similar to: Combining elements of vectors

Dear list, Is there any functionality in R that would allow me to parse config files? I have trie ??config and apropos('config') without succes, and also search the R package site. Mvh. Marie [[alternative HTML version deleted]]

Dear useRs, I have a collection of source file and some of these call others. The files are distribute among a number of directories, and to know how to call some other file they need to know what file is currently executed. As example, I have a file 'search.R' located in directory 'bin' which needs to access the file 'terms.conf' located in the directory 'conf',

Dear Brian, I dont understand what you mean. The thread was about the as.Date which you suggested to be used instead of the as.date. Following your advice I tried the as.Date and have questions about the observed behaviour, which was surprising to me. Is this what you call hijacking? Do you mean I ought start a new thread instead? I thought my question were relevant to the threads'

Dear R, I have find a website where they report problem with ARIMA models in R. I run the examples there and they give result as shown on the website. Does this mean that nothing has corrected in R? Maybe you not have seen the page, but the author said he contacted you. Here is the URL: http://www.stat.pitt.edu/stoffer/tsa2/Rissues.htm I like to know your opinion. Mvh. Marie [[alternative

Dear R, I have find a website where they report problem with ARIMA models in R. I run the examples there and they give result as shown on the website. Does this mean that nothing has corrected in R? Maybe you not have seen the page, but the author said he contacted you. Here is the URL: http://www.stat.pitt.edu/stoffer/tsa2/Rissues.htm I like to know your opinion. Mvh. Marie [[alternative

Hi, This has been asked before but not sufficiently answered from what I could find. How do you create combinations with repetitions (multisets) in R? If I have > set <- array(1:3) And I want to choose all combinations of picking 2 numbers, I want to get a print out like [,1] [,2] [1,] 1 1 [2,] 1 2 [3,] 1 3 [4,] 2 2 [5,] 2 3 [6,] 3 3 subsets(set,

Dear List, I try to develop code where plotting functions are embeded in my own functions. The following is simplified example: > test <- function() { > data <- data.frame(x=rep(1:2, each=50), y=rnorm(100)) > library(lattice) > attach(data) > xyplot(y~x) > detach() >} >test() As far as I understand R, when test is called this should create one local

R-2.9.1, Windows7 Dear list, I have a question to you that seems very simple to me, but I just can't figure it out. I have a dataframe called "ratings" which contains the following variables: evalR1, evalR2, evalR3, evalR4, scoreR1, scoreR2, scoreR3, scoreR4, opinionR1, opinionR2, opinionR3, opinionR4. (there are more variables, but this gives an idea of the data structure). What

Dear R-users, I am trying to use the grid.text and expression functions to display several character strings and plotmath text on a viewport. Some strings can include a variable portion (PI.limits in the following example), which I thought could be implemented by combining the bquote and the expression functions. Unfortunately, my expressions do not seem to be evaluated. I would greatly

Hello all, I am trying to create a matrix of 1s and -1s without any repetitions for a specified number of columns. e.g. 1s and -1s for 3 columns can be done uniquely in 2^3 ways. -1 -1 -1 -1 -1 1 -1 1 -1 -1 1 1 1 -1 -1 1 -1 1 1 1 -1 1 1 1 and for 4 columns in 2^4 ways and so on. I finally used the function combn([0 1],3) that I found at the following link

Hi, I've started my own (first) package, part of which consists in listing common physical constants (Planck's constant, the speed of light in vacuum, etc). I'm wondering what would be a good way of dealing with pairs of value/unit. > constants <- list( cel = 2.99792458e8 , #m/s > Z0 = 376.730313461, #ohm > eps0 = 8.854187817e-12,#F/m > mu0 = 4*pi*1e-7,#N/A^2

Hi List, I'm hoping to get opinions for enhancing the efficiency of the following code designed to take a vector of probabilities (outcomes) and calculate a union of the probability space. As part of the union calculation, combn() must be used, which returns a matrix, and the parallelized version of lapply() provided in the multicore package requires a list. I've found that

Dear all, I want to apply a function to list elements, two by two. I hoped that combn would help me out, but I can't get it to work. A nested for-loop works, but seems highly inefficient when you have large lists. Is there a more efficient way of approaching this? # Make some toy data data(iris) test <- vector("list",3) for (i in 1:3){ x <- levels(iris$Species)[i] tmp

Dear list, I'm quite surprised by this, unit(1:5,"char")[-c(1:2)] #4char 3char # what's going on?? while I expected something like, c(1:5)[-c(1:2)] # 3 4 5 Note that, unit(1:5,"char")[c(1:2)] # 1char 2char # fine ?unit warns about unit.c for concatenating, but also says, It is possible to subset unit objects in the normal way (e.g.,

My dear R-helpers: I am a novice in R and have the following text string manipulation question. Is there a function that performs the job described below? Say, wanted_output <- c("ab", "cd", "ef") #the function_wanted can generate c("ab", "cd", "ef") using ab cd ef as the single input argument wanted_output <- function_wanted(ab

Hello! I've a problem with the combn function and a set of vector. I would like to make a simple combination where, instead of scalars, i would like to combine vector, in order to form matrixes. In other words, i have nineteen 6-items vectors (for example coef1-coef19), that i would like to combine in n!/k!(n-k)! 6x6 matrixes. I tried with a code like this mma <-

Hello, I am plotting two distributions and want to draw a vertical line at the critical point 149. How can I stop it from going further up than the norm(140,15) curve? x<-seq(75,225,0.1) plot(x,dnorm(x,mean=140, sd=15), type='l', col='navy') abline(v = 149, col = "black") curve(dnorm(x,mean=150, sd=15),from=75, to=225, col='orange', add=TRUE) Thank you.

I'm able to do this as follows, but am wondering if anyone knows a simpler way which still avoids explicit loops? > (mystring <- letters[1:5]) [1] "a" "b" "c" "d" "e" > unlist(sapply(mystring[-length(mystring)], + function(x) paste(x,mystring[(grep(x,mystring)+1):length(mystring)],sep=""))) a1 a2 a3

Hello, I have a sequence of numbers: seq(1:50) and I would like to have all the possible combinations with this numbers without repeating any combination: 11, 12, 13, ... ,22,23,24,... How can I do it? Best, Dani -- Daniel Valverde Saub? Grup de Biologia Molecular de Llevats Facultat de Veterin?ria de la Universitat Aut?noma de Barcelona Edifici V, Campus UAB 08193 Cerdanyola del Vall?s-

Dear R useRs, i try to integrate the following function for many values "integrand" <- function(z) { return(z * z) } i do this with a for-loop for(i in 2:4) { z <- integrate(integrand, i-1, i)$value cat("z", z, "\n") } to speed up the computation for many values i tried vectors in integrate to do this. vec1<-1:3 vec2<-2:4