similar to: Trendline for a subset of data

Hi I would like to display the trendline and the R-square value in a xy scatter in R. For example if I want to plot f vs g I add the trendline using the commands below >library(quantreg) >plot(f,g) >abline(rq(g~f)) however I don't know how to display the R2 in the graph. Thank you in advance. Kind regards Maria [[alternative HTML version deleted]]

How to add trendline (i.e. straight line passing through maximum points) in graph. I have worked on the data given below. Please tell me how to add trendline in the graph. The script is as follows =================================== start ==================================================== # The data is as follows data <- c( 0.01, 0.02, 0.04, 0.13, 0.17 , 0.19 , 0.21 , 0.27 , 0.27 ,

Hi all, I have a dataset which consists of 2 columns. I'd like to plot them on a x-y scatter plot and fit an exponential trendline. I'd like R to determine the equation for the trendline and display it on the graph. Since I am new to R (and statistics), any advice on how to achieve this will be greatly appreciated. Many thanks, Chris -- View this message in context:

Hi, Is there a way to plot trendline with quantmod package? There is addLines function in the package but I can't seem to figure out how to use it (not well documented): > args(addLines) function (x, h, v, on = 1, overlay = TRUE, col = "blue") NULL so arguments "h" and "v" add horizontal and vertical lines. How does argument "x" work? I would like

I am hereby forwarding the data & method use to calculate the Kolmogorov-Smirnov goodness of fit test made manually by me in R launguage which deffers with the actual inbuilt formula as shown below. Further I have plot the graph in R. In that graph how to add trendline (i.e. straight line passing through maximum points in plot) to a Plot. R script is as follows please run this script to see

Dear all, I have data in the following format : X-axis Y-axis <0 10% 0-20 20% 20-40 30% 40-60 40% ......... and so on. I want to plot a bar graph of the above. Also I would want to add a trendline passing either through the center of each bar or through the top. Is it also possible to get the r-squared and p-values for

Hi, I am trying to fit a logarithmic trendline to a scatterplot of a species accumulation curve. I've tried abline, lines, curve and scatter.smooth but none of these work. Can anyone help please, Kyran

Hi Everyone, I''ve been looking into the different hypervisors that''re available, and i''ve noticed the Xen project and the XenServer by Citrix. Is there a difference? Or am i looking at an old website? Because the version on xen.org is 3.5.4 and the version on citrix is 5.5. Thanks, Matthew Millar

Hi everyone, I'm trying to determine the significance of a trendline. From my internet search months ago, I came across the following post. I modified tim and dat for simiplicity. tim <- 1:10 dat <- c(0.17, 1.09 ,0.11, 0.82, 0.23, 0.38 ,2.47 ,0.41 ,0.75, 1.44) fstat <- summary(lm(dat~tim))$fstatistic p.val <-

Maybe I wasn't clear about my query. I'm very familiar with pre-allocation and vectorization and I had already wrote an R code for this problem in this way. My question wasn't about the most efficient way to solve the problem. It was about whether in R it was possible to use the same index used in the loop to create a new variable and store the results in as in the example showed

... "(R is case sensitive, so "C" has no such problem)." Well, not quite. Try ?C To add to the previous comments, Dr. Gordon appears to need to do her/his homework and spend some time with an R tutorial or two before posting further here. There are many good ones on the web. Some recommendations can be found here: https://www.rstudio.com/online-learning/#R Cheers, Bert

OK this is bound to be something silly as I'm completely new to R - having started using it yesterday. However I am already warming to its lack of 'proper' GUI... I like being able to rerun a command by editing one parameter easily... try and do that in a Excel Chart Wizzard! I eventually want to use it to analyse some chemotherapy response / survival data. That data will not be

There are a couple of points to keep in mind when doing a log-transform of an exponential model, such as -- y = a*exp(b*x) 1. The implicit statistical model is multiplicative in the error. The implied statistical model of the log transform is -- log(y) = log(a) + b*x + u which implies -- y = a*exp(b*x)*exp(u) A linear regression in the log

I require some help in debugging this code  library(neuralnet) ir<-read.table(file="iris_data.txt",header=TRUE,row.names=NULL) ir1 <- data.frame(ir[1:100,2:6]) ir2 <- data.frame(ifelse(ir1$Species=="setosa",1,ifelse(ir1$Species=="versicolor",0,""))) colnames(ir2)<-("Output") ir3 <- data.frame(rbind(ir1[1:4],ir2))

Dear all, I have a script about iteration classification, like this below data(iris) N <- 5 ir.tr.iter <- vector('list',N) ir.tr <- vector('list',N) for (j in 1:N) { ir.tr[[j]] <- rpart(Species ~., data=iris) ir.tr.iter[j] <- ir.tr[[j]]$frame result <- list(ir.tr=ir.tr, ir.tr.iter=ir.tr.iter) } as.data.frame(as.matrix(ir.tr.iter))

Hi list, One of my co-workers found this problem with 'cor' in his code and I confirm it too (see below). He's using R 2.2.1 under Win 2K and I'm using R 2.3.0 under Win XP. =========================================== > R.Version() $platform [1] "i386-pc-mingw32" $arch [1] "i386" $os [1] "mingw32" $system [1] "i386, mingw32" $status

Hello, I'll use part of the iris dataset for an example of what I want to do. > data(iris) > iris<-iris[1:10,1:4] > iris Sepal.Length Sepal.Width Petal.Length Petal.Width 1 5.1 3.5 1.4 0.2 2 4.9 3.0 1.4 0.2 3 4.7 3.2 1.3 0.2 4 4.6 3.1 1.5

Greetings R experts, I'm having some difficulty recovering lda objects that I've saved within sublists using the save.image() function. I am running a script that exports a variety of different information as a list, included within that list is an lda object. I then take that list and create a list of that with all the different replications I've run. Unfortunately I've been

Hi Dieter and R community: I tried both of these three versions with ylim as suggested, none work: I am getting only single (pch = 16) not overlayed (pch =3) everytime. *vs 1* require(lattice) xyplot(Sepal.Length ~ Sepal.Width | Species , data= iris, panel= function(x, y, subscripts) { panel.xyplot(x, y, pch=16, col = "green4", ylim = c(0, 10)) panel.lmline(x, y, lty=4, col =

Hi everyone, I would like to identify the case by groups that is just bigger that avg plus sd. For example, using species as group and petal.wid as my variable in the iris data. What's the better way to doit? creating a function? So,the question is to identify the single element of each species that is just larger than a cut-off point (i.e. larger than mean + sd) I made this, but I can not