similar to: Search values and create a new matrix

Displaying 20 results from an estimated 1000 matches similar to: "Search values and create a new matrix"

2009 Jul 21
3
writte file doubt
Hi I wrotte this function but when I get the "tmp.xls" file it shows data in a rare way. I mean not appears a matrix with 2000 rows and 100 columns. Can anyone help me, guide me? kim<-function(){ tmp<-randz<-matrix(rnorm(200000, mean=0,sd=0.01 ),2000,100); dim(tmp) write(tmp,file="tmp.xls") Thanks in advance. On the other hand, everytime I execute a function
2009 Jul 27
2
pairs plot
Hi all, I want to plot trough pairs() plot a matrix with 4 columns. I want to make a trhee plot in a graph. Plotting pairs colum 2,3,4 on y axis and 1 on X axis. You mean (a plot with three graphs) ommitting the first pair with itself. And only the pairs with colum 1 with the other not all pairs. I. e. this matrix 4177 289390 8740 17220 3907 301510 8530 17550 3975 316970 8640 17650 3651 364220
2017 Jun 02
1
Upper bands and lower bands
Sorry, For me a vector is a matrix with mx1 dimmensions. But it is true that it is not the way I correctly must talk in R. Can you guide me in what I?m trying to do? I?m trying to find what I want in Excel using something like a parabolic function but dind?t get yet (then to try to replicate in R). 2017-06-02 7:01 GMT+02:00 Bert Gunter <bgunter.4567 at gmail.com>: > Bert Gunter >
2017 Jun 01
4
Upper bands and lower bands
Hi all I want to add a band of fluctuaci?n (exponential decreading) to a linear deacrecing values Imagine: I have a matrix like c(10,9,8,7,6,5,4,3,2,1) The thing is I want two new lines so that the m?ximum value of the new colum on the m?ximum is from 10% to 5% higher and the same lower for the m?nimum the final two matix will be something like c(10+0.10*10,9+0.089*9,8+0.075*8.....,1+0.05*1)
2009 Jul 29
1
Add a line in a Pairs2 and mark the axis length
Hi, I have finally installed TeachingDemos trough zip file and installed on lbrary. One new question: I want to draw a line (like abline) on diagonal or the result of running a ols. How can I do it. On the other hand, I want to mark the length on each sub plot y axis. It is possible? My function is sca<-function(){ z2<-read.table("Ase.txt",header=T)
2017 Jun 02
0
Upper bands and lower bands
Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Thu, Jun 1, 2017 at 11:20 AM, Pedro p?ramo <percentil101 at gmail.com> wrote: > Hi all > > I want to add a band of fluctuaci?n (exponential decreading) to a linear > deacrecing
2009 Dec 11
2
Data
Hi all, Imagine I have a matrix and the first colum is a list that repeats the same names, I want to sum the second column on each unique name on first column. Imagine this: Pepe 2 Pepe 3 Pepe 4 Jose 2 Jose 5 Manuel 4 Manuel 2 I want to make a new matrix that calculates and recognizes that there are 3 different names ans sum second column. But a priori I don´t know the list of the different
2011 Jun 18
1
Required libraries
Hi all, I´m trying to "recuperate" old files I wrotte and I´m trying to execute on R version 2.13.0 (2011-04-13), the thing is I execute my old file and nothing happens...I suposse I need to install some library but there no appears no message, no text telling "required grafics library" or something like that. How can I see wich libraries need to execute a file? Many thanks
2009 Jan 26
2
Getting data from a PDF-file into R
Hello I have around 200 PDF-documents, containing data i want organized in R as a dataframe. The PDF-documents look like this; http://www.nabble.com/file/p21667074/PRRS-billede%2Bmed%2Bfarver.jpeg or like this; http://www.nabble.com/file/p21667074/PRRS-billede%2Bmed%2Bfarver%2B2.jpeg So i want to pull out the data in coloured boxes it become organized like this (just in R instead of
2012 Aug 08
3
help, please! matrix operations inside 3 nested loops
hello, this is my script: #1) read in data: daten<-read.table('K:/Analysen/STRUCTURE/input_STRUCTURE_tab_excl_5_282_559.txt', header=TRUE, sep="\t") daten<-as.matrix(daten) #2) create empty matrix: indxind<-matrix(nrow=617, ncol=617) indxind[1:20,1:19] #3) compare cells to each other, score: for (s in 3:34) { #walks though the matrix colum by colum, starting at
2011 May 04
1
problem with package "adapt" for R in Mac
Hi, How i can install the package "adapt" in some version of R for mac? i try in 2.13, 2.9,2.7 and other previous versions... and nothing happens. and another question: There are some packages that do the same but that it is implemented for mac? (calculate integrals in 2 or more dimmensions). help me please, it's for an important work. greetings. -- Matías Hernán Ramírez
2008 Nov 20
1
convert factors to numbers
Hello, I have a problem with reading a csv-file. One colum of the inputfile consists of characters and numbers. After reading the csv-file I create a new dataframe by dividing the values of that colum into more colums (then a colum contains just characters or numbers) but the numbers are converted to factors. How can I create the new dataframe without having the numbers converted to factors?
2005 Nov 24
4
write.csv
hallo, i have a problem by writing a csv file the first colum is filled with index numbers from 1 to n. i have to unique two csv files once a week while one file is always the same. can anybody tell me, how to write the dataset into a csv file without the first row of the indexnumbers. x[,-1] does not wok as it eliminates the first "interesting" colum. col.names is not accepted by r
2010 Oct 15
4
Set value if else...
Hi I want to set a variable to either 1 or 0 depending on an value of a dataframe and then add this as a colum to the dataframe. This could be done with a loop but as we are able to do questions on a complete row or colum without a loop it would be sweet if it could be done. for example: table: Name Age Joel 24 agust 17 maja 40 and so on... And what I want to do is a command that
2009 Dec 01
4
median for time data
Hi everybody How do I do to calculate the median and average of a colum of time data like this: "8:50:10". I also need to plot the time difference between two colums Thanks a lot -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p932287.html Sent from the R help mailing list archive at Nabble.com.
2009 Jun 03
2
how can I ordinal regression??
What function and package I use to conduct ordinal regression?? My data is composed 2colums and 180rows. The first colum indicate level of mass and second colum is intensity. So, I want to calculate how much intensity are related mass. [[alternative HTML version deleted]]
2009 Jun 25
1
lm
Hi all, I want to make multiple least squares estimation on two matrix (without intercept) imagine matrix "a" and matrix "b", I want to "regress" each colum on matrix "a" (dependent variable) on each column of matrix b, I mean, regress first colum on a to first column on b. Second column on a to second column on b. Imagine "a" and "b"
2013 Dec 06
2
Using assign with mapply
I have a data frame whose first colum contains the names of the variables and whose second colum contains the values to assign to them: : kkk <- data.frame(vars=c("var1", "var2", "var3"), vals=c(10, 20, 30), stringsAsFactors=F) If I do : assign(kkk$vars[1], kkk$vals[1]) it works : var1 [1] 10 However, if I try with mapply
2010 Aug 02
1
lm length
Hi all, I wanto to run a plot about the levels of a variable parting on an ols regression. The regression in done on the rate of return of the variable. Imagine R_{t}=a+b*R_{t-1} So If P, the "estimated" price would be P_{t}=P_{t-1}*R_{t} Imagine that I obtain lm fitted values and the original R_{t}, R_{t-1} are [1000,1] dimmension... How it is posible to obtain also 1000,1 fitted
2008 Mar 22
2
counting values on one colum only
Hi all: Can someone help me count the number of rows with values in colum "a" only. assume the name of my dataframe is "weekly" I was trying i<- nrows(weekly$a) i but returns 7 when it should be 4. Thanks a b c d 27.000 27.000 1.569 0.013 160.000 27.000 1.632 0.013 146.000 27.000 1.830 0.015 70.000 27.000 2.475 0.019