similar to: Incremental ReadLines

** Disclaimer: I'm looking for general suggestions ** I'm sorry, but can't send out the file I'm using, so there is no reproducible example. I'm using read.table and it's taking over 30 seconds to read a tiny file. The strange thing is that it takes roughly the same amount of time if the file is 100 times larger. After re-reviewing the data Import / Export manual I think

HI, Using c11<- 0.01 c12<- 0.01 c1<- 0.10 c2<- 0.10 One possible problem is that: dim(res5) #[1] 513? 20 res6<-aggregate(.~m1+n1+m+n,data=res5[,c(1:6,9:12,21:24)] ,max) #Error in `[.data.frame`(res5, , c(1:6, 9:12, 21:24)) : ?# undefined columns selected A.K. ________________________________ From: Joanna Zhang <zjoanna2013 at gmail.com> To: arun <smartpink111 at

Does anyone know if Is there a way to manually install RSPython? I get this error when I try to run the script from my DOS prompt. V:\>R CMD INSTALL -c C:/Users/gene.leynes/Downloads/RSPython_0.7-1.tar.gz * installing to library 'C:/Users/gene.leynes/Documents/R/win-library/2.13' * installing *source* package 'RSPython' ... **********************************************

What should have been a routine upgrade to ZFS 0.6.4.1-1.el6.x86_64 somehow failed, and now I've lost access to a 2T raidz2 array. I've tried removing all zfs and related packages (spl*), then starting fresh. For reasons that have have nothing to do with this problem (I don't think), I'm still booted to kernel 2.6.32-431.29.2.el6.x86_64, and there are no other kernels installed.

Hello, I was having trouble passing in command line options when doing an package install earlier. >From An Introduction in R > In addition, you can use25<http://cran.r-project.org/doc/manuals/R-intro.html#fn-25>options > --arch=, --no-environ, --no-init-file, --no-site-file and --vanillabetween > R and CMD: these affect any R processes run by the tools. (Here --vanillais

Dear all, After struggling for some time with *apply() and eva() without success, I decided to ask for help. I have 3 lists labeled with, each contains 3 different interpolation functions with identical names: > names(missgp0) [1] "spl.1mb" "spl.2mb" "spl.5mb" > > names(missgp1) [1] "spl.1mb" "spl.2mb" "spl.5mb" > >

Hi R-users, I inted to make multiple plots using for loop. The question is how can I adjust the left hand side margin of the plot according to the names.arg argument in barplot2. In every plot I have different annotations in the y axis and they vary in length. Now when I have fixed margins opar <- par(mar=c(3,15,0,2)... I get the same margins in all of the plots. That leaves lots of white

I successfully combined my data frames, and am now on my next hurdle. I had combined the data and quarter, and used tapply to count the entries for each unique date/quarter pair. ar= tapply(ewrgnd$gw, list(ewrgnd$dq), sum) #for each date/quarter combination sums the gw (which are all 1) dq=row.names(ar) spl=strsplit(dq) But I need to split them back into the separate date and quarter. So I used

I am not certain that this is the right place to post this, but maybe some kind soul can point me in the right direction if not. And I apologize if this is the wrong spot...The reason I posted here is that I recall running across a syslinux changlog that said "..added support for reading .spl..." files. I want to customize the suse boot up splash screens (for a CD install). I have been

Dear all, I'm trying to use the Pspline add-on package to fit a quintic spline (norder =3), but I keep running into a Singularity error. > traj.spl <- smooth.Pspline(time, x, norder=3 ) Error in smooth.Pspline(time, x, norder = 3) : Singularity error in solving equations > Playing around with the other parameters produces an "unused arguments" error: > traj.spl

Thank you very much for your reply. Your code work well with this example. I modified a little to fit my real data, I got an error massage. Error in split.default(x = seq_len(nrow(x)), f = f, drop = drop, ...) : Group length is 0 but data length > 0 On Thu, Jan 31, 2013 at 12:21 PM, arun kirshna [via R] < ml-node+s789695n4657196h87@n4.nabble.com> wrote: > Hi, > Try this: >

Some wavelet analysis experts have implemented periodic boundary conditions for signals. I need to implement a circular buffer. Something like: "12345abcdefgh12345abcdefgh" so that at each step the riightmost element is moved to the leftmost index and everything else is properly shifted: "h12345abcdefgh12345abcdefg", "gh12345abcdefgh12345abcdef", .... My

Dear All, I've been?searching for?appropriate codes to compute the rate of change and the curvature?of ?nonparametric regression model whish was denoted by a smooth function?but?unfortunately?don't manage to?do?it. I presume that such characteristics from a smooth curve can be determined by the first and second derivative operators. The following are the example of fitting a

Dear R helpers Suppose following is an output due to some R process. I wish to save it as a table in 'temp.db' df <- data.frame(x = c(5, 4, 3, 11), y = c(25, 16, 9, 121))     library(RSQLite)     write('** Initializing','')     drv <- dbDriver("SQLite", shared.cache = TRUE)     con <- dbConnect(drv, dbname = "temp.db",

My apologies, I know that this is not a new problem, but I'm not sure how to find the answer I want to recursively loop over an object and trim trailing white space. When I use this function on a list of data.frame I get output like this: [1] "c(\" many spaces \", \" many spaces \")" "c(\" many spaces \", \" many spaces

hola soy nuevo usuario de R y necesito crear un objeto p tal que, p=lambda*integral[f´´(x)^2 dx ] donde "lambda" es uno de los parametros que resultan de la funcion "smooth.spline()" y la integral es sobre la derivada 2 de esa misma funcion... dos cuestiones: 1) como extraigo lambda de los resultados de smooth.spline() para usarlo como objeto cuando lo requiera y 2) como

I just followed the instructions on CRAN<http://cran.r-project.org/bin/linux/ubuntu/README> to install R on an Ubuntu instance. sudo apt-get install r-base Why does it install an old version of R? Can I install version 15.1? I changed my sources.list to be a current cran mirror. I believe that I have entered the URL correctly because at first I had it wrong (there was a trailing

Why doesn't this work? x = zoo(1:5, as.Date('2001-01-01')+1:5) x[as.Date('2001-01-05')] x[as.Date('2001-01-05')] = 0 x I think this is especially bad because it doesn't cause an error. It lets you do something to x, but then you can't see x again to see what it did. [[alternative HTML version deleted]]

Dear R users, Suppose I have a data set with inconsistent names for a field. I desire to make these to consistent names. i.e "University of New Jersey", "New Jersey Uni", "New Jersey University" (3 different inconsistent names) to "The University of New Jersey" (consistent name) Below are arbitrary data set produced from "state.name" (built

I've been wondering what L means in the R computing context, and was wondering if someone could point me to a reference where I could read about it, or tell me what it's called so that I can search for it myself. (L by itself is a little too general for a search term). I encounter it in strange places, most recently in the "save" documentation. save(..., list = character(0L),