similar to: expand data

Hello, See my problem below. a<-data.frame(c("s","c","c","n","n","n"),c(rep(1,3),rep(2,3)),c(rep(2,3),rep(1,3)),c("01/01/1999","10/02/2000","13/02/2000","11/02/2000","15/02/2000","23/02/2000"))

Hi, I have Forecast Class and Observed Class in a data matrix as below. > Sample1 FCT OBS 1 1 5 2 2 4 3 3- 3+ 4 3 3 5 3+ 3- 6 4 2 7 5 1 I want to find the difference between Observed and Forecast Classes. How can I get this done? I tried to following to convert the 1 through 5 classes, to 1 through 7 for both OBS and FCT column. > Sample1$OBS2 <- Sample1$OBS

Let's say I have a within-subject experiment with 2 observables, obs1 and ob2 and 2 independent factors, fac1 and fac2. I can do summary( aov( obs1~fac1*fac2 + Error(Subject/(fac1*fac2)) ) ) summary( aov( obs2~fac1*fac2 + Error(Subject/(fac1*fac2)) ) ) to test the 2 observables separately. > summary( fit<-manova( cbind(obs1,obs2)~fac1*fac2 + Error(Subject/(fac1*fac2)) ) ) gives

Hi, newbie question. I have a data-frame with 3 named columns: Name, Obs1, Obs2. The Name column members are made of alphanumeric characters: T1, T2, T3 etc. I would like to acess only that subset of the data-frame with Name == T44. X <- dataframe[dataframe$Name=='T44'] does not work. Any ideas on how to do this? I'm sure I'm missing a simple concept here. Thanks, Anjan --

Hello, I want to do fisher test for the rows in data file which has value less than 5 otherwise chi square test .The p values from both test should be stored in one resulted file. but there is some problem with bold if statement. I don't know how implement this line properly. x = cbind(obs1,obs2,exp1,exp2) a = matrix(c(0,0,0,0), ncol=2, byrow =TRUE) #matrix with initialized values

hi, all I am looking at R package RGL to draw a colored mesh/surface plot like this one (from matlab). http://www.mathworks.com/access/helpdesk/help/techdoc/visualize/cbar.gif The key features I am looking for is surfaced with grid and color, but not the terrain-like gradient. but I didn't come even close to it after browsing through rgl help file. have anyone drawn something like this

Hi, My problem maybe a little bit complicated, so forgive me if the following words are too much. #date set a0<-matrix(c(1.1,1.3,1.1,1.3,1.3, 2.0,1.8,2.0,1.8,1.8, "12/01/2008","05/20/2007","12/06/2008","05/10/2007","05/06/2007", "N","N","A","C","A", 1,2,3,4,5),ncol=5,byrow=FALSE)

Dear R Users, I have some data that is very similar in form to a 3D image - ie univariate data on a regular 3D grid. I keep this as a 3D numeric array in R with attributes describing the sampling points along the 3 dimensions. I would like to interpolate this onto a new regular 3D grid that I specify (eg by supplying 3 vectors corresponding to the new grid locations on each of the 3

Hi, for those with experience of Gruff module: suppose I want to send image from server straight to the browser (as example on gruff web site): send_data(g.to_blob, :disposition => ''inline'', :type => ''image/png'', :filename => "gruff.png") the server seems sending this binary data ok, but I am having

hi, There are two types of plotting I miss dearly in Matlab, can anyone enlighten me how to do similar stuff in R? - multiple figures with individual windows (not multiple figures in same window)? - draw something, hold on the drawing, wait for a key action, then overlay on top? Not sure if this makes sense, just want to check if there are developed techniques for them. Thanks Oliver

hi, all I have two questions on using R console effectively (this is on Mac, not sure if it applies to win platform): First, I'd like to make the console font bigger, the default is too small for my screen. There is a "Show Fonts" from Format menu where you can adjust it, but it seems only for current session. Next time I start R, I have to redo everything. My question is, is there

Hello. I am probably wrong... I am wondering if it could have a mistake in the code of the ansari.test function. For me, it seems that the function do not recover the p value at the correct side of the normal law N(0, 1) when it use the normal approximation (presence of ties) in a one tailed test. Exemple : quanti<-c(197, 205, 228, 234, 237, 195, 233, 226, 244, 227, 259, 185, 198, 253, 207,

I apologize in advance for the simplicity of this question. I use R 2-3 times a year, and I seem to forget more in the intervening months than I learn during my days of panicked reading.... I HAVE tried looking at the help resources; I'm just not very good at understanding them. I have a dataframe with 18 observations of 5 different things, and a second dataframe with and estimate for those

Dear All, I have conducted an experiment in order to examine predation pressure in the surroundings of potential wildlife road-crossing structures. I have documented predation occurrence (binary?) in these structures and calculated several possible explanatory variables describing the spatial heterogeneity in several scales. At the landscape scale I have calculated the percentage of different

Oliver gracias por le pista! Es un poco mas complicado, el código tiene varios pasos incluidos calculo de nuevas variables con los betas del glm y otras vueltas. Necesitaría una sentencia que tome cada lote haga los cálculos por separado y luego los une en el dataframe de salida El 30 de mayo de 2016, 10:02, Olivier Nuñez <onunez en unex.es> escribió: > Mira lapply .... > > Si L=

Hi, folks, Here are the codes: ############## y=1:10 x=c(1:9,1) lin=lm(log(y)~x) ### log(y) is following Normal distribution x=5:14 prediction=predict(lin,newdata=x) ##prediction=predict(lin) ############### 1. The codes do not work, and give the error message: Error in eval(predvars, data, env) : numeric 'envir' arg not of length one. But if I use the code after the pound sign, it

Full_Name: Martha Nason Version: 2.0.1 OS: Windows XP Submission from: (NULL) (137.187.154.154) I am running simulations using fisher's test on 2 x c tables and a very small p.value from fisher's test (<2.2e-16) is returned as a negative number. Code follows. > set.seed(0) > nreps.outer <-7 > pvalue.fisher <- rep(NA,nreps.outer) > > population1 <- c(

Carlos, capaz no me explique bien, va de nuevo... Tengo un dataFrame con varias variables que describen Lotes (127), he creado un código que calcula nuevas variables, re codifica otras y ordenas otras tantas. Es muy laborioso correr ese código 127 veces por lo cual quería hacer un sentencia (del tipo if() o repeat()), para obtener al final todos los lotes procesados. Saludos y gracias por tan

jep thats also configured. OLIVER WERNER System-Administrator > Am 10.01.2017 um 13:41 schrieb Vinicius Bones Silva via samba <samba at lists.samba.org>: > > check your /etc/nsswitch.conf and confirm that passwd and group lines have the winbind keyword > > passwd: files winbind > group: files winbind > > > > Em 10/01/2017 10:29, Oliver Werner via samba

Hi all, I am a grad student at Carnegie Mellon University. I had my course work in advanced storage systems in previous semester, and I am interested to work on Lustre. I prefer to take up a project that could be completed in a duration of a month or two. Since I am a novice w.r.t. my familiarity with Lustre code base, I seek your opinion to choose a project from the list: