similar to: Calculate Averages for time data

Hello My data contains following columns: 1st column: Posts (GM, Secretary, AM, Office Boy) 2nd Column: Dept (Finance, HR, ...) 3rd column: Tasks (Open the door, Fix an appointment, Fill the register, etc.....) depending on the post 4th column: Average Time required to do the task So the sample data would look like Posts Dept Task Average

Hello I am unable to find a graph for my data, My data contains following columns: 1st column: Posts (GM, Secretary, AM, Office Boy) 2nd Column: Dept (Finance, HR, ...) 3rd column: Tasks (Open the door, Fix an appointment, Fill the register, etc.....) depending on the post 4th column: Average Time required to do the task So the sample data would look like Posts Dept

Hello I have to import 2 txt files into R. 1 file contains the data and the other contains the header, column headings, datatypes and labels for the data. I have 2 problems: 1) my data file has mixed type of data e.g. 1 2 3 4 5 3-5 02/04/06 3 4 5 and so on, the data file is tab separated. when I import it, the data is getting stored in one single variable say V1. I need to separate it into rows

Hello Everyone I want to plot Moasic Plots, I have tried them using iplots package (using imosaic). The problem is the names dont get alligned properly, is there a way to a align the names and provide legend in Mosaic plots using R? Also I would like to know any other packages using which I can plot Mosaic Plots Thank you in advance Sunita -- View this message in context:

Hello I have 2 datasets say Data1 and Data2 both are of different dimesions. Data1: 120 rows and 6 columns (Varname, Vartype, Labels, Description, ....) The column Varname has 120 rows which has variable names such id, age, gender,.....so on Data2: 12528 rows and 120 columns The column names in this case are V1, V2, ......... V120 (which are default names in R when we say head=F in read.csv)

Hello My dataset is as follows: jobno recruits 1100 18 1200 1 1850 5 2100 190 2789 25 3000 1 . . . . the dataset has 130 rows I want to plot barplot from left side and cumulative curve from right side in one graph itself using layers in ggplot2. I sorted the recruits 1st in decreasing order

Hello In STATA there is command which has regression with clustering option. Can anyone tell me what is the command for the same in R for example in STATA its regress Height Weight, cluster(id) Thanks in Advance Regards Sunita -- View this message in context: http://www.nabble.com/Regression---cluster-option-in-STATA-tp25241948p25241948.html Sent from the R help mailing list archive at

Hello (this might be a very simple question) My data is as follows (table name is student) Year StudentsPassed 1 2000 300 2 2001 360 3 2002 450 4 2003 450 5 2004 270 6 2005 280 7 2006 400 8 2007 270 I want to plot a barplot so for this If I use barplot(students) it says "Error in barplot.default(students) : 'height' must be a vector or a

Hi All, I am attempting to work with some data from loggers. I have read in a .csv exported from MS Access that already has my dates and times (in 24 clock format), (with StringsAsFactors=FALSE). > head(tdata) LogData date time 1 77.16 2008/04/24 02:00 2 61.78 2008/04/24 04:00 3 75.44 2008/04/24 06:00 4 89.43 2008/04/24

Hello, I'm very new to R, and so my question is simple. I have data record with 80 years of daily temperatures in one long string. The dates are also recorded, in YYMMDD format. I'd like to learn an elegant simple way to pull out the annual averages. (Obviously, every 4th year has 366 days.) I know I can set up a formal loop to create annual records and then average. But R

Hello Everyone I am new to R I would like to know how to deal with Time Variable. If I have a column of containing Time data in the format of hh:mm:ss such as 00:56:45, 01:24:36, 01:41:25, and so on...... I could find averages for this column using the Chron package. But now I need to plot a graph so I need to convert this Time variable to numeric. My data is as follows: Activity

New user here. My goal is pull daily averages from a long dataset. I've been working with some code I got from this list from https://stat.ethz.ch/pipermail/r-help/2009-March/191302.html The code how I have been using it is as follows: library(zoo) library(chron) DB<-read.table("/Users/me/Desktop/R/data.csv", sep=",", header=TRUE, as.is =TRUE) z<-zoo(LTER6$temp,

Hello Everyone,I think this is a very simple problem, I have been struggling with it for a few days now. I have a 10-year daily data in the following format. Date A B C D E 1978-10-22 18 20.64 0.0 0.176 -1.76 1978-10-23 15 17.06 0.4 0.147 2.52 1978-10-24 3 7.588 0.0 0.068 -6.86 1978-10-25 9 11.491 0.0 0.102

Hello, I have been attempting to write a script that automatically calculates time intervals from a list of hh.mm.ss.ms timestamps. Should be easy, but I keep running into problems. Any help would be greatly appreciated!! Problems: 1. If I parse the timestamp, it doesn't always return the digits after the decimal 2. If I subtract .5 - .955 (as in 19:22:0.5 - 19:21:59.955), then I get a

Dear help list, I have a timestamp in as a chron object: > (x <- chron(dates = c("12/02/11", "22/11/11"), + times = c("07:30:00", "04:00:00"), + format = c(dates = "d/m/y", times = "h:m:s"))) [1] (12/02/11 07:30:00) (22/11/11 04:00:00) Now I want to shift the timestamp by 06:30 (hh:mm) backwards, to get

Full_Name: Dennis Wolf Version: 1.9.0 OS: Mac OS 10.3.3 Submission from: (NULL) (160.91.76.23) platform powerpc-apple-darwin6.8 arch powerpc os darwin6.8 system powerpc, darwin6.8 status major 1 minor 9.0 year 2004 month 04 day

I a have a text file where every line is like that: "2007-12-03 13:50:17 Juan Perez" ("yy-mm-dd hh:mm:ss First Name Second Name") I would like to make a data frame with two column one for date and the other one for name. When I use read.delim it was transformed in a data frame with 4 colums. Bye, Sebasti?n.

Not sure if there is an R way to do this or a regular express way, but here is what I am trying to do. I've got lots of data where the format is HH:MM:SS, but I need to format it like HH:MM:00, i.e. round the second down to zero. What is the best way to do this? Thanks again. Jason

Hello all, I'm trying to use zoo.read but can't figure out how to deal with the time format. (example below) would be nice if someone could help. best regards, Immanuel --------------------------- L <- "Date,Time,Open,High,Low,Close,Up,Down 05.02.2001,00:30,421.20,421.20,421.20,421.20,11,0 05.02.2001,01:30,421.20,421.40,421.20,421.40,7,0

Has anyone written a function that will print a difftime in the form: hh:mm:ss or yy-mm-dd hh:mm:ss depending on the actual size. (sloppy notation for months/minutes, but surely you get the point). Bendix ---------------------- Bendix Carstensen Senior Statistician Steno Diabetes Center Niels Steensens Vej 2 DK-2820 Gentofte Denmark tel: +45 44 43 87 38 mob: +45 30 75 87 38 fax: +45 44 43 07