedure: t1<-data.frame(table(substr(names(subset(lasker[[1]], lasker[[1]] >= 4)), 1, 7))) t1[1:5,] Var1 Freq 1 1988-02 3 2 1988-03 1 3 1988-04 1 4 1988-05 2 5 1988-06 3 How to make a new list?, dataframe? having 189 elements in the 'lasker' list: > str(lasker[[1]]) 'table' int [, 1:1274] 1 1 3 2 1 5 4 1 1 4 ... -

I need some help with sub-setting my data.  I am trying to divide a data frame into multiple data frames based on the year collected, and stored in a list with each new data frame labeled with "year X" where X is the year the data was collected.  When I run my current code I get nine error messages stating "In one_year[name] <- myear :  number of items to replace is not a

Hi, Having a dataframe 'l1' (dput output is below): >dim(l1) 1274 2 >l1[1:12,] Var1 Freq 1 1988-01-13 1 2 1988-01-16 1 3 1988-01-20 3 4 1988-01-25 2 5 1988-01-30 1 6 1988-02-01 5 7 1988-02-08 4 8 1988-02-14 1 9 1988-02-16 1 10 1988-02-18 4 11 1988-02-24 2 12 1988-03-04 1 I want to extract the times

Hi all, I have been chipping away at a problem I encountered in calculating rates per year from a moderately large data file (46412 rows). When I ran the following command, I got obviously wrong output: interval<- c(NA,as.numeric(diff( strptime(mkdf$MEAS_DATE,"%d/%m/%Y")))/365.25) The values in MEAS_DATE looked like this: mkdf$MEAS_DATE[1:10] [1] 1/5/1962 1/5/1963

Hello everyone. Just have a question , cant figure out how to make this histogram. I have this table, that i stored in a variable name new.data2. Table looks like this Year GeoArea SmpNo Month Gear Maturity Length Age YearC 1989 1 362 10 22 1 225 1 1988 1991 1 267 10 10 1 191 1 1990 1991 1 267 10 10 1 202 1 1990 1992