similar to: Extracting the name of an object

Hi, How do I use the string content of a string variable to reference a data frame of the same name? I want to do the typical tasks of 1) building a name with a string variable and using the string variable to create a data frame (or any object) whose name is the string value of the variable and 2) pass on a string to a function as a parameter, and then use that string to refer to an existing

Hello everyone, I am trying to prune a data frame for partial least squares analysis. I need to delete an entire row if one cell in the row contains a NA. Presently, I am running a loop that is supposed to extract the rows that are full of numbers into a second data frame and skips the rows that contain a single NA value. I want to know if there is a simple way to determine if a row

Hello everyone, I have a couple of fairly simple questions (I hope) the answers to which I cannot find through the documentation at the moment. 1. I would like to delete the a row from a matrix if a certain elimination criterion is met. I am familiar with x <- x[-7,] (to remove row 7, for example). Are there any other means of removing an entire row? 2. Is there a single command that

Hi, I have managed to format my data into a single datframe consisting of two AsIs response and predictor dataframes in order to supply the plsr command of the pls package for principal components analysis. When I execute the command, however, I get this error: > fiber1 <- plsr(respmat ~ predmat, ncomp=1, data=inputmat,validation="LOO") Error in model.frame.default(formula =

Hello, Is possible to place a label on a multipanel figure outside the boundaries of any single one of the existing graphs in a panel? Specifically, I have a function that creates a panel with quartz() and then fills it with 6 graphs consisting of exactly the same plot for 6 different groups. I would like to add one title for the entire figure at the top of the figure, but I cannot figure out

Hi, I have written boxplot commands of this form before, but I don''t quite understand why the function call is reporting a syntax error in this instance. All parameters passed to the function are strings. Thanks in advance. Payam > simplevar <- function(wframe,column1,column2) { + tframe <- get(wframe) + x1 <- which(names(wframe)==column1) + x2 <-

I have encountered a more fundamental problem in my data set. I''m using read.csv, and all the data are imported as character. How do I do a string comparison in a line like this: M10[ !sapply(1:10, function(x)666 %in% M10[x,]), ] Alternately, how do I change the class type on a column in a data frame from character to numeric? Thank you very much. Payam [[alternative HTML version

Hello all, It seems that the GeneMeta passage returns NA in the respective row if any gene in the data sets to be synthesised are missing. Do you know of a way to overcome this problem? I tried using the 'impute' package to fill-in the missing values, but R crashes if 'impute' and 'GeneMeta' packages are used together. I have asked a separate question for that. Thanks

Hello, I'm having trouble discovering what's going wrong with my use of natural joins via sqldf. Following the instructions under 4i at http://code.google.com/p/sqldf/, which discusses creating indices to speed joins, I have been only unreliably able to get natural joins to work. For example, > Tid <- c('AES 01-01-02 10:58:00', 'AES 01-01-02 11:53:00', 'AES

there is my code,  expect return value  is a data frame but R say it is list: SEXP Julia_R_MD_NA_DataFrame(jl_value_t* Var) {  SEXP ans,names,rownames;  char evalcmd[4096];  int i;  const char* dfname="DataFrameName0tmp";  jl_set_global(jl_main_module, jl_symbol(dfname), (jl_value_t*)Var);  //Get Frame cols   sprintf(evalcmd,"size(%s,2)",dfname);  jl_value_t*

Hello everybody, it's a few minutes that i've subscribed in your mailing list. nice to meat all of you. I have samba on redhat 8 as a file server for a couple of "win98" & "winXP"'s.It work's for my XP OS's but I don't know how to join the "win98" 's in. please help me thanks payam.

Hi, I would like to extract the last row of each group in a data frame. The data frame is as follows Name Value A 1 A 2 A 3 B 4 B 8 C 2 D 3 I would like to get a data frame as Name Value A 3 B 8 C 2 D 3 Thank you for your suggestions in advance Jeff

A time series text with a title that seems designed to hide its wide scope is: Forecasting with Exponential Smoothing The State Space Approach Hyndman, R.J., Koehler, A.B., Ord, J.K., Snyder, R.D. Springer 2009. This book is actually an excellent overview of time series theory, ARIMA as well as state space. It is of course, in part, a manual for the forecast and other packages in what has been

Hi, I'm looking for a function which returns the name of the argument object as a string: >vect <- 1:3 >function(vect) "vect" I've looked at 'name', 'names', 'objects', none seem to do exactly what I want. ls/objects comes close, but I can't figure out how to force it to give me only one object name. daver

Hello all, I have a data frame dataa: newdate newstate newid newbalance newaccounts 1 31DEC2001 AR 1 1170 61 2 31DEC2001 VA 2 4565 54 3 31DEC2001 WA 3 2726 35 4 31DEC2001 AR 3 2700 35 The following gives me the balance of state AR:

Hello all, I have the following problem: 1) A list was defined as 'a' a <- list("var1"=c(100:1), "var2"=c(1:100), "var3"=rnorm(100)) 2) a function 'foo' was defined that extracts the variable name assigned to x using the deparse(substitute()) functionality. This name will then be used within the function to generate specific output files, etc.

(R 1.9.1; Windows 2000;) I'm just comparing ease of use, speed, etc for methods of transferring data frames in the Excel, MySQL, R triangle. It turns out that going from Excel to R (when doing this carefully). Using the clipboard is actually quite fast and efficient (2 seconds for transferring 120 000 cells on a common desktop computer as compared to much longer for going the RODBC route,

I'm trying to rename the columns in a list of data.frames using the following... for(i in 1:length(filenames)) { assign(names(get(filenames[i])), c("name", "infood", "time") ) } R returns no errors, but the names are unchanged in the data.frames. The original names were things like > names(get(filenames[2])) [1] "Tc45w4.V1" "Tc45w4.V2"

Hi all, is there a way to extract the name of a function, i.e. do the reverse of match.fun applied to a character string? I would like to print out the name of a function supplied to another function as an argument. For example: myFunc = function(x) { x+1 } applyFunc = function(fnc, x) { fnc = match.fun(fnc) fnc(x) } Is there a way to obtain "myFunc" from the argument fnc in

All, I have a workspace containing only data frame objects. I would like to loop though each one and clean-up text columns in them. How can I have R loop through the list? I have tried to find an answer in R help but the closest solution I can find is to make a static list of data frames, as illustrated in this recent post: ---------begin post On Tuesday 19 February 2008 (19:51:15), TLowe wrote: