similar to: ggplot2::qplot() -- arbitary transformations of coordinate system?

My question is related to plot( ) in the mgcv package. Before modelling the data, a few predictors were transformed to normalize them. Therefore, the x-axes in the plots show transformed predictor values. How do I back-transform the predictors so that the plots are easier to interpret? Thanks in advance, Suzan -- Suzan Pool Oregon State University Cooperative Institute for Marine

Hello, this following code give a nice png: /library(ggplot2) i <- 1 png(file=paste('test ',i,'.png',sep='')) qplot(carat, data=diamonds, fill=color,geom='histogram')+scale_y_continuous(i) dev.off() / I would like to get more files, but the following code doesn't make any file: /library(ggplot2) for (i in 1:2) { png(file=paste('test

Hi Hadley: I'm practicing writing a document using MikTex but can't make qplot to execute. It works when using 'plot' though. Is this a normal behaviour? \documentclass[9pt]{article} \title{ggplot2 example} \begin{document} \maketitle \section*{Examples of using ggplot2} The goal is to be able to import ggplot2 graphics into the annual report. Hadley Wickham has done a great

On OS X 10.8.2, after I installed ggplot2, and picked mirror of Singapore. it could not find qplot function. Could anyone pls help me ? Thank you. Pls see: > install.packages("ggplot2")--- Please select a CRAN mirror for use in this session ---also installing the dependencies ¡®colorspace¡¯, ¡®stringr¡¯, ¡®RColorBrewer¡¯, ¡®dichromat¡¯, ¡®munsell¡¯, ¡®labeling¡¯, ¡®plyr¡¯,

Hi, I wish to plot multiple histograms(representing different data so different range along xaxis but y axis is the same) horizontally in ggplot2. I'd like it to look like facets. Is this possible? -- Rajesh.J [[alternative HTML version deleted]]

Hi, Here are three plots: library(ggplot2) data(diamonds) randind <- sample(nrow(diamonds),1000,replace=FALSE) dsmall <- diamonds[randind,] qplot(carat, data=dsmall, geom="histogram",binwidth=1) qplot(carat, data=dsmall, geom="histogram",binwidth=.1) qplot(carat, data=dsmall, geom="histogram",binwidth=.01) What are ways to put these three plots on a single

Hi Ian, Per your suggestion, I reinstalled R 2.9.0, then I reinstalled ggplot2 on top. The problem persists. Here's the what happens after the installation: > qplot (carat, price, data = diamonds, alpha = I(1/10)) Warning message: In grid.Call.graphics("L_points", x$x, x$y, x$pch, x$size) : semi-transparency is not supported on this device: reported only once per

I can plot to png's fine when i run this directly from the top-level script/console: png('diamonds.png');qplot(carat,price,data=diamonds);dev.off() But for some reason it's not working when that's in a function: (function(){png('diamonds.png');qplot(carat,price,data=diamonds);dev.off()})() I suspect this is because the qplot's return value must be

Hi all, Is there any way for me to to string in the argument of qplot or ggplot? for example qplot(x='carat',y='price',data=diamonds,geom=c('point','smooth')) instead of qplot(x=carat,y=price,data=diamonds,geom=c('point','smooth')) Thanks!! Regards, TszKin Julian [[alternative HTML version deleted]]

Hi, I've been struggling with this problem the last few days and finally discovered it's happening at a very fundamental level. Going through Stephen Turner's tutorial on ggplot2, I entered these base graphics commands: > with(diamonds, plot(carat,price)) > with(diamonds, plot(carat,price), xlab="Weight in Carats", ylab="Price in USD",

Suppose that I'm working on Hadley's diamond dataset and I want to review the relationship between price, colour and carat. I might run the following: library(ggplot2) #plot scatter and add some hex binning q<-qplot(carat,price,data=diamonds, geom=c("hex"), main="Variability of Diamond Prices by Carat and Colour") #facet to get one scatter for

I've seen this asked, but never fully answered.  Is it possible to plot stacked histograms in R? I have four data sets that I would like to show combined vertically in histogram format.  Is this possible?  Thank you for any feedback you can provide. P.S. I know I can show the four sets side by side, but I want to combine them, but still uniquely identify each.   Thanks again.

Hello I'd like to plot a histogram of some data composed of real numbers. The bin width I'm using is ~ 0.01, which results in high values in the y axis, so that the area under each bar corresponds to the probability of the data in that range. Is is possible to plot points whose y coordinate correspond to that probability, instead of plotting the histogram bars? In other words, instead of

Dear r-helpers, Does anyone have a straightforward example of putting together three unrelated (expect for a common y-axis) xyplot() figures in what would be in base graphics a par(mfrow = c(1, 3)) arrangement? _____________________________ Professor Michael Kubovy University of Virginia Department of Psychology USPS: P.O.Box 400400 Charlottesville, VA 22904-4400 Parcels: Room 102

Good day, Sometimes, sparse.model.matrix outputs a dgCMatrix which has column names consisting of factor levels that were not in the original dataset. The first factor appears to be correctly transformed, but the following factors don't. For example: diamonds <- as.data.frame(ggplot2::diamonds) > colnames(sparse.model.matrix(~ . -1, diamonds)) [1] "carat"

Hi, I would like to use the effect() function (actually a slightly modified version of it) on the output of the lmer() function in the lme4 package. But the effects package requires the nlme pacvkage, which is incompatible with lme4. Workaround? ______________________________________________ Professor Michael Kubovy University of Virginia Department of Psychology for mail add: for FedEx or

I currently use lattice functions to produce multiple pages of plots using the "layout" argument to specify the number of rows and columns of panels, e.g., xyplot(price ~ carat | clarity, diamonds, layout = c(2, 2)) This results in 2 pages of 4 panels each. "diamonds" is a data.frame distributed with ggplot2. I would like to do the same with ggplot2 but have been

Dear R-helpers, How do I transform v <- c('insd-otsd', 'sppr-unsp') into c('insd--otsd', 'sppr--unsp') ? _____________________________ Professor Michael Kubovy University of Virginia Department of Psychology USPS: P.O.Box 400400 Charlottesville, VA 22904-4400 Parcels: Room 102 Gilmer Hall McCormick Road Charlottesville, VA 22903

df1 <- data.frame(a = LETTERS[1:2], b = LETTERS[3:4], c = 1:2) I am looking for an idiom that swaps the elements of df$a and df$b when (e.g.) df$c == 2, resulting in df2 <- data.frame(a = LETTERS[c(1, 4)], b = LETTERS[c(3, 2)], c = 1:2) _____________________________ Professor Michael Kubovy University of Virginia Department of Psychology USPS: P.O.Box 400400 Charlottesville, VA

Dear Friends, Here is an algorithm for finding concave hulls: http://get.dsi.uminho.pt/local/ Has anyone implemented such an algorithm in R? RSiteSearch('concave hull') didn't reveal one (I think). _____________________________ Professor Michael Kubovy University of Virginia Department of Psychology Postal Address: P.O.Box 400400, Charlottesville, VA 22904-4400 Express Parcels