Displaying 20 results from an estimated 800 matches similar to: "How to separate the string?"
2009 Aug 03
2
Some SQL Challenges
Hi,
Im trying to complete a list of jobs using SQL Querries and some "if else"
commands but im stucked in some steps. Could any of you give me some help?
-in COLUMN1 change the format 20JAN2000:00:00:00 to 20JAN2000 and exclude
every row that date is different from 20.
-extract the first character in COLUMN2 and creat COLUMN3 with that value
ex:
COL2,COL3
135,1
461,4
247,2
-in every
2013 Mar 21
2
Displaying median value over the horizontal(median)line in the boxplot
Hi,
set.seed(45)
test1<-data.frame(columnA=rnorm(7,45),columnB=rnorm(7,10)) #used an example probably similar to your actual data
apply(test1,2,function(x) sprintf("%.1f",median(x)))
#columnA columnB
# "44.5"? "10.2"
par(mfrow=c(1,2))
lapply(test1,function(x) {b<-
2009 May 14
2
Function to read a string as the variables as opposed to taking the string name as the variable
I am writing a custom function that uses an R-function from the
reshape package: cast. However, my question could be applicable to
any R function.
Normally one writes the arguments directly into a function, e.g.:
result=cast(table1, column1 + column2 + column3 ~ column4,
mean) (1)
I need to be able to write this statement as follows:
result=cast(table1, string_with_columns ~
2024 Jun 06
2
R Shiny Help - Trouble passing user input columns to emmeans after ANOVA analysis
Hello everybody,
I have experience coding with R, but am brand new to R Shiny. I am trying
to produce an application that will allow users to upload their own
dataset, select columns they want an ANOVA analysis run on, and generate
graphs that will allow users to view their results. However, I am getting
the following error: *"Argument is of length zero."*
Being new to Shiny, I am
2007 Oct 19
1
(no subject)
# Hello
# I have a question regarding pairwise calculations of a matrix using a
"for-loop."
# Below I have a matrix "X" with 8 columns. These are Genotypic data so
Column1 & Column2 is
# a unit, Column3 & Column4 is a unit, Column5 & Column6 is a unit, and
Coulmn7 & 8 is a unit.
# I have a loop designed to calculate the number of times an individual in
2007 Oct 19
1
conduct pairwise column comparisons without comparing a column to itself
# Hello
# I have a question regarding pairwise calculations of a matrix using a
"for-loop."
# Below I have a matrix "X" with 8 columns. These are genotypic data so
Column1 & Column2 is
# a unit, Column3 & Column4 is a unit, Column5 & Column6 is a unit, and
Coulmn7 & 8 is a unit.
# I have a loop designed to calculate the number of times an individual in
2012 Jun 12
4
How to index a matrix with different row-number for each column?
here's my question: suppose I have a matrix:
mt<-matrix(1:12,ncol=6)
now I have a vector
vt<-c(1,2,2,2,1,2)
which means I want to get:
the 1st row for column1;
the 2nd row for column2;
the 2nd row for column3;
the 2nd row for column4;
...
that what I want is this vector:
1,4,6,8,9,12
Does anyone know how to do this fast?
I know I can use for-loop to travel all columns,but
2008 Feb 26
1
Split data.frames depeding values of a column
Hello to all
is there a function wich splits a data.frame (column1,column2,column3,....)
into
data1 <-(column1,column3....) #column2 = 1
data2 <-(column1,column3....) #column2 = 2
data3 <-(column1,column3....) #column2 = 3
...
Regards Knut
2004 Oct 25
2
Reading sections of data files based on pattern matching
I am about to write general functions to read the output of simulations
models.
These model generate output files with different sections which I want
to analyze plot etc.
Since this will be used many people at the department I wanted to make
sure that will do this in the best way.
For instance I want to read a snippets of data from a text that look
like this.
2010 Feb 27
1
New Variable from Several Existing Variables
I am new to R, but have been using SAS for years. In this transition period,
I am finding myself pulling my hair out to do some of the simplest things.
An example of this is that I need to generate a new variable based on the
outcome of several existing variables in a data row. In other words, if the
variable in all three existing columns are "Yes", then then the new variable
should
2006 Apr 06
1
reshape question
Hi,
I have a data fram like this:
date column1 column2 column3 value1 value2 value3
1-1 A B C 10 5 2
2-1 A B D 5 2 0
3-1 A B E 17 10 7
How can I reshape it to:
date column1 column2 column3 v x
1-1 A B C value1 10
1-1 A B C value2 5
1-1 A B C value3 2
2-1 A B D value1 5
2-1 A B D value2 2
2-1 A B D value3 0
3-1 A B E value1 17
3-1 A B E value2 10
3-1 A B E value3 7
Thx!
Regards,
Richard
2010 Feb 09
3
split strings in a vector and convert it to a data.frame
hi,
I have a vector full of strings like;
xy_100_ab xy_101_ab xy_102_ab xy_103_ab
I want to seperate each string in three pieces and the separator should be the "_"
at the end I want a data.frame like:
column1 column2 column3
xy 100 ab
xy 101 ab
xy 102 ab
xy 103 ab
I tried strsplit but I couldn't figure out how to convert the list I get into a data.frame.
I just
2006 May 09
9
Active Record HELP!!!!!
Hello,
Can someone kindly tell what the heck creating a relationship does in
active record?
I understand the idea of joining the tables and such. But how do I use
it? Is it available in a scaffold? How about when I want to view a
record and want to see all the joined data from the other table? Do I
have to manually code the data I want from the other table? Does this
automatically make the
2009 Dec 03
2
Dataframe help
Hi there
I have two dataframes
Dataframe_1
column_1 colum_2
121 12345
145 1675
167 2765
Dataframe_2
column_1 column2
121 abc
345 lmn
167 efg
I want a resulting dataframe
121 12345 abc
167 2765 efg
how do i go abt it
Ramya
--
View this message in context: http://n4.nabble.com/Dataframe-help-tp947934p947934.html
Sent from the R
2004 Nov 23
5
number of pairwise present data in matrix with missings
is there a smart way of determining the number of pairwise present data
in a data matrix with missings (maybe as a by-product of some
statistical function?)
so far, i used several loops like:
for (column1 in 1:99) {
for (column2 in 2:100) {
for (row in 1:500) {
if (!is.na(matrix[row,column1]) & !is.na(matrix[row,column2])) {
pairs[col1,col2] <- pairs[col1,col2]+1
2010 May 31
2
accessing a data frame with row names
Readers,
I have entered a file into r:
,column1,column2
row1,0.1,0.2
row2,0.3,0.4
using the command:
dataframe<-read.table("/path/to/file.csv",header=T,row.names=1)
When I try the command:
dataframe[,2]
I receive the response:
NULL
I was expecting:
row1 0.2
row2 0.4
What is my error with the syntax please?
Yours,
r251
mandriva2009
2009 Apr 03
2
how to sort and plot data?
hi,
Previously my email very simple and less information. Let say I have raw
data as below:-
user_id website time
20 google 0930
21 yahoo 0935
20 facebook 1000
25 facebook 1015
61 google 0940
60 yahoo 1050
40 friendster 1115
61 google 1200
40
2009 Jun 15
2
Help with syntax error
Hi,
I have written boxplot commands of this form before, but I don''t quite understand why the function call is reporting a syntax error in this instance. All parameters passed to the function are strings.
Thanks in advance.
Payam
> simplevar <- function(wframe,column1,column2) {
+ tframe <- get(wframe)
+ x1 <- which(names(wframe)==column1)
+ x2 <-
2009 Jun 17
6
script help
Hi
?
I have a file. list.txt (two columns)
?
column1??? column2
name??????? address
?
?
I need to put in the letter file letter.txt eg:
?
Dear: Chloe
Address: CA
?
Can I use this
?
for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt
?
Thank you for your help
?
?
?
?
?
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2006 Jun 07
4
Question: coding protected methods
Apologies first, because I need to ramp up on Ruby and coding Ruby in Rails,
however it''s my 3rd day with this beast :) so I''m asking :
When I added protected methods to the model before it was like:
protected
method....................
end
Would this be a valid way to write a protected method as well ?:
attr_protected :column1, :column2
Perhaps this particular call