similar to: Numbering sequences of non-NAs in a vector

Displaying 20 results from an estimated 4000 matches similar to: "Numbering sequences of non-NAs in a vector"

2010 May 20
3
regex help: splitting strings with no separator
Greetings, I have a vector of values that are a word followed by a number, e.g., x = c("Apple12","HP42","Dell91"). The goal is to split this vector into two vectors such that the first vector contains just the words and the second contains just the numbers. I cannot use strsplit (or at least I do not know how) as there is no obvious separator. I can use sub to
2010 Jan 06
1
Write a blank line to CSV
Greetings and happy new year! I'm attempting to write a series of tables to a CSV file, and would like to insert a blank line after each table. To do this, I use: > write.csv(NULL,"tables.csv",append=T) which appears to work, except that this warning is thrown: > Warning message: > In write.table(NULL, "tables.csv", append = T, col.names = NA, : > appending
2010 Aug 06
2
stats::reshape question
Hello, A quick question for my edification. When I run the following (R 2.8.1 on Microsoft Windows): > d = data.frame(x1=c(1,2),x2=c(3,4),y1=c(5,6),y2=c(7,8)) > reshape(d,varying=c("y1","x1","y2","x2"),v.names=c("y","x"),dir="long") I found myself surprised by the results--the column labeled "y" is actually
2010 Dec 02
2
Hmisc label function applied to data frame
Hello, I'm attempting to create a data frame with correlations between every pair of variables in a data frame, so that I can then sort by the value of the correlation coefficient and see which pairs of variables are most strongly correlated. The sm2vec function in the corpcor library works very nicely as shown here: library(Hmisc) library(corpcor) # Create example data x1 = runif(50) x2 =
2011 Sep 26
1
How to Store the executed values in a dataframe & rle function
Hi group, This is how my test file looks like: Chr start end sample1 sample2 chr2 9896633 9896683 0 0 chr2 9896639 9896690 0 0 chr2 14314039 14314098 0 -0.35 chr2 14404467 14404502 0 -0.35 chr2 14421718 14421777 -0.43 -0.35 chr2 16031710 16031769 -0.43 -0.35 chr2 16036178 16036237 -0.43 -0.35 chr2 16048665 16048724 -0.43 -0.35 chr2 37491676 37491735 0 0 chr2 37702947 37703009 0 0
2010 Sep 16
2
glm: formula vs character
Hello, This is a question motivated by curiosity, not a pressing problem. Any responses are much appreciated! In the following code, function reg1 calls glm with a formula object while reg2 uses a string. In both cases, glm works; however, in the second case, the add1 function fails with the following message: "Error in eval(predvars, data, env) : invalid 'envir' argument."
2007 Oct 09
3
identify number of sequences from a vector
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2005 Mar 11
2
Calculating lengths of runs of 0 or 1 sequences in meteorological data
Dear List Members, I need some help about programming in S language. My problem is as follows: I have meteorological data (about rainfall measurement each day from 1989-2002), say like http://www.angelfire.com/ab5/get5/data.rainfall.txt or http://www.angelfire.com/ab5/get5/R.rainfall.txt in a sequence of 0(denoting dry day)'s and 1(denoting wet day)'s. I want to construct a frequency
2020 Aug 26
1
NAs and rle
Hi All, A twitter user, Mike fc (@coolbutuseless) mentioned today that he was surprised that repeated NAs weren't treated as a run by the rle function. Now I know why they are not. NAs represent values which could be the same or different from eachother if they were known, so from a purely conceptual standpoint there is no way to tell whether they are the same and thus constitute a run or
2012 Mar 08
3
Calculating length of consecutive sequences within a vector
Hi all, I have a nx1 logical array of zeros and ones and I want to calculate the individual lengths of all 1-consecutive sequences contained in it. Is there an easy quick way to do this in R? So, if I have a vector such as 111001101000011111110 I would like to get (1) 3, (2) 2, (3) 1, (4) 7 Any help would be appreciated! thanks! Jorge [[alternative HTML version deleted]]
2011 Jun 01
3
Identifying sequences
Hallo Everybody Consider the following vector a=1:10 b=20:30 c=40:50 x=c(a,b,c) I need a function that can tell me that there are three set of continuos sequences and that the first is from 1:10, the second from 20:30 and the third from 40:50. In other words: a,b, and c. regards Christiaan [[alternative HTML version deleted]]
2008 Dec 09
2
Need help optimizing/vectorizing nested loops
Hi, I'm analyzing a large number of large simulation datasets, and I've isolated one of the bottlenecks. Any help in speeding it up would be appreciated. `dat` is a dataframe of samples from a regular grid. The first two columns are the spatial coordinates of the samples, the remaining 20 columns are the abundances of species in each cell. I need to calculate the species richness in
2006 Oct 08
1
Simulate p-value in lme4
Dear r-helpers, Spencer Graves and Manual Morales proposed the following methods to simulate p-values in lme4: ************preliminary************ require(lme4) require(MASS) summary(glm(y ~ lbase*trt + lage + V4, family = poisson, data = epil), cor = FALSE) epil2 <- epil[epil$period == 1, ] epil2["period"] <- rep(0, 59); epil2["y"] <- epil2["base"]
2004 Apr 05
3
2 lme questions
Greetings, 1) Is there a nice way of extracting the variance estimates from an lme fit? They don't seem to be part of the lme object. 2) In a series of simulations, I am finding that with ML fitting one of my random effect variances is sometimes being estimated as essentially zero with massive CI instead of the finite value it should have, whilst using REML I get the expected value. I guess
2009 Jan 22
1
convergence problem gamm / lme
Hope one of you could help with the following question/problem: We would like to explain the spatial distribution of juvenile fish. We have 2135 records, from 75 vessels (code_tripnr) and 7 to 39 observations for each vessel, hence the random effect for code_tripnr. The offset (‘offsetter’) accounts for the haul duration and sub sampling factor. There are no extreme outliers in lat/lon. The model
2016 Apr 08
3
Generating Hotelling's T squared statistic with hclust
I am doing a cluster analysis with hclust. I want to get hclust to output the Hotelling's T squared statistic for each cluster so I can evaluate is data points should be in a cluster or not. My research to answer this question has been unsuccessful. Does anyone know how to get hclust to output the Hotelling's T squared statistic for each cluster? Mike [[alternative HTML version
2011 Jan 20
2
circular reference lines in splom
Hello everyone, I'm stumped. I'd like to create a scatterplot matrix with circular reference lines. Here is an example in 2d: library(ellipse) set.seed(1) dat <- matrix(rnorm(300), ncol = 3) colnames(dat) <- c("X1", "X2", "X3") dat <- as.data.frame(dat) grps <- factor(rep(letters[1:4], 25)) panel.circ <- function(x, y, ...) { circ1
2009 Feb 22
2
Semantics of sequences in R
Inspired by the exchange between Rolf Turner and Wacek Kusnierczyk, I thought I'd clear up for myself the exact relationship among the various sequence concepts in R, including not only generic vectors (lists) and atomic vectors, but also pairlists, factor sequences, date/time sequences, and difftime sequences. I tabulated type of sequence vs. property to see if I could make sense of all
2009 Feb 22
2
Semantics of sequences in R
Inspired by the exchange between Rolf Turner and Wacek Kusnierczyk, I thought I'd clear up for myself the exact relationship among the various sequence concepts in R, including not only generic vectors (lists) and atomic vectors, but also pairlists, factor sequences, date/time sequences, and difftime sequences. I tabulated type of sequence vs. property to see if I could make sense of all
2008 Jul 24
2
NAs - NAs are not allowed in subscripted assignments
Dear List, I ran into some trouble handling missing values. Assume 2 vectors (numeric) including NAs a <- c(rep(seq(1,4),4),NA,NA) b <- c(sample(1:2,14,replace=T),NA,NA,1,2) I want to replace the values of vector a that are smaller than 2 and larger than 3 into NAs only in case vector b equals 1 a[b==1][a[b==1]<2 | a[b==1]>3] <- NA The following error accurse: NAs are not