similar to: evaluate sum of sum

Hi r-users, How do we evaluate the summation of (1/m!) from 0 to infinity (for example). Any help is very much appreciated. Thank you.

Hi r-users,   I have this data below.  I would like to obtain the weekly rainfall sum.  That is I would like to find sum for day 1 to day 7, day 8 - day15, and so on.    year month day rain 1  1922     1   1  0.0 2  1922     1   2  0.0 3  1922     1   3  0.0 4  1922     1   4  0.0 5  1922     1   5  0.0 6  1922     1   6  0.0 7  1922     1   7  0.0 8  1922     1   8  6.6 9  1922     1   9  1.5 10

Hi r-users,   I have this data below and would like to plot a barplot overlap with a line. This is my data: > hist_50     pdf_obs pdf_gen.50 1  0.000000   0.000000 2  0.083156   0.125366 3  0.132196   0.158230 4  0.126866   0.149432 5  0.120469   0.127897 6  0.121535   0.104096 7  0.103412   0.082171 8  0.082090   0.063539 9  0.065032   0.048408 10 0.050107   0.036470 11 0.036247   0.027236 12

Dear r-users,   I have these data below:   I would like to compare each column with a certain value and count how many in each column less than that specified value.    odd column (1,3,5) will compare with 1.61 and even column (2,4,6) will compare with 75 and I would like to count how many for each column.      I tried these below but it give me just one set of data.   critical  <-

Dear r-users,   I have daily rainfall data from 1971 to 2000.  I would like to extract november and december data only.  I would also like to do column bind for november and december, therefore I would like to delete 31 December from december data so that the length of november and december are the same.  Hope somebody can help me.  I tried this below:   > kuantan.dt.1 <-

Hi r-users, I would like to add a plot of vertical line segment with arrow from (77,.6) to (77,0) and also a horizontal  line segment with arrow from (0,0.6) to (77,.6) .  So far this is what I have: plot(sq, cdf, type="l", lwd=4,col="blue",xaxs="i",yaxs="i", xlab= "Rainfall (mm)", ylab= "Random no.", main="Random number  and

Hi r-users,   I would like to use Kolmogorov smirnov test but in my observed data(xobs) there are ties.  I got the warning message.  My question is can I do something about it?   ks.test(xobs, xsyn)           Two-sample Kolmogorov-Smirnov test data:  xobs and xsyn D = 0.0502, p-value = 0.924 alternative hypothesis: two-sided Warning message: In ks.test(xobs, xsyn) : cannot compute correct

Hi R-users,   I would like to search for the values of seq that match my rand values.  In excel I will use =VLOOKUP(G2,$E$2:$F$32,2).  For example, for rand=.262 it will give me approximately seq=120 and rand=0.964293344, seq=460 and etc.   E           F     G cdf         seq   rand 0.00E+00    0     0.262123478 1.56E-03    20    0.964293344 1.55E-02    40    0.494827113 5.30E-02    60   

Hi, I need some opinion.  I would like to use graph that I generate from R code and save it into word document.  Which format is better? pdf, jpeg or tiff? Thank you. [[alternative HTML version deleted]]

Hi R-expert, I try to eliminate 29 Feb but I got an error message below: feb_data1 <- Pooraka_data[Pooraka_data$Month=="2",] feb_28days <- feb_data1 [feb_data1$Day=="28",] feb_29days <- feb_data1 [feb_data1$Day=="29",] ## delete 29 Feb feb_no_29 <- feb_data1 [-(feb_29days),] feb_no_29 <- feb_data1 [-(feb_29days),] Error in xj[i] : invalid subscript

Hi,   Does R has something similar  to vlookup function in excel?   Thank you for the info. [[alternative HTML version deleted]]

Hi, I have a data below and would like to search for positive pairs only and form a new data set. ???????????X1??? ??? ??? ?X2 31.0 9.0 11.0 1.0 1.0 0.0 0.0 0.0 8.0 0.0 0.0 0.0 2.0 2.0 18.0 3.0 0.0 0.0 0.0 0.0 0.0 0.0 10.0 0.0 6.0 0.0 ... The new data will be X1'?? X2' 31.0 9.0 11.0 1.0 2.0 2.0 18.0 3.0 I tried to write the function as: y1y2 <-?

Dear R users, I'm trying to carry out monte carlo integration of a posterior density function which is the product of a normal and a gamma distribution. The problem I have is that the density function always returns 0. How can I solve this problem? Here is my code #generate data x1 <- runif(100, min = -10, max = 10) y <- 2 * x1^2 + rnorm(100) # # # # # # # # Model 0 # # # # # # #

Sorry, I can't reproduce the example below even on the same machine. However, the following example produces the same error as NULL values in prior examples: > setClass("FOOCLASS", +????????? representation("list") + ) > ma = new("FOOCLASS", list(M=matrix(rnorm(300), 30,10))) > isS4(ma) [1] TRUE > data.frame(a=1:3) == ma Error in

Hi R-users,   I wrote a code to evaluate double sum as follows:   ff2 <- function(bb,eta,z,k) { r <- length(z) for (i in 1:r) { sm1 <- sum((z[i]*bb/2)*(psigamma((0:k)+eta+1,deriv=0)/(factorial(0:k)*gamma((0:k)+eta+1))))  sm2 <- sum((besselI(z[i]*bb,eta)*log(z[i]*bb/2) - sm1)/besselI(z[i]*bb,eta))  sm2 } ff2(bb,eta,z,10)     but it gave me the following message:   >

Hi R-users, Can Maple function be exported to R? I have a jacobian matrix (4X4)?from maple in algebraic form which involve modified Bessel function of the first kind. I just wonder whether we can use algebraic form into R before the value of the parameters can be estimated. Thank you so much for your attention and help.

Dear r-users, I have dailly rainfall data from year 1971 to 2000. I use aggregate to form monthly rainfall data.  What I don't understand is that the data for the year 2000 become on the top, instead of year 1971.  Here are some codes and output: agg_dt1     <- aggregate(x=dt1[,4],by=dt1[,c(1,2)],FUN=sum) > head(agg_dt1,20); tail(agg_dt1,20)    Tahun Bulan     x 1      0     1 398.6

FYI. http://leonardo-m.livejournal.com/73732.html If anyone is motivated, please file bugs for the losing cases. Also, it might make sense to incorporate the tests into our nightly tester test suite. Thanks, Evan

Hi r-users,   I would like to know how to put all the data that is greater than certain value in certain cell for my histogram.  For example, since maximum value of p1 is 588 it doesn't fit in the breaks that we specified.  Can we write breaks >300?   max(p1[,2]) pre.hist <- hist(p1[,2],breaks = c(0,50,100,150,200,250,300),right=FALSE)   > max(p1) [1] 587.2761 > pre.hist <-

Hi r-users,   Is there any quick way to write this label?   c("0","50","100","150","200","250","300","350","400","450", "500","550","600","650","700","750","800","850","900")   Thank you.