similar to: variance explained by each predictor in GAM

"It seems therefore that there is no other way than read in individually > 100 weather tables using read.tables., right? Using file.choose() doesn't change the work." Yes. With that many files, file.choose() does not make sense. However, I still do not understand what is the problem with using lapply() on the character vector of file names with read.table() as you did in your

I'm using 1.6.2 on a win 2k box. (I know I'm due for an upgrade.) I've used brute force to label a series of vectors, and I'm wondering if there's a better way to do this. I wanted to create a biplot of the 2nd & 3rd PCs, and did this: test <- edit(loadings(cv.prc.spr)) test.1 <- test[,1] test.2 <- test[,2] test.3 <- test[,3] x0 <- 0 y0 <- 0 i <-

I have a set of modeled climate data recorded at irregular intervals. The format of the data is such that there are monthly measurements for the years 2000, 2020, 2050, 2080, etc. Therefore I have 12 regular records, a skip of some number of years, then 12 more monthly records, another skip, and so on.... I created a dataframe from .txt with the read.table() command. For starters I need

note: whole function is below- I am sure I am doing something silly. when I use it like USGS(input="precipitation") it is choking on the precip.1 <- subset(DF, precipitation!="NA") b <- ddply(precip.1$precipitation, .(precip.1$gauge_name), cumsum) DF.precip <- precip.1 DF.precip$precipitation <- b$.data part, but runs fine outside of the function: days=7

Dear R-users Sorry for posting the previous message too soon before I have finished it. I have matrix (mprecip) with headers: > dim(mprecip) [1] 6268 170 > mprecip date GilzeRijen Eindhoven Volkel ZuidLimburg Arcen Ubachsberg 1 01/01/1978 NA 0.0 NA 0.1 NA NA 2 01/02/1978 NA 0.0 NA 0.0 NA NA 3

The simplest would be to convert precip to character and then back to a factor if you really want it to be a factor. This will also remove the levels that no longer exist. str(dat) # 'data.frame': 5 obs. of 3 variables: # $ Sites : Factor w/ 5 levels "Site1","Site2",..: 1 2 3 4 5 # $ temp : num 14 15 12 12.5 17 # $ precip: Factor w/ 5 levels

Hello, I have a set of one-liners (many thanks to previous responses from this list) that I use to look at newly imported data sets with functions like dim(), names(), str(), etc. within lapply(). Generally, these commands work for me but, I am apparently still missing some aspect of list manipulation. I don't understand why I get a set of NULL list elements at the end of each output as

Hello, I have count data that illustrate the presence or absence of individuals in my study population. I created a grid cell across the study area and calcuated a count value for each individual per season per year for each grid cell. The count value is the number of time an individual was present in each grid cell. For illustration my data columns look something like this and are repeated for

Hi Sjoerd, For ISel, I think having a separate register class will give you less headache. I wondering if you could get away with not touching the instructions descriptions at all, instead defining external pattens for the FullFP16 case, like so: def VCVTBHS: ASuI<0b11101, 0b11, 0b0010, 0b01, 0, (outs SPR:$Sd), (ins SPR:$Sm), IIC_fpCVTSH, "vcvtb",

I would like to revive this thread, as I am struggling a lot with the FP16 implementation in the ARM backend. My implementation in https://reviews.llvm.org/D38315 is finished (except one case), but a more robust alternative implementation was suggested. One can indeed argue that my current implementation is a bit fragile, because it involves manually patching up the isel dags for a few cases. The

Dear R community, I am having trouble determining how to create the graph I want utilizing my relatively limited knowledge of R. So far I have been using the lattice library to create most of what I need. The dataset (enviro) consists of 2 variables (Temp and Precip) for each Day of a 2-yr period (Year). I wish to display Temp and Precip along the y axis plotted by Day on the x axis to allow

Dear all, I'm having trouble getting the correct spacing between x-axis labels on a barplot. This is the command I'm using to generate the plot: temp <- barplot(precip, beside=TRUE, xaxt="n", las=1, xpd=FALSE, col="grey28", ylim=c(0, max(precip))) Here is the structure of temp: > str(temp) ?num [1:96, 1] 0.7 1.9 3.1 4.3 5.5 6.7 7.9 9.1 10.3 11.5 ... And here

I'm using R 1.6.2 on a Windows 2000 machine. I've plotted the results of an MDS run labeled by a numerical ID, and color coded by a group code: plot(cv.mds.spr$points, type="n", main="Non-Metric Multidimensional Scaling of SprRun CV Watersheds") text(cv.mds.spr$points, labels = as.character(cv.wshed.id.spr), col = codes(cv.wshed.grp), cex=.75) Question is, how do I

Dear group, First I provide you with an example, I found in the newsgroup. Then I'd like to explain my problem to you by means of the output. enviro <- data.frame(Year = rep(2001:2002, each = 365), Day = rep(1:365, 2), Precip = pmax(0, rnorm(365 * 2)), Temp = 2 + 0.2 * rnorm(365 * 2)) xyplot(Precip + Temp ~ Day | Year,

Hi all, i'm sure there is an easy way to do this, but i'm stumped, so any help would be appreciated. i have a single column of data for precipitation every 15 minutes over a year. i want to sum the precip to daily data. so the first 96 records = the first day, the second 96 records = the second day, and so on.... is there a way to write a for loop that would sum the data to daily, and

Ok, thanks. Except the question was meant slightly different. Less w.r.t. organizing the register classes, and more w.r.t. implementation. I've noticed for instance that when trying to model this straight forwardly by writing a vreg from spills and reading this from fills (not further elaborated here), that the spiller can't handle vreg def-use pairs: there are assertions making sure a

Hello friends of R, My name is Toni, i'm 25 and I'm working on the Meteorological Investigation team from Balearic Islands. I had contact to you because I have a problem: I done a file for every day since 1912 about precipitation. That file has the following structure: > str(Ast) Loading required package: sp Formal class 'SpatialPixelsDataFrame' [package "sp"]

Hi R user, Would you mind to help me on how I can change a value in a specific column and row in a big table? but the column of the table is a factor (not numeric). Here is an example. I want to change dat[4:5,3]<-"20" but it generated NA> do you have any suggestions for me? dat<-structure(list(Sites = structure(1:5, .Label = c("Site1", "Site2",

Hello, Two lapply questions (system info and sample data below): 1) Why does the first form of command1 add the name of y _after_ the str() output rather than before as does the second (preferred) form? # command1 version1 invisible(lapply(ls(pattern='bn'), function(y) cat(y, "\n", str(get(y)), "\n") )) # command1 version2 (preferred output)

Hello, I have two different files which I'd like to combine to make one data frame but I've no idea how to do it! The first file has two columns; one is the date, the following is a binary code for debris flow events. Then my other file has also two columns; the date and then precipitation data. The thing is, is that the two date columns don't all contain the same dates. The binary