similar to: Substituting numerical values using `apply'

When installing asterisk, I follow de "Getting Started" manual and i get the following error while compilig asterisk: if [ -d CVS ] && ! [ -f .version ]; then echo CVS-HEAD-08/06/04-09:53:57 > .version; fi bison ast_expr.y --name-prefix=ast_yy -o ast_expr.c make: *** [ast_expr.c] broken pipe Just this, nothing else. Zaptel and Libpri installed without any problem and system

Hi all, I have a question regarding the anova function aov(). I want to perform an anova calculation using one grouping variable but more than one numerical variables: So instead of: aov(v ~ g) I want something like aov(v1 + v2 + v3 ~ g) Essentially I want to find out whether the variables v1, v2, v3, etc can collectively discriminate between different values of variable g. Could

Hi all, I have a question regarding the boxplot function. The data I am working on has 1 grouping variable (G) and it has many numerical variables (V1, V2, V3, V4, Vx, etc). What I would like to do is create a boxplot where the Y-axis represents the numerical values of variable V1...Vx (all the variables have the same range). The X-axis needs to represent the G-V combination. So suppose the

I am having following problem: I?m constructing model for calculation of area of triangle. I know sides a, b, and gamma angle. I wish to calculate the area using heron?s formula: S <- sqrt(s*(s-a)*(s-b)*(s-c)) where s <- (a+b+c)/2 and c is calculated using law of cosines: c <- sqrt(a^2 + b^2 -2*a*b*cos(gamma)) since i am calculating a regression model, i need derivation of this

Dear R-help subscribers Would you tell me how to apply SSfpl with binary data as below? Unfortunately, there is not the EXAMPLE in help(SSfpl) for binary data but for quantitative data(Chick). V1: dose V2: log-transformed dose V3: response (rate) V1 V2 V3 1 0.775 -0.2548922 0.1666667 2 5.000 1.6094379 0.8148148 3 10.000 2.3025851 0.5000000 4 20.000 2.9957323

Hi, I have some trouble with the following: I have a table of 7 rows and 6columns. The columns 1,2,3 have information about the number of employees. The columns 4,5,6 have information about the number of working hours. Each row, is corresponding with a week. My goal is to make a boxplot, histogram etc. of the columns 4, 5 and 6 (thus, the data of the number of working hours). How can I select by

Dear all Just for fun, I have just downloaded the paper mentioned below and checked it with R-1.6.1. Everything is ok with exception of Table 2b, where I get always 1 instead of 0.5: > pbinom(1e15,2e15,0.5) [1] 1 Which value should be correct? Best regards Christian Stratowa ============================================== Christian Stratowa, PhD Boehringer Ingelheim Austria Dept NCE Lead

I installed R (R-2.4.1-win32.exe) on a new computer with Windows Vista and a 64 bit operating system (hp dv9000 with intel core t7200). The base R runs fine, but I can not get any of the packages to load. From within R I choose install packages choose a site then a package. I tried installing 2 packages and get similar errors (see below), I just copied and pasted lines from R. Can anyone

Dear R-users, For a data frame (say in this example X) I want to look up the corresponding value in a 'look-up data frame' (in this example Y). The for-loop works but is very time-consuming because 'X' in reality is very big. Therefore I would like to have a solution with apply. However, I do not succeed. Any suggestions? Thanks in advance, Hanneke

Hello, I am moving LDAP from one domain to another We have moved off of a.wustl.edu network to b.school.edu network. I have searched vi /etc/nslcd.conf vi /etc/openldap/ldap.conf and removed all referances to "a" I restarted /etc/init.d/nscd restart this is redhat 6.7, and my ldap server is now ldap.b.wustl.edu:389 a.school.edu to b.school.edu I keep getting messages

Hi I have 3 dataframes, a,b,c with 0/1 values...i have to check a condition for dataframe a and b and then input the rows ids to datframe c . In the if condition, I AND the 2 rows of from a and b and then see if the result is equal to one of them. I have done this using a for loop, however, it takes a long time to execute with larger dataset..Can you help me do it using apply function so that i

Hi Neha, Perhaps merge() from base or join from dplyr is what you are looking for. data. table could also be interesting. Hth Ulrik On Wed, 2 May 2018, 21:28 Neha Aggarwal, <aggarwalneha2000 at gmail.com> wrote: > Hi > > I have 3 dataframes, a,b,c with 0/1 values...i have to check a condition > for dataframe a and b and then input the rows ids to datframe c . In the if >

Hi all, I have n independent variables A_1, A_2, A_3,......,A_n, and each with known variances var(A_1), var(A_2),..., but unknown mean. How can I get the approximation of the variance of the product of the variables using numerical computation, i.e. var(A_1*A_2*A_3*.....*A_n)? Thanks. Sincerely, Yanwei Zhang Department of Actuarial Research and Modeling Munich Re America Tel: 609-275-2176

Hello How can I apply functions along "layers" of a data matrix? Example: daf <- data.frame( 'id' = rep(1:5, 3), matrix(1:60, nrow=15, dimnames=list( NULL, paste('v', 1:4, sep='') )), rep = rep(1:3, each=5) ) The data frame "daf" contains 3 repetitions/layers (rep) of 4 variables of 5 persons (id). For some reason, I want to calculate

Hello everyone, I have been trying to figure out away to integrate under a spline produced by the package tps(fields). As the package does not output functions I am trying to do something similar to the trapezium rule. My data are 3D (x, y & z). I have extracted from the surface output by Tps the values of z at regular intervals so that I have a grid of figures, for example: 1 4 6 6 8 8

Hello all, I'm hoping to find a way to evaluate the following sort of integral in R. \int_a^b \int_{g(y)}^Inf f(x,y) dx dy. The integral has no closed form and so must be evaluated numerically. The "adapt" package provides for multidimensional integration but does not appear to allow the limits of integration to be a function. I need to evaluate a number of integrals of this

Hi R-experts, how can I apply a function to each numeric column of a data frame and return the whole data frame with changes in numeric columns only? In my case I want to do a median imputation of the numeric columns and retain the other columns. My dataframe (DF) contains factors, characters and numerics. I tried the following but that does not work: foo <- function(x){

I have a data set of many rows and many columns in which both the rows and the columns have associated grouping factors. Is there a way to do what 'aggregate' does but in the other dimension? The way I have been doing this is to use 'aggregate' on the data in the usual way and then rotate the result and apply 'aggregate' again. This works but is a little messy and I was

Dear R community, I am trying to apply a simple operation to several dataframes (e.g. nrow) and cannot get the looping to work. My objective is to get an output that indicates me the number of rows for every dataframe. > c V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 1 1 11 21 31 41 51 61 71 81 91 2 2 12 22 32 42 52 62 72 82 92 3 3 13 23 33 43 53 63 73 83 93 4 4 14 24 34 44 54 64 74 84 94 5 5

I have a question that must have a simple answer (but eludes me). I need a row-by-row logical comparison across three numeric variables in a data frame: foo$x, foo$y, foo$z. The logic is if( x < y || x > z ) 1 else 0 for a particular row. It is simple and very inefficient to use for(i in 1:length(foo$x)){ } loops. How can I accomplish this using sappy( ) / lapply( ) / apply( ) or