similar to: Error when using step

I posted this question way down at teh end of another thread realted to an error in step, but that was stupid since it really is another matter altogether. I should have posted it separately, as I have now done. The code below creates a data.frame comprising three marginally noisy surfaces. The code below (including a fix courtesy of David Winsemius that avoids a step function error through use

I have a large dataset grouped by a factor and I want to perform a regression on each data subset based on this factor. There are many ways to do this, posted here and elsewhere. I have tried several. However I found one method posted on the R wiki which works exactly as I want, and I like the elegance and simplicity of the solution, but I don't understand how it works. Its all in the formula

Hi, When i tried to merge two datasets (multiple to multiple merge), i met a problem on how to stop a possible loop in the sampling arguments. ###My codes are as follows.### data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE)

Hi there, data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE) data1<-data.frame(data1) names(data1)<-c("areaid","x","y","date") data1 areaid x y date 1 1 1.2 1.3 3/23/2004 2 1 1.5 2.3 3/22/2004 3 2

Hi Rusers, I found sometimes that the same values cannot be judged to be the same in R. Anybody knows the probelm? I think i ignored some minor detail. Thanks. Here is the example. ############ data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE)

Hi all, I am trying to create images in R suitable for journal publication. I'd like to make an image that is 3.6" wide and 5.08" length, and 1200 dpi. When I create a tiff file that is 800 dpi and 4x4", it works (although doesn't look good). But when I create a tiff that is the size and dpi I want, it doesn't work. I get the following error: Error in tiff(filename =

I've searched the Web with Google and do not find what might cause this particular error from an invocation of cenboxplot: cenboxplot(cu.t$quant, cu.t$ceneq1, cu.t$era, range=1.5, main='Total Recoverable Copper', ylab='Concentration (mg/L)', xlab='Time Period') Error in if (n > 0) (1L:n - a)/(n + 1 - 2 * a) else numeric() : argument is of length zero I do

Hi I have a very big data.frame : str(fslu12) 'data.frame': 277200 obs. of 11 variables: $ V1 : num 304 304 304 304 304 ... $ V2 : num 300 300 300 300 300 300 300 300 300 300 ... $ V3 : num 10 10 10 10 10 10 10 10 10 10 ... $ V4 : num 79.1 52 30.6 37.3 63 79.1 52 30.6 37.3 63 ... $ V5 : num 0.005 0.00498 0.00496 0.00491 0.00484 ... $ V6 : num 0.01 0.00997 0.00988 0.00969

Hello, I'm relatively new to R. I've read the intro guide, but I can't quite figure out how to: I have a function: Jcost <- function (theta, in, out) { a <- output - input %*% theta 1/2 * t(a) %*% a } where "theta" is a 2x1 matrix "in" is a 20x2 matrix "out" is a 20x1 matrix return value is a scaler This works well when I only want to

Hello, I have read recent posts on this topic (Dr. Ronnen Levinson's Monday 02:39:55 pm), but before I install a 64 bit system, and purchase more RAM, I want to make sure I understand this interesting issue. I was attempting to plot a data frame containing Dow Jones stock information: > length(Date) [1] 19957 > length(Close) [1] 19957 > head(DowJones) Date Open High

I am creating graphs for a publication and would like them to have the same font size... but when I create a figure with multiple plots, the font size decreases even though I haven't changed the tiff() resolution or pointsize specifications, I have increased the figure size according to how many plots it will ultimately have, and I have made sure the margins are equivalent for single and

CentOS Errata and Security Advisory 2014:0043 Moderate Upstream details at : https://rhn.redhat.com/errata/RHSA-2014-0043.html The following updated files have been uploaded and are currently syncing to the mirrors: ( sha256sum Filename ) i386: 6611318ec0b1db26f564df6ee47c9e1bdf88696ddcd943ebeda373154aba5617 bind-9.8.2-0.23.rc1.el6_5.1.i686.rpm

Hi, I am using aggregate to compute means for later plotting. There are two factors involved and the problem is that the values of the second factor ( Age ) in the means are not in the right order because "10" comes inbetween "1" and "2" What I really want is the numeric value of Age but as.numeric and as.integer returns the level value instead. Is there a way to

I'm using fisher.exact on a 4x2 table and it seems to work. Does anyone know exactly what is going on? I thought fisher.exact is only for 2x2 tables. Note: I can't use chi-squared because I have a couple of cells with 0 and < 5 observations. -- View this message in context: http://r.789695.n4.nabble.com/fisher-exact-for-2x2-table-tp3481979p3481979.html Sent from the R help

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Dear Spencer and Prof. Fox, Thank you for your replies. I'll very appreciate, if you have any ideas concerning the problem described below. First, I'd like to describe the model in brief. In general I consider a model with three equations. First one is for annual GRP growth - in general it looks like: 1) GRP growth per capita = G(investment, migration, initial GRP per

Hello, The range() with complete.cases() removes NA's for the date variables that are read from a data frame. However, the issue is that the same function does not remove NA's for the other date variable that is created using the dplyr/mutate(). The console and the reproducible example are given below. Any advice how to resolve this issue would be appreciated. Thanks, Pradip Muhuri

?s 22:54 de 11/06/2023, javad bayat escreveu: > Dear Rui; > Many thanks for your email. I used one of your codes, > "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works > correctly for me. > Actually I need to expand the codes so as to consider all "Levels" in the > "Layer" column. There are more than hundred

Dear Rui; Many thanks for your email. I used one of your codes, "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works correctly for me. Actually I need to expand the codes so as to consider all "Levels" in the "Layer" column. There are more than hundred levels in the Layer column. If I use your provided code, I have to write it

I've setup dovecot to auth both system and virtual users but it is refusing to work. It keeps saying user is not found. Is there something more that I need to set? dovecot.conf: ============================================================================ = default_mail_env = maildir:/var/mail/%1.1u/%u/Maildir mail_extra_groups = mail protocol imap { } protocol pop3 { } protocol lda {