similar to: plot positive predictive values

Displaying 20 results from an estimated 4000 matches similar to: "plot positive predictive values"

2009 Sep 04
0
plotting positive predictive values
Hi, I'm trying to fit a smooth line in a plot(y ~ x) graph. x is continuous variable y is a proportion of success in sub-samples, 0 <= y <= 1, from a Monte Carlo simulation. For each x there may be several y-values from different runs. Each run produces several sub-samples, where "0" mean no success in any sub- sample, "0.5" means success in half of the
2011 Dec 01
3
Change the limits of a plot "a posteriori"
Hi all How can I change the limits (xlim or ylim) in a plot that has been already created? For example, consider this naive example curve(dbeta(x,2,4)) curve(dbeta(x,8,13),add=T,col=2) When adding the second curve, it goes off the original limits computed by R for the first graph, which are roughly, c(0,2.1) I know two obvious solutions for this, which are: 1) passing a sufficiently large
2011 Aug 01
3
Beta fit returns NaNs
Hi, sorry for repeating the question but this is kind of important to me and i don't know whom should i ask. So as noted before when I do a parameter fit to the beta distr i get: fitdist(vectNorm,"beta"); Fitting of the distribution ' beta ' by maximum likelihood Parameters: estimate Std. Error shape1 2.148779 0.1458042 shape2 810.067515 61.8608126 Warning
2001 Jun 06
3
error in dbeta (PR#970)
Full_Name: Hans Peter Wolf Version: 1.2.1 OS: hpux10.20 Submission from: (NULL) (129.70.84.25) dbeta computes a wrong result with parameters (1.3,1) > version platform hppa2.0-hp-hpux10.20 arch hppa2.0 os hpux10.20 system hppa2.0, hpux10.20 status major 1 minor 2.1 year
2013 Sep 18
1
dbeta may hang R session for very large values of the shape parameters
Dear all, we received a bug report for betareg, that in some cases the optim call in betareg.fit would hang the R session and the command cannot be interrupted by Ctrl-C? We narrowed down the problem to the dbeta function which is used for the log likelihood evaluation in betareg.fit. Particularly, the following command hangs the R session to a 100% CPU usage in all systems we tried it (OS X
2011 Jul 29
1
How to interpret Kolmogorov-Smirnov stats
Hi, Interpretation problem ! so what i did is by using the: >fit1 <- fitdist(vectNorm,"beta") Warning messages: 1: In dbeta(x, shape1, shape2, log) : NaNs produced 2: In dbeta(x, shape1, shape2, log) : NaNs produced 3: In dbeta(x, shape1, shape2, log) : NaNs produced 4: In dbeta(x, shape1, shape2, log) : NaNs produced 5: In dbeta(x, shape1, shape2, log) : NaNs produced 6: In
2007 Nov 08
1
64-bit R-build on Mac OS X 10.4 - make check failures
Hi all, I compiled 64-bit R on an Apple Mac G5 running OS X, but it failed make check. Simon Urbanek suggested I post results to R-devel. > On Nov 6, 2007, at 10:23 PM, Steven McKinney wrote: > > > Hi Simon, > > > > Would you be able to give more guidance on how to compile 64-bit > > libiconv for Tiger, > > You can get the sources from Apple and compile
2008 Oct 19
1
multivariate integral with ADAPT when the parameter is close to boundary
Dear All, There is one problem I encountered when I used ADAPT to compute some 2-D integral w.r.t beta density. For example, when I try to run the following comments: fun2<-function(theta){return(dbeta(theta[1],0.005,0.005)*dbeta(theta[2],0.005,0.005))} int.fun2<-adapt(ndim=2,lo = c(0,0), up = c(1,1),functn = fun2,eps = 1e-4) It seems it will take very long time to run. Acturally, I
2007 Nov 24
2
how to compute highest density interval?
Suppose i want to compute a 95% highest density for a beta distribution beta(a,b) the two end points x1 and x2 shoudl satisfy the following two equations: pbeta(x1,a,b)-pbeta(x2,a,b)=95% dbeta(x1,a,b)=dbeta(x2,a,b) Is there any fast way to compute x1 and x2 in R? [[alternative HTML version deleted]]
2008 Sep 30
2
R's integrate function
Hello, I am trying to use R's integrate function to calculate the following integral for z=423: integrate(function(y,z){ sapply(y, function(y,z){ integrate(function(x,z) 1/x*dbeta(0.01,x/(0.005/1.005),(1-x)/(0.005/1.005))*dbeta(y,x/(0.005/1.005),(1-x)/(0.005/1.005))*(1-y)^z,0,1,423)$value }) },0,1,423)$value but I receive an error message saying that the maximum number of subdivisions is
2004 Nov 09
3
Strange results for Beta Distribution
Dear All, I got these results from the example in the function "dbeta": >x <- seq(0, 1, length=21) > dbeta(x, 1, 1) [1] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 Any Idea? TIA Giovanni dr. Giovanni Parrinello Section of Medical Statistics Department of Biosciences University of Brescia 25127 Viale Europa, 11 Brescia Italy Tel: +390303717528 Fax: +390303701157
1997 Apr 15
1
R-alpha: Bug & Patch in dbeta.c (0.50 - PreR 7)
dbeta(1, a,b) would return 1 instead of 0. Here is the patch for ..../src/math/dbeta.c : --- dbeta.c~ Sun Nov 24 23:43:10 1996 +++ dbeta.c Tue Apr 15 21:25:30 1997 @@ -23,9 +23,7 @@ { if (a <= 0.0 || b <= 0.0) DOMAIN_ERROR; - if (x <= 0) + if (x <= 0 || x >= 1.0) return 0.0; - if (x >= 1.0) - return 1.0; return MATH_CHECK(pow(x, a - 1) * pow(1.0 - x, b - 1.0) /
2012 Jan 03
6
calculate quantiles of a custom function
Hi, I guess that my problem has an obvious answer, but I have not been able to find it. Suppose I create a custom function, consisting of two beta-distributions: myfunction <- function(x) { dbeta(x,2,6) + dbeta(x,6,2) } How can I calculate the quantiles of myfunction? I have not seen any continous function treated in the docs, and applying the "quantile function" gives me an
2000 Aug 24
1
too large alpha or beta in dbeta ?
Dear friends. Is this as expected ? Is alpha and beta too large simply ? > dbeta(.1,534,646) [1] NaN Warning message: NaNs produced in: dbeta(x, shape1, shape2, log) Best wishes Troels -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or
2000 Aug 25
1
Re: [R] too large alpha or beta in dbeta ? (PR#643)
>>>>> "TL" == Thomas Lumley <thomas@biostat.washington.edu> writes: TL> On Thu, 24 Aug 2000, Troels Ring wrote: >> Dear friends. >> >> Is this as expected ? Is alpha and beta too large simply ? >> >> > dbeta(.1,534,646) >> [1] NaN >> Warning message: >> NaNs produced in:
2005 Jul 27
1
error message running R2WinBUGS
*Dear R-user, * I try to run Winbugs from R using bugs function in R2WinBUGS.My model works well in Winbugs except that I can't get DIC. Since I don't need DIC, when I try to run Winbugs from R , I set "DIC=FALSE". My model is as following: model { for (i in 1:N) { for(j in 1 : T ) { x[i, j] ~ dbin(p[i, j],n[i]) #Hier.prior p[i, j] ~ dbeta(alpha[i, j], beta[i, j]) alpha[i, j]
2010 Jan 04
3
how to plot multiple density functions in one graph
Hello, I am new to R and have two easy questions. How can you plot multiple density functions in one graph? I have five beta densities that I would like to plot in one graph. I understand how to plot one beta density as a line: plot (x,(dbeta(x,shape1=,shape2=,), type ="l") Does the Pareto distribution need to be added to R with an additional package? thanks, John [[alternative
2013 Jan 22
2
Assistant
Good-day Sir, I am R.Language users but am try to? estimate parameter of beta distribution particular dataset but give this error, which is not clear to me: (Initial value in "vmmin" is not finite) beta.fit <- fitdistr(data,densfun=dbeta,shape1=value , shape2=value) kindly assist. expecting your reply:
2010 Jun 23
1
A question about R2Winbugs
Dear R users: I was trying to fit a HMM with mixture of Gaussian into the dataset, and I tried to implement it by R2Winbugs. But I got the following errer. * Error in FUN(X[[1L]], ...) : .C(..): 'type' must be "real" for this format* Does anybody know what's the problem? Does R2Winbugs accept some matrix as inits? I would really appreciate your help. Thank you very much.
2007 Oct 24
1
plot within a loop
Hi , I'm having problem with the following plot. Basically I have to do 51(length of d, see below) plots. I want 6 plots (say) in a page and rests are in different pages. win.graph() starts a plot in new page. But I'm not being able to combine par(mfrow = c(3,2)) and win.graph() within a loop. > d [1] 14.108 13.883 11.022 13.426 2.341 9.010 12.868 15.603 30.810 3.931 11.825