similar to: avoid NA in list

Hi ! I have a vector: vec= TRUE TRUE TRUE TRUE FALSE FALSE FALSE FALSE TRUE TRUE FALSE and I'm looking for a method which let me get only the first values equal TRUE from this vector. It means that I want to get a vector: vec_out = TRUE TRUE TRUE TRUE or posictions values = TRUE: vec_out = 1,2,3,4 -- View this message in context:

Hi! I want to use one method "combinations" from "gtools" package but in my code I must use also "dprep" method where is method "combinations" too. Mayby I show you result my help function: Help on topic 'combinations' was found in the following packages: Package Library dprep /usr/lib64/R/library gtools

Hi, My english isn't brilliant and my problem is very difficult to describe but I try ;) My first question is: May I write loop "for" like this or similar - for (i in sth : sth[length(sth)], k in sth_else : length(sth_else) ) - I'd like to have two independent conditions in the same loop "for". My secound question depend on program below. I'd like to write every

Do you know any good editor R? -- View this message in context: http://www.nabble.com/Editor-R-tp23822342p23822342.html Sent from the R help mailing list archive at Nabble.com.

Hi, For example: I built a half matrix "w" using a daisy(x, metric = c("euclidean")) http://www.nabble.com/file/p25211016/1.jpg And next I transformed this matrix "w" using isoMDS function, for example isoMDS(w, k=2) and as result I got: http://www.nabble.com/file/p25211016/2.jpg And now I have two questions: 1. If number in matrix w[2, 1] (= 0.41538462) match

Hi, I have got a data frame: df=data.frame(x=c(3,6,7),y=c(2,7,4)) and I would like to write my values from data frame to list using loop, for example: lista=list() for (i in 1: length(?)){ lista[[?]][?] = df [?] } But I havn't got any idea what I should put in places where I put a question mark? As a rusult I would like to get a list like this: list: [[1]] 3,6,7 [[2]] 2,7,4 I

I think it's easy problem but I can't find solution. I have a vector: vec <- c (23.4, 3.0, 14.7, 7.7) and I would like to add all values which are inside my vector to each other. as a result a want to get one value like sum all values from my vector- sth=(23.4 + 3.0 + 14.7 + 7.7) PS. I usually don't know how long is my vector in my function -- View this message in

Hi, I have a vector a=c(NA, 3, 4, 4, NA, NA, 3) and I would like to use is.na(a) function to get a vector like this: wy=(1,2,2,2,1,1,2) - you know, this vector create 1 or 2 depends on value in vector "a" This is my short code but something is wrong and I don't know what... for (i in 1:7){ a=c( NA, 3, 4, 4, NA, NA, 3) fun1=function(x){ x=1 print(x) } fun2=function(x){

Hello! I wont to use a function is.na() I have two vectors: > a=c(1,NA,3,3,3) > b=c(0,0,0,0,0) and when I use is.na function it's ok: > is.na(a) [1] FALSE TRUE FALSE FALSE FALSE but I would create sth like this: for i in 1:length(a){ if (wsp[i] == is.na(a)) {b=43} } or like this if(is.na(a)) b=3 else a [1] 1 NA 3 3 3 but I always get an error: the condition has

I have a vector like this: h <- c(4, 6, NA, 12) and I create the secound logical vector like this: g <- c(TRUE, TRUE, FALSE, TRUE) And my problem is that I would like to get a new "m" vector as a rasult "h" and "g"( as dot-matrix printer) but with missed "NA" value, for example: m = (4,6,12) Do you have any idea? -- View this message in

I have a database like this: "kol1";"kol2";"kol3" ... "2";"5";"9" "9";"6";"6" "4";"6";"5"... I looking for a kod in R which let mi aviod in column unnecessary value, for example number "9". So, if I have: Kol1 2 9 4 4... after loop in R I would like to get my

Dear All, I have a list, where several components are NULL, and I'd like to obtain that very same list without the NULL components (i.e., I do not want to unlist or otherwise loose the rest of the list structure). I can do that with a loop, but how could I do it without a loop? Thanks, Ram?n -- Ram?n D?az-Uriarte Bioinformatics Unit Centro Nacional de Investigaciones Oncol?gicas (CNIO)

I heve got a list: lista=list() a=c(2,4,5,5,6) b=c(3,5,4,2) c=c(1,1,1,8) lista[[1]]=a lista[[2]]=b lista[[3]]=c > lista [[1]] [1] 2 4 5 5 6 [[2]] [1] 3 5 4 2 [[3]] [1] 1 1 1 8 I would like to know where is number 5 (which line)? For example I have got a loop: k= vector(mode = "integer", length = 3) for(i in 1:3) { for (j in 1:length(lista[[i]])){ if

Hello, Is this expected ? > nchar( c( "", NA ) ) [1] 0 2 Should not the second one be NA ? Romain -- Romain Francois Professional R Enthusiast +33(0) 6 28 91 30 30 http://romainfrancois.blog.free.fr |- http://bit.ly/98Uf7u : Rcpp 0.8.1 |- http://bit.ly/c6YnCi : graph gallery collage `- http://bit.ly/bZ7ltC : inline 0.3.5

I'd like to replace a value in a data frame with an NA, but can't figure out how. For example, say you have a<-c(1,2,3,4) b<-c(5,6,7,8) data<-data.frame(a,b) Now, how would you set the third row of the second column ( data [[3,2]] ) to NA? I have tried all types of permutations with is.na, including is.na<- data[[3,2]], which does not work. Thanks

Hi, I do have a data set with some missing values that appear as blanks. I want to fill these blanks with an NA. How can this be done? Thanks for your help -- View this message in context: http://www.nabble.com/filling-blanks-with-NA-tp21584278p21584278.html Sent from the R help mailing list archive at Nabble.com.

Windows 7, R-2.11.1 and R-2.12.0beta When I do file.info(list.files(getwd())) I get what I expect, a dataframe with a lot of variables, especially isdir, which tells me if the named object is a file or a directory. In the result of file.info(list.files(paste(R.home(),"library",sep="/"))) all variables have only NA values, even when I start R in elevated mode.

Dear list, Does anyone know if there is a function that replaces a matrix of "NA"s in an array with the previous matrix with numbers? For example, I have an array ab <- array(dim=c(3,3,15),dimnames=list(rows=1:3,cols=1:3,dim=times)) . Select out put from the array is: , , dim = 0.478356969557745 cols rows 1 2 3 1 0.4921053 0 0.5078947 2 0.0000000 0

Hi all, When I try to sum a few columns in a data frame (which has NA?s randomly distributed as elements), I am not able to get the summing operation to ignore the NA?s. Let me explain with the following code : ################################? a<-structure(list(a1 = c(NA, 2, 3, NA, 5, 6, NA, 8, 9, NA), a2 = c(NA, + 4, 5, 5, NA, 7, 8, 8, NA, 10), a3 = c(2, NA, 6, 8, NA, 12, 14, + NA, 18, 20)),

Hello, I have observed the following odd behavior of "is.na( )" and hope someone can give me an explanation Example: X1=rep(1:2,5)[-1] X2=rep(1:5,rep(2,5))[-1] y= runif(9) y[3]=NA xtabs(y~x1+x2) Now xtabs(is.na(y)~x1+x2) says that cell 2,2 is NA x2 x1 1 2 1 0 0 2 0 1 3 0 0 4 0 0 5 0 0 Whereas xtabs(!is.na(y)~x1+x2) says that all but cell 1,1 and 2,2 are not NA x2