similar to: to get the R-Squared value

Dear list, I have two lists: one with data and one with TRUE/FALSE values for data I want to further analyze (see example below). I have been able to use a for loop to extract the data that I want to keep, but think that there probably exists a way to do it without a loop. Any ideas? #sample data set.seed(100) example = list(letters[1:10], letters[1:10], letters[1:10]) ind =

I have very large data sets given in a format similar to d below. Converting these to a data frame is a bottleneck in my application. My fastest version is given below, but it look clumsy to me. Any ideas? Dieter # ----------------------- len = 100000 d = replicate(len, list(pH = 3,marker = TRUE,position = "A"),FALSE) # Data are given as d # preallocate vectors pH =rep(0,len) marker

I'm looking for an R function that simply recodes a quantitative variable into a number of classes according to specified break-points. Obviously I can do this using nested ifelse() commands, but I want to write it into a function where I can't pre-specify the number of classes. Is there an obvious way to do this? An example to clarify: how to convert c(0,10,5,1,9,6) to

Dear all, I want to put 9 barplots side by side. My code below only print 5 names from 9 names I gave. Problem: how to print all of those 9 names? I use cex=0.8 but did not work, it gave me error message. d<-matrix(rpois(45,3),5,9) barplot(d,beside=T,col=rainbow(5),names=c("CRTL","LSB","ONEMKR",

I can think of many brute-force ways to do this outside of R, but was wondering if there was a simple/elegant solution within R instead. I have a table that looks something like the following: Factor1 Factor2 Value A 11/11/2009 5 A 11/12/2009 4 B 11/11/2009 7 B 11/13/2009 8 >From that I need to generate all permutations of Factor1 and Factor2 and force a 0 for any combination that doesn?t

Hi all, Looking at the help file for prcomp and the code in stats:::prcomp.default, the scale parameter for the default S3 method has a trailing period: it written as scale. I assume there is a reason for it (backwards compatibility with S was suggested) but I thought I'd ask. Thanks, Greg -- Greg Hirson ghirson at ucdavis.edu Graduate Student Agricultural and Environmental Chemistry

Dear members, I want to create 8 graphs and write it into one page using mfrow=c(4,2). How to make all graphs (including the titles, legends, line types) to be scale down (resized proportionally). As an illustration, below is the code: pdf("testmfrow.pdf") par(mfrow=c(4,2)) x<-seq(1:10) y1<-rnorm(10) y2<-rnorm(10,mean=2,sd=1) y3<-rnorm(10,mean=3,sd=1)

Hi all, Does anyone know how to plot overlapping qqnorm plots on the same window? Suppose I have data in the vector x and y: qqnorm(x) lines(qqnorm(y)) I though these two lines will do the job... However, lines doesn't seem to work. Anyways, thanks in advance! -- View this message in context: http://www.nabble.com/Plotting-two-qqnorm-plots%3A-tp25352893p25352893.html Sent from the R help

Hi everybody, Does anyone know what problem may be with this test. I am applying 5 different normality tests and use p-values for them, but for some reason S-W gives me NA, while sample size is 100. Any ideas? Thanks a lot! [[alternative HTML version deleted]]

Hello everyone. In my last post I did not explained my problem quite well. I made a principal component analysis and took the 2 first principal components. I made ​​a chart of my points based on the score of the 2 PC. I would like to add on this graph a 95% confidence region. To do this I used the ellipse function as follows: pcsref=PC$score[data[,1]==ref,1:2] #matrix containing the scores

Hi! Does anybody know a string function that would calculate how many characters two strings share? I.e. ("Hello World","Hello Peter") would be 7. Thanks. Laetitia

useR's, I want to be able to rotate a matrix 90 degrees, clockwise. For example, > mat [,1] [,2] [,3] [,1] 1 2 1 [,2] 3 2 6 [,3] 4 5 3 I want to rotate it, so that it looks like this... [,1] [,2] [,3] [,1] 4 3 1 [,2] 5 2 2 [,3] 3 6 1 Does anyone know a quick and straightforward way to do this? Thanks in advance. -- View

Hi, I tried looking through google search on whether there's a way to computer the median for each row of a nxn matrix and return the medians for each row for further computation. And also if the number of columns in the matrix are even, how could I specify which median to use? Thank you very much! -- Edward Chen [[alternative HTML version deleted]]

Hi - Many organizations now make their data available as XML via a REST web service architecture. Is there any R package or facility to access this type of data directly (eg, to make the HTTP GET request and have the downloaded data put into an R data frame)? I used several R search sites to look for an answer, but came up with very little. Any help would be appreciated. Thanks very much. Gary

Hi all, I have a vector of strings and need to count the number of times a string appears in the vector. eg: [1] spp6 spp10 spp6 spp6 spp4 spp2 spp9 spp10 spp5 spp2 spp2 spp3 [13] spp4 spp3 spp6 spp10 spp6 spp4 spp9 spp3 spp6 spp1 spp10 spp8 [25] spp2 spp10 spp9 spp7 spp1 spp3 spp8 spp6 spp3 spp8 spp6 spp5 [37] spp5 spp9 spp3 spp1 spp4 spp5 spp9 spp3

R-list   I am sorry for asking this stupid question, but i have been running in circles. I want to randomly generate a scaling point of between 1 and 10, for say hundred entries, where the first 10% percent is has rates between 2 and 7, the next 15% 3 and 7, 20% between 3 and 9, 20% between 3 and  10, 35% between 5 and 10. The problem is that i can only generate the usual 100 using runif function

I deal with a huge amount of Biology data stored in different databases. The databases belongig to Bioconductor organization can be accessed through Bioconductor packages. Unluckily some useful data is stored in databases like, for instance, miRDB, miRecords, etc ... which offer just an interactive HTML interface. See for instance http://mirdb.org/cgi-bin/search.cgi,

Dear R helpers,   Suppose I am dealing with no of interest rates at a time and the no of interest rates I am selecting for my analysis is random i.e. it can be 2, can be 10 or even higher. The R-code I had written (with the guidance of R helpers obviously and I am really grateful to all of you) as of now is sort of hard coding when it comes to reading interest rates as an input e.g.   ## INPUT  

Is that possible to create superscript text on the graph legend, for example to put "cm2" (centimeter square) on the legend. Please show me how to do it. Thanks. -- Agus Susanto [[alternative HTML version deleted]]

Dear list, I have come across this issue: combn(letters[1:5], 3) [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,] "a" "a" "a" "a" "a" "a" "b" "b" "b" "c" [2,] "b" "b" "b" "c" "c" "d" "c"