Displaying 20 results from an estimated 1000 matches similar to: "Naive knn question"
2009 Jun 17
1
Predict Fanny Membership
Hello List,
My question is an elementary one. I have run a fuzzy kmeans cluster using
FANNY to group freshwater fish assemblages. I then went in the field to
validate that classification and have retrieved new assemblage data for a
new suite of streams. Therefore I would like to use Predict to determine how
well the original clustering fits the new data. However I have not figured
out a
2009 Nov 15
1
Problem building package for R 2.10.0 on Mac OS X
Hi
I have submitted a package (rioja) to CRAN. It checks OK for all R versions and OS's except r-release-macosx-ix86 where it fails when checking the examples. Specifically, it fails because R can't find the package vegan which is needed in a function. Here is the snippet from the check results:
### Begin snippet
checking examples ... ERROR
Running examples in 'rioja-Ex.R'
2011 Sep 08
1
error in knn: too many ties in knn
Hello.
I found the behavior of knn(
http://stat.ethz.ch/R-manual/R-devel/library/class/html/knn.html) function
looking very strange.
Consider the toy example.
> library(class)
> train <- matrix(nrow=5000,ncol=2,data=rnorm(10000,0,1))
> test <- matrix(nrow=10,ncol=2,data=rnorm(20,0,1))
> cl <- rep(c(0,1),2500)
> knn(train,test,cl,1)
[1] 1 1 0 0 1 0 1 1 0 1
Levels: 0 1
It
2007 Nov 28
2
Clustering
Hello all!
I am performingsome clustering analysis on microarray data using
agnes{cluster} and I have created my own dissimilarity matrix according to a
distance measure different from "euclidean" or "manhattan" etc. My question
is, if I choose for example method="complete", how are the distances
between the elements calculated? Are they taken form the dissimilarity
2006 Jun 07
1
knn - 10 fold cross validation
Hi,
I was trying to get the optimal 'k' for the knn. To do this I was using the following function :
knn.cvk <- function(datmat, cl, k = 2:9) {
datmatT <- (datmat)
cv.err <- cl.pred <- c()
for (i in k) {
newpre <- as.vector(knn.cv(datmatT, cl, k = i))
cl.pred <- cbind(cl.pred, newpre)
cv.err <- c(cv.err, sum(cl != newpre))
}
2007 Apr 11
1
Function knn.dist from knnflex library
Hello,
I am feeling that this question can have a very simple answer, but I
can't find it.
I need to use the function knn.dist from knnflex library.
Whatever I try, I get the error:
Error in as.vector.dist(x, "character") : unused argument(s) ("character")
First example:
> a<-NULL
> a<-rbind(a,c(5.2,-8.1))
> a<-rbind(a,c(8.8,-16.1))
>
2004 Mar 29
1
Interpreting knn Results
Maybe you should show your colleague how to access help pages in R? Right
in ?knn, it says:
prob: If this is true, the proportion of the votes for the winning
class are returned as attribute 'prob'.
so 1.0 mean all three NNs are of the `winning'; i.e., predicted, class, and
0.66667 means 2 out of the 3 NNs are of the winning class, etc.
Andy
> From: Ko-Kang
2005 Jul 06
1
Error message NA/NaN/Inf in foreign function call (arg 6) when using knn()
I am trying to use knn to do a nearest neighbor classification. I tried using my dataset and got an error message so I used a simple example to try and understand what I was doing wrong and got the same message. Here is what I typed into R:
try
[,1] [,2] [,3] [,4]
r "A" "A" "T" "G"
r "A" "A" "T" "G"
f
2008 Oct 29
1
Help with impute.knn
ear all,
This is my first time using this listserv and I am seeking help from the
expert. OK, here is my question, I am trying to use impute.knn function
in impute library and when I tested the sample code, I got the error as
followingt:
Here is the sample code:
library(impute)
data(khanmiss)
khan.expr <- khanmiss[-1, -(1:2)]
## ## First example
## if(exists(".Random.seed"))
2004 May 05
1
Segfault from knn.cv in class package (PR#6856)
The function knn.cv in the class package doesn't have error checking to
ensure that the length of the classlabel argument is equal to the number
of rows in the test set. If the classlabel is short, the result is often
a segfault.
> library(class)
> dat <- matrix(rnorm(1000), nrow=10)
> cl <- c(rep(1,5), rep(2,5))
> cl2 <- c(rep(1,5), rep(2,4))
> knn.cv(dat, cl)
[1] 2
2010 Dec 22
0
help with knn.impute
Hi
I have a dataset from biological data with forty samples whichh relate to four
different treatments. Each sample has thousands of values but as usuual contains
missing values
I want to use knn to imput these missing values. I am doing tthis using
knn.impute. Do I need to specify the various groups or can I just use the
knn.impute command on the whole dataset together.
Also I am setting
2005 Oct 06
1
how to use tune.knn() for dataset with missing values
Hi Everybody,
i again have the problem in using tune.knn(), its giving an error saying
missing values are not allowed.... again here is the script for
BreastCancer Data,
library(e1071)
library(mda)
trdata<-data.frame(train,row.names=NULL)
attach(trdata)
xtr <- subset(trdata, select = -Class)
ytr <- Class
bestpara <-tune.knn(xtr,ytr, k = 1:25, tunecontrol = tune.control(sampling
2005 Mar 21
1
How to do knn regression
How can I do a simple k nearest neighbor regression in R? My training
data have 1 predictor and 1 outcome, both are numeric. I also need to
use FPE and SC to find the optimal model. I know there is knn() in
class package, but it's for knn classification. I also find a kknn
package. What function should I use?
Thanks in advance!
Menghui
2005 Mar 15
1
KNN one factor predicting problem
Could anybody help me out please?
> cl<-as.factor(traindata[,13])
> knn(traindata[1:295,2], newdata[1:32,2], cl,k=2,
prob=TRUE)
Error in knn(traindata[1:295, 2], newdata[1:32, 2],
cl, k = m, prob = TRUE) :
Dims of test and train differ
Both traindata and newdata have 13 elements. Only one
of the first 12 elemnets is needed to predict the 13
element.
What's the problem of
2008 Aug 11
1
question about knn
Hello all,
am a newby in R,
am trying the knn function, and am doing just a stupid test :
> knn(c(1,2,3,4,5,6), c(3), k=4 ,prob=TRUE,factor(c(1:6)))
the result is unstable !! i have each time different result :
[1] 5
attr(,"prob")
[1] 0.1666667
Levels: 1 2 3 4 5 6
[1] 4
attr(,"prob")
[1] 0.1666667
Levels: 1 2 3 4 5 6
[1] 1
attr(,"prob")
[1] 0.1666667
Levels:
2011 Aug 30
1
ROC plot for KNN
Hi I need some help with ploting the ROC for K-nearest neighbors. Since KNN
is a non-parametric classification methods, the predicted value will be
either 0 or 1.
It will not be able to test for different cutoff to plot ROC. What is the
package or functions I should use to plot ROC for KNN?
Thanks.
Qian
[[alternative HTML version deleted]]
2011 Aug 31
8
!!!function to do the knn!!!
hi, r users
i have a problem with KNN.
i have 2 datasets, X0 and X1.
>dim(X0)
>1471*13
dim(X1)
>5221*13
and for every instances in the dataset X1, i want to find the nearest
neighbour(1nn) in the dataset X0.
and i dont have the true classifications of dataset X1.
but the function knn() need true classifications(cl) to do prediction.
i just curious if there are some other function
2002 Jun 13
0
results of knn() command
Hi all,
I'm using knn() to estimate the missing values of a matrix and I just want
to output the complete matrix resulting from this command.
For example
m is a matrix with missing values
m1<-knn(m,k=10)
I want m1 to be a matrix I can work with, that is to say I want to apply
mean(m), var(m)...but the format is changed.
How do I solve this problem?
thanks
2012 Nov 15
0
R KNN Regression Help
Hi Experts,I'm writing up my thesis on open source data mining at the moment
and I have to do some simple R experiments; however, I have very little
experience with R.. And I am hoping one of you can please help me out:)I
need need to run a regression task that uses the KNN algorithm with k = 5
and cross validation = 10 on the computer hardware datset from the uci repo
and report the RMSE. All
2011 Mar 02
2
*** caught segfault *** when using impute.knn (impute package)
hi,
i am getting an error when calling the impute.knn
function (see the screenshot below).
what is the problem here and how can it be solved?
screenshot:
##################
*** caught segfault ***
address 0x513c7b84, cause 'memory not mapped'
Traceback:
1: .Fortran("knnimp", x, ximp = x, p, n, imiss = imiss, irmiss,
as.integer(k), double(p), double(n), integer(p),